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{
"metadata": {
"name": "",
"signature": "sha256:0a4301c920a86f7888d81f22a80d24105313c5ae1dd42947a9f33bfe49dcea1b"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 11 : Steady Flow in Open Channels"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 11.1 Page No : 348"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math \n",
"\n",
"\t\n",
"#Initialization of variables\n",
"y = 3.4 \t#ft\n",
"n = 0.016\n",
"\t\n",
"#calculations\n",
"A = (10+2*y)*y\n",
"P = 10+ 2*math.sqrt(5) *y\n",
"Rh = A/P\n",
"f = 116*n**2 /Rh**(1./3)\n",
"e = 14.8*Rh/ 10**(1./2/math.sqrt(f))\n",
"\t\n",
"#Results\n",
"print \"absolute roughness of pipe = %.4f ft\"%(e)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"absolute roughness of pipe = 0.0159 ft\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 11.2 Page No : 362"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math \n",
"\t\n",
"#Initialization of variables\n",
"y = 1.495 \t#ft\n",
"Q = 14. \t#cfs\n",
"g = 32.2\n",
"\t\n",
"#calculations\n",
"yc = (Q**2 /g *2)**(1./5)\n",
"\t\n",
"#Results\n",
"print \"yc = %.2f ft is greater than uniform flow depth. Hence flow is supercritical\"%(yc)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"yc = 1.65 ft is greater than uniform flow depth. Hence flow is supercritical\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 11.3 Page No : 366"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math \n",
"\t\n",
"#Initialization of variables\n",
"q = 27./4\n",
"g = 32.2\n",
"Q = 27. \t#cfs\n",
"d = 2. \t#ft\n",
"dz1 = 0.3 \t#ft\n",
"\t\n",
"#calculations\n",
"yc = (q**2 /g)**(1./3)\n",
"V2 = Q/(4*yc)\n",
"V1 = Q/(4*d)\n",
"dz = d+ V1**2 /(2*g) - V2**2/(2*g) - yc\n",
"y2 = 1.6 \t#ft\n",
"drop = d-(y2+dz1)\n",
"dz2 = 0.6 \t#ft\n",
"up = 2.12 \t#ft\n",
"down = 0.66 \t#ft\n",
"\t\n",
"#Results\n",
"print \"yc = %.2f ft. Since, depth is greater than critical depth, the flow is subcritical\"%(yc)\n",
"print \" Drop in water height = %.2f ft\"%(drop)\n",
"print \" Drop upstream = %.2f ft and Downstream = %.2f ft\"%(up,down)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"yc = 1.12 ft. Since, depth is greater than critical depth, the flow is subcritical\n",
" Drop in water height = 0.10 ft\n",
" Drop upstream = 2.12 ft and Downstream = 0.66 ft\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 11.5 Page No : 381"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math \n",
"\t\n",
"#Initialization of variables\n",
"y0 = 2.17 \t#ft\n",
"q = 400./10 #flow rate\n",
"g = 32.2\n",
"d = 4.8 \t#ft\n",
"S0 = 0.0016\n",
"\t\n",
"#calculations\n",
"yc = round((q**2 /g)**(1./3),2)\n",
"y2 = round(y0/2 *(-1 + math.sqrt(1+ 8*q**2 /(g*y0**3))),2)\n",
"y1 = round(d/2 *(-1 + math.sqrt(1+ 8*q**2/(g*d**3))),2)\n",
"E1 = round(y0 + (q/y0)**2 /(2*g),2)\n",
"E2 = round(y1+ (q/y1)**2 /(2*g),2)\n",
"Vm = 0.5*(q/y0 + q/y1)\n",
"Rm = 0.5*(y0/1.434 + y1/1.552)\n",
"S = (0.013*Vm/(1.49*Rm**(2./3)))**2\n",
"dx = (E1-E2)/(S-S0)\n",
"E1d = E2\n",
"E2d = d+ (q/4.8)**2 /(2*g)\n",
"HPl = 62.4*q*10*(E1d-E2d)/550\n",
"\n",
"#Results\n",
"print \"Power loss = %.2f \"%(HPl)\n",
"#The answer is a bit different from the textbook due to rounding off error\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Power loss = 7.79 \n"
]
}
],
"prompt_number": 41
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 11.6 Page No : 386"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from numpy import *\n",
"\t\n",
"#Initialization of variables\n",
"y1 = array([1.5, 1.48])\n",
"V1 = array([2.22, 2.29])\n",
"d = 1.2\n",
"\t\n",
"#calculations\n",
"q = y1*V1\n",
"V2 = q/d\n",
"Vm = array([2.5, 2.56])\n",
"Rh1 = array([0.9, 0.89])\n",
"Rh2 = array([0.88, 0.78])\n",
"Rhm = (Rh1+Rh2)/2\n",
"S = (q*Vm/ Rhm**(2./3))**2\n",
"dx = [358 ,226]\n",
"yavg = (y1[0] + y1[1])/2\n",
"qavg = (q[0] + q[1])/2\n",
"B = 4.5\n",
"Q = qavg*B\n",
"\t\n",
"#Results\n",
"print \"Flow rate = %.1f m**3/s\"%(Q)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Flow rate = 15.1 m**3/s\n"
]
}
],
"prompt_number": 10
}
],
"metadata": {}
}
]
}
|
