path: root/Fiber_Optics_Communication_by_H._Kolimbiris/chapter6_1.ipynb

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 "worksheets": [
  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "Chapter 6: Optical Transmittor"
     ]
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.1,Page number 139"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#Given\n",
      "\n",
      "Tj=125;         #in degree celsius\n",
      "Tamp=60;        #n degree celsius\n",
      "Pt=1.8;         #in W\n",
      "RthJ_a =34;     #in k/w(Assumption)\n",
      "Rth=(Tj-Tamp)/Pt;\n",
      "print\"Rth =\",round(Rth,4),\"K/W\";\n",
      "if Rth>RthJ_a:\n",
      "    print\"No Heat sink is required\";\n",
      "else:\n",
      "    print\"Yes,Heat sink is required\";    \n",
      "  \n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Rth = 36.1111 K/W\n",
        "No Heat sink is required\n"
       ]
      }
     ],
     "prompt_number": 2
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.2,Page number 140"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#Given\n",
      "\n",
      "Tj=120;         #in degree celsius\n",
      "Tamp=80;        #in degree celsius\n",
      "Pt=2.1;         #in W \n",
      "RthJ_a =34;     #in k/w(Assumption)\n",
      "Rth=(Tj-Tamp)/Pt;\n",
      "print\"Rth =\",round(Rth,4),\"K/W\";\n",
      "if Rth>RthJ_a:\n",
      "    print\"No Heat sink is required\";\n",
      "else:\n",
      "    print\"Yes,Heat sink is required\";"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Rth = 19.0476 K/W\n",
        "Yes,Heat sink is required\n"
       ]
      }
     ],
     "prompt_number": 5
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.3,Page number 140"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "#data insufficient\n",
      "Rth=17.70;          # Rth assumed minimum\n",
      "Rthc_H=0.65;        #k/w\n",
      "Rthj_a=33.0;          #k/w\n",
      "Rthj_c=3;           #k/w\n",
      "RthH_a=1/(1/Rth-1/Rthj_a)-Rthj_c-Rthc_H;\n",
      "print\"RthH-a <=\",round(RthH_a,4),\"K/W\";"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "RthH-a <= 34.5265 K/W\n"
       ]
      }
     ],
     "prompt_number": 8
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.4,Page number 148"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "Vcc=5;        #in volt\n",
      "Icc=24;       #in mA\n",
      "Vset=0.65;    #in volt\n",
      "Vf=1.5;       #in volt\n",
      "IMOD=15;      #in mA\n",
      "TA=25;        #in degree celsius\n",
      "Pdynamic=(Vcc-Vf-Vset)*Icc;\n",
      "print\"Power dissipation under dynamic condition\",Pdynamic,\"mW\";\n",
      "Pstatic=(Vcc*Icc);\n",
      "print\"power dissipation under static condition\",Pstatic,\"mW\";\n",
      "PD=Pdynamic+Pstatic;\n",
      "print\"total power dissipation\",PD,\"mW\";\n",
      "#Tj=TA+PD*wj_a;\n",
      "TA=25;       #in degree cel\n",
      "wj_a=84;     #degree cel/w\n",
      "PD=188.4;    #mW\n",
      "Tj=TA+PD*10**-3*wj_a;\n",
      "print\"Temp. of junction temp\",Tj,\"degree C\";\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Power dissipation under dynamic condition 68.4 mW\n",
        "power dissipation under static condition 120 mW\n",
        "total power dissipation 188.4 mW\n",
        "Temp. of junction temp 40.8256 degree C\n"
       ]
      }
     ],
     "prompt_number": 9
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.5,Page number 150"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "Ifon=120.0;       #in mA\n",
