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{
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"name": "",
"signature": "sha256:efee43f3cff9fdca8c69d559c1c84e6f19cd4b3e6da3711c7567d0790f5b7290"
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Ch-11, Hydro-Thermal Co-Ordination"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"example 11.2 Page 234"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"l1=700 ;t1=14 ;l2=500; t2=10\n",
"ac=24 ;bc=0.02#variables of cost equation\n",
"aw=6 ;bw=0.0025 #variables of watere quantity equation\n",
"b22=0.0005 #loss coefficient\n",
"r2=2.5\n",
"from numpy import arange, mat\n",
"lam=arange(1,40,0.001)\n",
"gg=1; q=1\n",
"for lam in arange(25,4,0.0010):\n",
" a=[2*bc, 0, 0, r2*bw*2+2*b22*lam]\n",
" b=[lam-ac ,lam-aw*r2]\n",
" p=inv(a)*b\n",
" g=round(p(1)+p(2))\n",
" l=round(l1+b22*p(2)**2)\n",
" lq=round(l2+b22*p(2)**2)\n",
" if g>=l:\n",
" print \"\\nfor load condition %dMW \\n then, \\n \\t lamda %f \\t p1=%fMW \\n \\t p2=%fMW \\t pl=%fMW\"%(l1,lam,p[0],p[1],2*b22*p[1])\n",
" break\n",
" #end\n",
"#end\n",
"for lam in arange(25,40,0.001):\n",
" a=mat([[2*bc ,0],[0, r2*bw*2+2*b22*lam]])\n",
" b=([[lam-ac] ,[lam-aw*r2]])\n",
" pq=(a**-1)*b\n",
" \n",
" g=round(pq[0]+pq[1])\n",
" lq=round(l2+b22*pq[1]**2)\n",
"\n",
" if g>=lq:\n",
" print \"\\nfor load condition %dMW \\n then, \\n \\t lamda %f \\t p1=%fMW \\n \\t p2=%fMW \\t pl=%fMW\"%(l2,lam,pq[0],pq[1],2*b22*pq[1])\n",
" break\n",
" #end\n",
"#end\n",
"dwu=[(aw+bw*p)*p*t1+t2*(aw+bw*pq[1])*pq[1]]*3600\n",
"doc=[(ac+bc*p)*p*t1+(ac+bc*pq[0])*pq[0]*t2]\n",
"print \"\\ndaily water used %fm**3 \\ndaily operating cost of thermal plant Rs%f\"%(dwu[0],doc[0])\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"for load condition 500MW \n",
" then, \n",
" \t lamda 31.705000 \t p1=192.625000MW \n",
" \t p2=377.898428MW \t pl=0.377898MW\n",
"\n",
"daily water used 26664.961210m**3 \n",
"daily operating cost of thermal plant Rs55337.878125\n"
]
}
],
"prompt_number": 10
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"example 11.3 Page "
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from math import sqrt\n",
"#given \n",
"p=250#load\n",
"rt=14 #run time\n",
"t=24#total time\n",
"ac=5 ;bc=8; cc=0.05 #variables of cost equation\n",
"bw=30; cw=0.05 #variables of water per power\n",
"qw=500#quantity of water\n",
"lam=bc+cc*2*p #lambda\n",
"a=-qw*(10**6)/(3600*rt)\n",
"inn=sqrt(bw**2-4*cw*a)\n",
"phh1=(-bw+inn)/(2*cw)#solution of quadratic equation\n",
"phh2=(-bw-inn)/(2*cw)\n",
"if phh1>0 :\n",
" r=lam/(bw+cw*phh1) \n",
" print \" hydro plant power is %fMW \\n the cost of water is %fRs.per hour/m**3/sec\"%(phh1,r) \n",
"\n",
"if phh2>0 :\n",
" r=lam/(bw+cw*phh2) \n",
" print \" hydro plant power is %fMW \\n the cost of water is %fRs.per hour/m**3/sec\"%(phh2,r) "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" hydro plant power is 237.047484MW \n",
" the cost of water is 0.788486Rs.per hour/m**3/sec\n"
]
}
],
"prompt_number": 11
}
],
"metadata": {}
}
]
}
|
