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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 2 : Thermometry"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.1 pageno : 29"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"li = 1.23;\t\t\t#length of melting ice in mm\n",
"lf = 18.56;\t\t\t#length of melting ice reading in pressure of 74.24cm of mercury in mm\n",
"l = 10.75;\t\t\t#length of melting ice at which temperature to be calculated\n",
"mp = 0;\t\t\t#melting point in deg.C\n",
"T = 50;\t\t\t#temperature of melting ice at which length to be calculated in deg.C\n",
"\n",
"# Calculations\n",
"sp = 100-(76-74.24)/(2.7);\t\t\t#76cm of mercury steam point is 100 deg.C so at 74.24cm of mercury the steam point in deg.C\n",
"t = (l-li)*(sp-mp)/(lf-li);\t\t\t#temperature at 10.75mm of melting ice in deg.C\n",
"lt = ((T*(lf-li))/(sp-mp))+li;\t\t\t#length of ice at 50 deg.C\n",
"\n",
"# Result\n",
"print 'the temperature of melting ice at 10.75mm of hg is %3.2f deg.C \\\n",
" \\nthe length of ice corresponding to 50 deg.C is %3.2f mm of mercury'%(t,lt)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"the temperature of melting ice at 10.75mm of hg is 54.58 deg.C \n",
"the length of ice corresponding to 50 deg.C is 9.95 mm of mercury\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.2 pageno : 30"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"p1 = 23.5;\t\t\t#pressure when immersed in liquid air in cm\n",
"p2 = 75.;\t\t\t#pressure when immersed in ice in cm\n",
"p3 = 102.4;\t\t\t#pressure when immersed in steam in cm\n",
"T = 100.;\t\t\t#boiling point of temperature in deg.C\n",
"\n",
"# Calculations\n",
"t = (p1-p2)*T/(p3-p2);\t\t\t#temperature of the liquid air in deg.C\n",
"\n",
"# Result\n",
"print 'the temperature of liquid of air is %3.2f deg.C'%(t)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"the temperature of liquid of air is -187.96 deg.C\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.3 pageno : 30"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"t1 = 283.;\t\t\t#temperature of bulb when pressure is h-2cm of hg in k\n",
"t2 = 546.;\t\t\t#temperature of bulb when pressure is h-22cm of hg in k\n",
"h1 = 2.;\t\t\t#differnce of mercury level at 283k in cm\n",
"h2 = 22.;\t\t\t#differnce of mercury level at 546k in cm\n",
"\n",
"# Calculations\n",
"h = ((h2*t1)+(h1*t2))/(t2-t1);\t\t\t#height of the barometer in cm\n",
"\n",
"# Result\n",
"print 'height of the barometer is %3.2f cm'%(h)\n",
"\n",
"print \"Note : Answer in book is wrong. Please calculate manually and check.\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"height of the barometer is 27.83 cm\n",
"Note : Answer in book is wrong. Please calculate manually and check.\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"\n",
"Example 2.4 pageno : 30"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"p0 = 76.;\t\t\t#pressure at 0 deg.C in cm of hg\n",
"p1 = 228.;\t\t\t#pressure (76+152) at T deg.C in cm of hg\n",
"t0 = 273.;\t\t\t#temperature of bulb in K\n",
"\n",
"# Calculations\n",
"T = p1*t0/p0;\t\t\t#temperature at 228 cm of hg pressure in K\n",
"\n",
"# Result\n",
"print 'the temperature of bulb is %3.2f K'%(T)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"the temperature of bulb is 819.00 K\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.5 page no : 30"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"t1 = 0;\t\t\t #temperature in deg.C\n",
"t2 = 100;\t\t\t#temperature in deg.C\n",
"t3 = 208;\t\t\t#temperature in deg.C\n",
"r1 = 3.5;\t\t\t#resistance in ohms\n",
"r2 = 5.2;\t\t\t#resistance in ohms\n",
"r3 = 6.9;\t\t\t#resistance in ohms\n",
"r4 = 9.4;\t\t\t#resistance in ohms\n",
"\n",
"# Calculations\n",
"tpt = (r3-r1)*100/(r2-r1);\t\t\t#temperature in deg.C\n",
"d = round((t3-tpt)/(2.08*1.08),2);\t\t\t#deflection\n",
"tp = round((r4-r1)*100/(r2-r1),2);\t\t\t#temperature in deg.C\n",
"t6 = (3.5*(((tp/100)**2)-tp/100))+tp;\t\t\t#temperature in deg.C\n",
"t7 = (3.5*(((t6/100)**2)-t6/100))+tp;\t\t\t#temperature in deg.C\n",
"t8 = (3.5*(((t7/100)**2)-t7/100))+tp;\t\t\t#temperature in deg.C\n",
"t9 = (3.5*(((t8/100)**2)-t8/100))+tp;\t\t\t#temperature in deg.C\n",
"\n",
"#Result\n",
"print 'the temperature of the bath is %3.2f deg.C'%(t9)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"the temperature of the bath is 385.50 deg.C\n"
]
}
],
"prompt_number": 13
}
],
"metadata": {}
}
]
}
|