      "Vcc=5;          #in V\n",
      "Vfon=2;         #in V\n",
      "R3=(Vcc-Vfon)/Ifon/10**-3 +3.2*(Vcc-Vfon-1.4)/Ifon/10**-3;\n",
      "print\" R3=\",round(R3,4),\"ohm\";\n",
      "\n",
      "R0=(R3-32)/3.2;\n",
      "print\" R0=\",round(R0,4),\"ohm\";\n",
      "\n",
      "R1=(R0+10)/2;\n",
      "print\" R1=\",round(R1,1),\"ohm\";\n",
      "R2=R1-10;\n",
      "print\" R2=\",round(R2,1),\"ohm\";\n",
      "C1=2*10**-9/R1;\n",
      "print\" C1=\",round(C1*10**12,4),\"pF\";         \n",
      "\n",
      "#answer in book is approximately written\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " R3= 67.6667 ohm\n",
        " R0= 11.1458 ohm\n",
        " R1= 10.6 ohm\n",
        " R2= 0.6 ohm\n",
        " C1= 189.1626 pF\n"
       ]
      }
     ],
     "prompt_number": 5
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.6,Page number 155"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "Impd1=250;     #in microA\n",
      "Impd0=25;      #in microA\n",
      "Iref=(1./16)*Impd1*10**-6;\n",
      "print\" Reference current is\",Iref*10**6,\"microA\";\n",
      "Rref=1.5/Iref;\n",
      "print\" External bias resistor value Rref1 is\",Rref/1000,\"kohm\";\n",
      "\n",
      "Rref1=24.0/Impd1/10**-6;\n",
      "print\" Also,Rref1=24/Impd \\n External bias resistor value is\",Rref1/1000,\"kohm\";\n",
      "Irefz=(1./4)*Impd0;\n",
      "print\" Ref0 current is\",Irefz,\"microA\";\n",
      "Rrefz=1.5/Irefz/10**-6;\n",
      "print\" External bias resistor value Rrefz is\",Rrefz/1000,\"kohm\";\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " Reference current is 15.625 microA\n",
        " External bias resistor value Rref1 is 96.0 kohm\n",
        " Also,Rref1=24/Impd \n",
        " External bias resistor value is 96.0 kohm\n",
        " Ref0 current is 6.25 microA\n",
        " External bias resistor value Rrefz is 240.0 kohm\n"
       ]
      }
     ],
     "prompt_number": 7
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.7,Page number 157"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "R=400;          #in mA\n",
      "nEO=25;         #in mW\n",
      "n_laser=nEO*10**-3*R*10**-3;\n",
      "print\"n_laser =\",n_laser;\n",
      "Tone=(40*10**-12)*(80*10**3)/n_laser;\n",
      "print\"Tone =\",Tone*10**6,\"micros\";\n",
      "BWone=1./(2*math.pi*Tone);\n",
      "print\"BWone =\",round(BWone,4),\"Hz \";\n",
      "Tzero=(40*10**-12)*80*10**3/n_laser;\n",
      "BWzero=1.0/2/math.pi/Tzero;        #Hz\n",
      "print\"BWzero =\",round(BWzero,4),\"Hz\";\n",
      "\n",
      "#answer misprinted\n",
      "\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "n_laser = 0.01\n",
        "Tone = 320.0 micros\n",
        "BWone = 497.3592 Hz \n",
        "BWzero = 497.3592 Hz\n"
       ]
      }
     ],
     "prompt_number": 13
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.8,Page number 159"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "iol =5;         #in mA\n",
      "ioh=80;         #bias current in mA\n",
      "ralarmH=(1.5*1500)/ioh/10**-3;\n",
      "print\" Alarm resistor RalarmH is\",ralarmH/1000,\"kOhm\";\n",
      "ralarmL=(1.5*300)/iol/10**-3;\n",
      "print\" Alarm resistor RalarmL is\",ralarmL/1000,\"kOhm\";\n",
      "ialarmh=80*10**-3;\n",
      "ialarmH=ioh*10**-3/1500;\n",
      "print\" Alarm current  IalarmH is\",round(ialarmH*10**6,4),\"microA\";  #unit of anwer misprinted in book\n",
