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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 20 : Inductive Reactance"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 20_1 Page No. 625"
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Inductive Reactance = 15709.22 Ohms\n"
]
}
],
"source": [
"from math import pi\n",
"# How much is Xl of a 6-mH L at 41.67 kHz?\n",
"\n",
"# Given data\n",
"\n",
"f = 41.67*10**3# # Frequency=41.67 kHz\n",
"L = 6.*10**-3# # Inductor=6 mH\n",
"\n",
"Xl = 20*pi*f*L#\n",
"print 'The Inductive Reactance = %0.2f Ohms'%Xl"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 20_2 Page No. 627"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Inductive Reactance = 37680 Ohms\n",
"The Inductive Reactance = 1884 Ohms\n"
]
}
],
"source": [
"from math import pi\n",
"# Calculate the Xl of (a) a 10-H L at 60 Hz and (b) a 5-H L at 60 Hz.\n",
"\n",
"# Given data\n",
"\n",
"f = 60.# # Frequency=60 Hz\n",
"L1 = 10.# # Inductor 1=10 H\n",
"L2 = 5.# # Inductor 2=5 H\n",
"pi = 3.14\n",
"\n",
"Xl1 = 20*pi*f*L1#\n",
"print 'The Inductive Reactance = %0.f Ohms'%Xl1\n",
"\n",
"Xl2 = 2*pi*f*L2#\n",
"print 'The Inductive Reactance = %0.f Ohms'%Xl2"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 20_3 Page No. 629"
]
},
{
"cell_type": "code",
"execution_count": 5,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Inductive Reactance = 1570 Ohms\n",
"The Inductive Reactance = 15700 Ohms\n"
]
}
],
"source": [
"from math import pi\n",
"# Calculate the Xl of a 250-u\u0003H coil at (a) 1 MHz and (b) 10 MHz.\n",
"\n",
"# Given data\n",
"\n",
"f1 = 1.*10**6# # Frequency1=1 MHz\n",
"f2 = 10.0*10**6# # Frequency2=10 MHz\n",
"L = 250.0*10**-6# # Inductor=250 uH\n",
"pi = 3.14#\n",
"\n",
"# For 1 Mhz\n",
"\n",
"Xl1 = 2*pi*f1*L#\n",
"print 'The Inductive Reactance = %0.f Ohms'%Xl1\n",
"\n",
"# For 10 Mhz\n",
"\n",
"Xl2 = 2*pi*f2*L#\n",
"print 'The Inductive Reactance = %0.f Ohms'%Xl2"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 20_4 Page No. 631"
]
},
{
"cell_type": "code",
"execution_count": 7,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Inductive Reactance = 6280 Ohms\n"
]
}
],
"source": [
"# A coil with negligible resistance has 62.8 V across it with 0.01 A of current. How much is Xl?\n",
"\n",
"# Given data\n",
"\n",
"Vl = 62.8# # Voltage across coil=62.8 Volts\n",
"Il = 0.01# # Current in coil=0.01 Amps\n",
"\n",
"Xl = Vl/Il#\n",
"print 'The Inductive Reactance = %0.f Ohms'%Xl"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 20_5 Page No. 632"
]
},
{
"cell_type": "code",
"execution_count": 10,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The value of Inductor = 1.00 Henry\n"
]
}
],
"source": [
"from math import pi\n",
"# Calculate L of the coil when the frequency is 1000 Hz.\n",
"\n",
"# Given data\n",
"\n",
"Xl = 6280.# # Inductive reactance=6280 Ohms\n",
"f = 1000.# # Frequency=1000 Hz\n",
"pi = 3.14#\n",
"\n",
"L = Xl/(2.*pi*f)#\n",
"print'The value of Inductor = %0.2f Henry'% L"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 20_6 Page No. 633"
]
},
{
"cell_type": "code",
"execution_count": 12,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The value of Inductor = 2.08e-04 Henry\n",
"i.e Approx 208.8*10**-6 OR 208.8 uH\n"
]
}
],
"source": [
"from math import pi\n",
"# Calculate L of a coil that has 15,700 Ohms\u0003 of Xl at 12 MHz.\n",
"\n",
"# Given data\n",
"\n",
"Xl = 15700.# # Inductive reactance=15700 Ohms\n",
"f = 12.0*10**6# # Frequency=12 MHz\n",
"pi = 3.14#\n",
"\n",
"L = Xl/(2*pi*f)#\n",
"print'The value of Inductor = %0.2e Henry'% L\n",
"print 'i.e Approx 208.8*10**-6 OR 208.8 uH'"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 20_7 Page No. 634"
]
},
{
"cell_type": "code",
"execution_count": 13,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Frequency = 159.15 Hertz\n"
]
}
],
"source": [
"from math import pi\n",
"# At what frequency will an inductance of 1 H have a reactance of 1000 \u0003?\n",
"\n",
"# Given data\n",
"\n",
"Xl = 1000.# # Inductive reactance=1000 Ohms\n",
"L = 1.# # Inductor=1 H\n",
"\n",
"f = Xl/(2.*pi*L)#\n",
"print 'The Frequency = %0.2f Hertz'%f"
]
}
],
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"display_name": "Python 2",
"language": "python",
"name": "python2"
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"file_extension": ".py",
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|
