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{
"metadata": {
"name": "Chapter 5"
},
"nbformat": 2,
"worksheets": [
{
"cells": [
{
"cell_type": "markdown",
"source": [
"#Chapter 5 :- The Second Law of Thermodynamics"
]
},
{
"cell_type": "markdown",
"source": [
"##<heading2> Example 5.1 Page no- 194"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"",
"# Given :-",
"W = 410.00 # net work output in kj claimed ",
"Q = 1000.00 # energy input by heat transfer in kj",
"Tc = 300.00 # temperature of cold reservoir in kelvin",
"TH = 500.00 # temperature of hot reservoir in kelvin",
"",
"# Calculations ",
"eta = W/Q # thermal efficiency",
"etamax = 1-(Tc/TH)",
"",
"# Results",
"print '-> Eta = ',round(eta,4)",
"print '-> Etamax = ',round(etamax,4)",
"print '-> Since eta is more than etamax, the claim is not authentic'"
],
"language": "python",
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"-> Eta = 0.41",
"-> Etamax = 0.4",
"-> Since eta is more than etamax, the claim is not authentic"
]
}
],
"prompt_number": 1
},
{
"cell_type": "markdown",
"source": [
"##<heading2> Example 5.2 Page no- 195"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"",
"# Given :-",
"Qcdot = 8000.00 # in kj/h",
"Wcycledot = 3200.00 # in kj/h",
"Tc = 268.00 # temperature of compartment in kelvin",
"TH = 295.00 # temperature of the surrounding air in kelvin",
"",
"# Calculations ",
"beta = Qcdot/Wcycledot # coefficient of performance",
"betamax = Tc/(TH-Tc) # reversible coefficient of performance",
"",
"# Results",
"print '-> Coefficient of performance is ',round(beta,3)",
"print '-> Coefficient of performance of a reversible cycle is ',round(betamax,3)"
],
"language": "python",
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"-> Coefficient of performance is 2.5",
"-> Coefficient of performance of a reversible cycle is 9.926"
]
}
],
"prompt_number": 2
},
{
"cell_type": "markdown",
"source": [
"##<heading2> Eample 5.3 Page no- 196"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"",
"# Given :-",
"Tc = 283.0 # in kelvin",
"TH = 295.0 # in kelvin",
"QH = 5*(10**5) # in kj per day",
"",
"# Calculations",
"Wcyclemin = (1-(Tc/TH))*QH",
"",
"# Results",
"print '-> Minimum theoretical work input for one day of operation in kJ is: ',round(Wcyclemin,2)"
],
"language": "python",
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"-> Minimum theoretical work input for one day of operation in kJ is: 20338.98"
]
}
],
"prompt_number": 3
}
]
}
]
}
|
