1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
|
{
"metadata": {
"name": "",
"signature": "sha256:779dd4cf4a63ec7ae3b3ee56b532415f0e7430caa393646786820e5bcc3483bb"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Chapter 6 : Dimensional Analysis and Dynamic Similitude"
]
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 6.2 Page no 233"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"L = 10 # length scale lp/l\n",
"\n",
"\n",
"rhop = 0.86*998.2 # density inn kg/m**3\n",
"\n",
"mup = 8*10**-3 # viscosity in Ns/m**2\n",
"\n",
"Vp = 2.5 # Velocity in m/s\n",
"\n",
"\n",
"rhom = 998.2 # density in kg/m**3\n",
"\n",
"mum = 1.005*10**-3 # viscosity in Ns/m**2\n",
"\n",
"\n",
"Vm = Vp*L*(rhop/rhom)*(mum/mup) # velocity in m/s\n",
"\n",
"print \"Hence the model should be tested at a velocity of \",round(Vm,2),\"m/s. This velocity in the model is called corresponding velocity\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Hence the model should be tested at a velocity of 2.7 m/s. This velocity in the model is called corresponding velocity\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 6.3 Page no 233"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"from __future__ import division\n",
"\n",
"from math import *\n",
"\n",
"l = 300 # length in ft\n",
"\n",
"Q = 100000 # discharge in cfs\n",
"\n",
"Cd = 3.8 # coefficient of discharge\n",
"\n",
"L = (1/50) # length scale\n",
"\n",
"\n",
"Qm = 100000*(L)**(5/2) # model discharge in cfs\n",
"\n",
"print \"Maximum discharge, Qm = \",round(Qm,8),\"cfs\"\n",
"\n",
"H = (Q/(Cd*l))**(2/3) # height over spill way\n",
"\n",
"h = H*L*12 # head over spill model\n",
"\n",
"print \"Maximum head over crest = \",round(h,2),\"ft\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Maximum discharge, Qm = 5.65685425 cfs\n",
"Maximum head over crest = 4.74 ft\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
