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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 12 : MultiStage Amplifiers"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 12.1a, Page No 433"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"Ry=1 #in K\n",
"Rg=1 #in M\n",
"Ri=1 #in K\n",
"hOE=1.0/40 #in K^-1\n",
"\n",
"#fL=1/(2*%pi*(ro+ri)*Cb)<=10\n",
"#Since ri=1M , ro<Ry=1K , then ro+ri=1M\n",
"\n",
"#Calculations\n",
"Cb=1/(2*math.pi*1*10)\n",
"\n",
"#Results\n",
"print(\"Minimum Value of coupling Capacitance for given FET = %.3f \" %Cb)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Minimum Value of coupling Capacitance for given FET = 0.016 \n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 12.1b, Page No 433"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#initialisation of variables\n",
"Ry=1#in K\n",
"Rg=1#in M\n",
"Ri=1#in K\n",
"hOE=1.0/40 #in K^-1\n",
"\n",
"#fL=1/(2*math.pi*(ro+ri)*Cb)<=10\n",
"\n",
"#Ro>1/hOE=40K ro=Rc=1K. Rb>Ri=1K then ri=1K\n",
"\n",
"#Calculations\n",
"ro=1000.0 #in ohm\n",
"ri=1000.0 #in ohm\n",
"Cb=1.0/(2*math.pi*10*(ro+ri))\n",
"\n",
"#Results\n",
"print(\"Coupling Capacitance for given transistor = %.2f v \" %(Cb*(10**6)))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Coupling Capacitance for given transistor = 7.96 v \n"
]
}
],
"prompt_number": 2
}
],
"metadata": {}
}
]
}
|