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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 1 : Electricity"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 1_5 Page No. 24"
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Output Voltage of a Battery = 7.20 Volts\n"
]
}
],
"source": [
"# What is the output voltage of a battery that expends 3.6 J of energy in moving 0.5C of charge?\n",
"\n",
"# Given data\n",
"\n",
"W = 3.6# # Work=3.6 Jouls\n",
"Q = 0.5# # Charge=0.5 Columb\n",
"\n",
"V = W/Q#\n",
"print 'The Output Voltage of a Battery = %0.2f Volts'%V"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 1_6 Page No. 24"
]
},
{
"cell_type": "code",
"execution_count": 2,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Intensity of Charge Flow = 12.00 Amps\n"
]
}
],
"source": [
"#The charge of 12 C moves past a given point every second. How much is the intensity of charge flow?\n",
"\n",
"# Given data\n",
"\n",
"Q = 12# # Charge=12 Columb\n",
"T = 1# # Time=1 Sec i.e every second\n",
"\n",
"I = Q/T#\n",
"print 'The Intensity of Charge Flow = %0.2f Amps'%I"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 1_7 Page No. 24"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Current = 5.00 Amps\n"
]
}
],
"source": [
"# The charge of 5 C moves past a given point in 1 s. How much is the current?\n",
"\n",
"# Given data\n",
"\n",
"Q = 5# # Charge=5 Columb\n",
"T = 1# # Time=1 Sec\n",
"\n",
"I = Q/T#\n",
"print 'The Current = %0.2f Amps'%I"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 1_8 Page No. 25"
]
},
{
"cell_type": "code",
"execution_count": 5,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Resistance for Conductance value 0.05 S = 20.00 Ohms\n",
"The Resistance for Conductance value 0.1 S = 10.00 Ohms\n"
]
}
],
"source": [
"# Calculate the resistance for the following conductance values: (a) 0.05 S (b) 0.1 S\n",
"\n",
"# Given data\n",
"\n",
"G1 = 0.05# # G1=0.05 Siemins\n",
"G2 = 0.1# # G1=0.1 Siemins\n",
"\n",
"R1 = 1/G1#\n",
"print 'The Resistance for Conductance value 0.05 S = %0.2f Ohms'%R1\n",
"\n",
"R2 = 1/G2#\n",
"print 'The Resistance for Conductance value 0.1 S = %0.2f Ohms'%R2"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 1_9 Page No. 26"
]
},
{
"cell_type": "code",
"execution_count": 9,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Conductance for Resistance value 1 kohms = 1e-03 Siemens\n",
"OR 1 mS\n",
"The Conductance for Resistance value 5 kohms = 2e-04 Siemens\n",
"OR 200 uS\n"
]
}
],
"source": [
"#Calculate the conductance for the following resistance values: (a) 1 kOhms \b(b)5 kOhms\n",
"\n",
"# Given data\n",
"\n",
"R1 = 1.0*10**3# # R1=1k Ohms\n",
"R2 = 5.0*10**3# # R2=5k Ohms\n",
"\n",
"G1 = 1/R1#\n",
"print 'The Conductance for Resistance value 1 kohms = %0.e Siemens'%G1\n",
"print 'OR 1 mS'\n",
"\n",
"G2 = 1/R2#\n",
"print 'The Conductance for Resistance value 5 kohms = %0.e Siemens'%G2\n",
"print 'OR 200 uS'"
]
}
],
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"kernelspec": {
"display_name": "Python 2",
"language": "python",
"name": "python2"
},
"language_info": {
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"name": "ipython",
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"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
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|
