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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 16 : Capacitance"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 16_1 Page No. 492"
]
},
{
"cell_type": "code",
"execution_count": 4,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Charge Stored = 1.00e-04 Columb\n",
"i.e 100*10**-6 Columbs\n"
]
}
],
"source": [
"# How much charge is stored in a 2 uF capacitor connected across a 50-V supply?\n",
"\n",
"# Given data\n",
"\n",
"V = 50# # Voltage=50 Volts\n",
"C = 2*10**-6# # Capacitor=2 uFarad\n",
"\n",
"Q = C*V#\n",
"print 'The Charge Stored = %0.2e Coulomb'%Q\n",
"print 'i.e 100*10**-6 Coulombs'"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 16_2 Page No. 492"
]
},
{
"cell_type": "code",
"execution_count": 5,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Charge Stored = 2.00e-03 Columb\n",
"i.e 2000*10**-6 Columbs\n"
]
}
],
"source": [
"# How much charge is stored in a 40 uF capacitor connected across a 50-V supply?\n",
"\n",
"# Given data\n",
"\n",
"V = 50# # Voltage=50 Volts\n",
"C = 40*10**-6# # Capacitor=2 uFarad\n",
"\n",
"Q = C*V#\n",
"print 'The Charge Stored = %0.2e Coulomb'%Q\n",
"print 'i.e 2000*10**-6 Coulombs'"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 16_3 Page No. 493"
]
},
{
"cell_type": "code",
"execution_count": 6,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Charge Stored = 4.00e-05 Columb\n",
"i.e 40*10**-6 Columbs OR 40 uColumb\n"
]
}
],
"source": [
"# A constant current of 2 uA charges a capacitor for 20 s. How much charge is stored? Remember I=Q/t or Q=I*t.\n",
"\n",
"# Given data\n",
"\n",
"I = 2*10**-6# # Current=2 uAmps\n",
"t = 20# # Time=20 Sec\n",
"\n",
"Q = I*t\n",
"print 'The Charge Stored = %0.2e Coulomb'%Q\n",
"print 'i.e 40*10**-6 Coulombs OR 40 uCoulomb'"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 16_4 Page No. 494"
]
},
{
"cell_type": "code",
"execution_count": 7,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Capacitance = 2.00e-06 Farad\n",
"i.e 2 uF\n"
]
}
],
"source": [
"# The voltage across the charged capacitor is 20 V. Calculate C.\n",
"\n",
"#Given data\n",
"\n",
"V = 20# # Voltage=20 Volts\n",
"Q = 40*10**-6# # Charge=40 uCoulomb\n",
"\n",
"C = Q/V\n",
"print 'The Capacitance = %0.2e Farad'%C\n",
"print 'i.e 2 uF'"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 16_5 Page No. 495"
]
},
{
"cell_type": "code",
"execution_count": 8,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Voltage across Capacitor = 500.00 Volts\n"
]
}
],
"source": [
"# A constant current of 5 mA charges a 10 uF capacitor for 1 s. How much is the voltage across the capacitor?\n",
"\n",
"# Given data\n",
"\n",
"I = 5*10**-3# # Current=5 mAmps\n",
"t = 1# # Time=1 Sec\n",
"C = 10*10**-6# # Cap=10 uFarad\n",
"\n",
"Q = I*t#\n",
"\n",
"V = Q/C#\n",
"print 'The Voltage across Capacitor = %0.2f Volts'%V"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 16_6 Page No. 496"
]
},
{
"cell_type": "code",
"execution_count": 9,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Capacitance = 1.77e-09 Farad\n",
"i.e 1700*10**-12 F OR 1770 pF\n"
]
}
],
"source": [
"# Calculate C for two plates, each with an area 2 sqm, separated by 1 cm with a dielectric of air.\n",
"\n",
"# Given data\n",
"\n",
"c = 8.85*10**-12# # Constant=8.85 p\n",
"A = 2# # Area=2 sqm\n",
"d = 1*10**-2# # Distance=1 cm\n",
"K = 1 # Permeability=1\n",
"\n",
"C = K*c*(A/d)#\n",
"print 'The Capacitance = %0.2e Farad'%C\n",
"print 'i.e 1700*10**-12 F OR 1770 pF'"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 16_11 Page No. 514"
]
},
{
"cell_type": "code",
"execution_count": 10,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Energy Stored = 0.23 Joules\n"
]
}
],
"source": [
"# The high-voltage circuit for a color picture tube can have 30 kV across 500 pF of C . Calculate the stored energy.\n",
"\n",
"# Given data\n",
"\n",
"V = 30*10**3# # Voltage=30 kVolts\n",
"C = 500*10**-12# # Cap=500 pFarad\n",
"\n",
"E = 0.5*C*V*V\n",
"print 'The Energy Stored = %0.2f Joules'%E"
]
}
],
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|
