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{
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"name": "",
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 6 - Dimensional analysis and model similitude"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3 - Pg 230"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the flow rate of water and pressure drop\n",
"#Initialization of variables\n",
"dg=0.5 #in\n",
"dw=12. #in\n",
"rhog=0.022 #slug/ft^3\n",
"rhow=1.94 #slug/ft^3\n",
"muw=2.34e-5 #lb-sec/ft^2\n",
"mug=3.50e-7 #lb-sec/ft^2\n",
"Qg=0.15 #ft^3/s\n",
"dpg=100. #lb/ft^2\n",
"#calculations\n",
"Vr=dg/dw *rhog/rhow *muw/mug\n",
"Qr=Vr*dw*dw /dg/dg\n",
"Qw=Qr*Qg\n",
"dpr=rhow/rhog *(Vr)*Vr\n",
"dpw=dpr*dpg\n",
"#results\n",
"print '%s %.2f %s' %(\"Flow rate of water =\",Qw,\"ft^3/s\")\n",
"print '%s %.1f %s' %(\"\\n Pressure drop =\",dpw,\"lb/ft^2\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Flow rate of water = 2.73 ft^3/s\n",
"\n",
" Pressure drop = 8.8 lb/ft^2\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 4 - Pg 231"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the velocity ratio, time ratio, acceleration ratio and force ratio.\n",
"#Initialization of variables\n",
"import math\n",
"Lr=1./10.\n",
"rhom=2.\n",
"rhop=1.94\n",
"#calculations\n",
"Vr=math.sqrt(Lr)\n",
"Tr=Lr/Vr\n",
"ar=Vr/Tr\n",
"Fr=rhom/rhop *ar*Lr*Lr*Lr\n",
"#results\n",
"print '%s %.4f' %(\"Velocity ratio = \",Vr)\n",
"print '%s %.4f' %(\"\\n Time ratio = \",Tr)\n",
"print '%s %d' %(\"\\n Acceleration ratio = \",ar)\n",
"print '%s %.6f' %(\"\\n Force ratio = \",Fr)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Velocity ratio = 0.3162\n",
"\n",
" Time ratio = 0.3162\n",
"\n",
" Acceleration ratio = 1\n",
"\n",
" Force ratio = 0.001031\n"
]
}
],
"prompt_number": 2
}
],
"metadata": {}
}
]
}
|
