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{
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{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 23 : Alternating Current Circuits"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 23_1 Page No. 715"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Total Impedence Zt = 38.18 Ohms\n",
"Current I = 0.00 Ampers\n",
"i.e 1.31 mAmps\n",
"Theta z = 45.00 Degree\n"
]
}
],
"source": [
"from math import sqrt,atan,pi\n",
"# A 27-Ohms R is in series with 54 Ohms\u0004 of Xl and 27 Ohms\u0004 of Xc. The applied voltage Vt is 50 mV. Calculate ZT, I, and Theta z.\n",
"\n",
"# Given data\n",
"\n",
"R = 27.# # Resistance=27 Ohms\n",
"Xl = 54.# # Inductive reactance=54 Ohms\n",
"Vt = 50.*10**-3# # Applied voltage=100 Volts\n",
"Xc = 27.# # Capacitive reactance=27 Ohms\n",
"\n",
"nXl = Xl-Xc# # Net Inductive reactance\n",
"R1 = R*R#\n",
"nXl1 = nXl*nXl#\n",
"\n",
"Zt = sqrt(R1+nXl1)#\n",
"print 'Total Impedence Zt = %0.2f Ohms'%Zt\n",
"\n",
"I = (Vt/Zt)#\n",
"print 'Current I = %0.2f Ampers'%I\n",
"print 'i.e 1.31 mAmps'\n",
"\n",
"Oz = atan(Xc/R)*180/pi\n",
"print 'Theta z = %0.2f Degree'%Oz"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 23_2 Page No. 717"
]
},
{
"cell_type": "code",
"execution_count": 4,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Total Current It = 0.00 Amps\n",
"i.e 2.55 mAmps\n",
"The Equivqlent Impedence Zeq = 19.64 Ohms\n",
"approx 19.61 Ohms\n",
"Theta z = -45.00 Degree\n"
]
}
],
"source": [
"from math import atan,pi,sqrt\n",
"# The following branch currents are supplied from a 50-mV source: Ir=1.8 mA# Il=2.8 mA# Ic=1 mA. Calculate It, Zeq, and Theta I.\n",
"\n",
"# Given data\n",
"\n",
"Va = 50.*10**-3# # Applied voltage=50m Volts\n",
"Ir = 1.8*10**-3# # Ir=1.8 mAmps\n",
"Il = 2.8*10**-3# # Ir=2.8 mAmps\n",
"Ic = 1.*10**-3# # Ic=1 mAmps\n",
"\n",
"nI = Il-Ic# # net current\n",
"Ir1 = Ir*Ir#\n",
"nI1 = nI*nI#\n",
"\n",
"It = sqrt(Ir1+nI1)#\n",
"print 'The Total Current It = %0.2f Amps'%It\n",
"print 'i.e 2.55 mAmps'\n",
"\n",
"Zeq = Va/It#\n",
"print 'The Equivqlent Impedence Zeq = %0.2f Ohms'%Zeq\n",
"print 'approx 19.61 Ohms'\n",
"\n",
"Oz = atan(-(nI/Ir))*180/pi\n",
"print 'Theta z = %0.2f Degree'%Oz"
]
}
],
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