      "ialarml=5*10**-3;\n",
      "ialarmL=iol*10**-3/300;\n",
      "print\" Alarm current  IalarmL is\",round(ialarmL*10**6,4),\"microA\";\n",
      "\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " Alarm resistor RalarmH is 28.125 kOhm\n",
        " Alarm resistor RalarmL is 90.0 kOhm\n",
        " Alarm current  IalarmH is 53.3333 microA\n",
        " Alarm current  IalarmL is 16.6667 microA\n"
       ]
      }
     ],
     "prompt_number": 4
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.9,Page number 160"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "Ibias=15.;       #in mA  assumption\n",
      "Ild=35.;         #in mA\n",
      "Rld=50.;         #in ohm\n",
      "Ildi=100.;       #in mA\n",
      "Ilde=50.;        #in mA\n",
      "Imod=(Ildi+Ilde)/Ildi*35;  #mA\n",
      "print\"Total modulation current is \\nImod=\",round(Imod,4),\"mA\";\n",
      "Ildq=1.2/100*10**3;                    #in mA  \n",
      "print\"The current complementary output is Ildq=\",round(Ildq,4),\"mA\";\n",
      "Vld=-1.2-Rld*(Ibias+Ild)*10**-3;       #optical high\n",
      "print\"The laser voltage for optical high is Vld=\",round(Vld,4),\"V\";\n",
      "Vld=-1.2-Rld*(Ibias)*10**-3;           #optical dark\n",
      "print\"The laser voltage for optical dark is Vld=\",round(Vld,4),\"V\";\n",
      "Vldq=-Ild*10**-3*Rld;\n",
      "print\"The laser voltage at complimentary o/p is Vldq=\",round(Vldq,4),\"V\";\n",
      "Rchock=5;           #in Ohm\n",
      "Vchock=-Rchock*Ibias*10**-3;\n",
      "print\"Vchock=\",round(Vchock,4),\"V\";\n",
      "Vbias=0.5*(-3.7+Vld)+Vchock;\n",
      "print\"Vbias=\",round(Vbias,4),\"V\";\n",
      "\n",
      "#(i) Pdvee1\n",
      "Pdvcc=5*2.5;          #in mW\n",
      "print\"Pdvcc=\",round(Pdvcc,4),\"mW\";\n",
      "Pdvee1=4.5*80;        #in mW\n",
      "print\"Pdvee1=\",round(Pdvee1,4),\"mW\";\n",
      "\n",
      "#(ii) Pdvee2\n",
      "Pdvee2=6*160;         #in mW\n",
      "print\"Pdvee2=\",Pdvee2,\"mW\";\n",
      "\n",
      "#(iii) PdLD\n",
      "PdLD=0.5*(3.75*50);    #in mW\n",
      "print\"PdLD=\",round(PdLD,4),\"mW\";\n",
      "\n",
      "#(iv) PdLQ\n",
      "PdLDQ=0.5*abs(Vld)*50;  #in mW\n",
      "print\"PdLDQ=\",round(PdLDQ,4),\"mW\";\n",
      "\n",
      "#(v) PdLDQ\n",
      "Pdbias=abs(Vbias)*Ibias; #in mW\n",
      "print\"Pdbias=\",round(Pdbias,4),\"mW\";\n",
      "\n",
      "#PT\n",
      "PT=Pdvcc+Pdvee1+Pdvee2-(PdLD+PdLDQ+Pdbias);\n",
      "print\"Total power dissipation (PT)=\",round(PT,4),\"mW\";\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Total modulation current is \n",
        "Imod= 52.5 mA\n",
        "The current complementary output is Ildq= 12.0 mA\n",
        "The laser voltage for optical high is Vld= -3.7 V\n",
        "The laser voltage for optical dark is Vld= -1.95 V\n",
        "The laser voltage at complimentary o/p is Vldq= -1.75 V\n",
        "Vchock= -0.075 V\n",
        "Vbias= -2.9 V\n",
        "Pdvcc= 12.5 mW\n",
        "Pdvee1= 360.0 mW\n",
        "Pdvee2= 960 mW\n",
        "PdLD= 93.75 mW\n",
        "PdLDQ= 48.75 mW\n",
        "Pdbias= 43.5 mW\n",
        "Total power dissipation (PT)= 1146.5 mW\n"
       ]
      }
     ],
     "prompt_number": 6
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.10,Page number 161"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "vcc=-5;             #in v\n",
      "imod=35;            #in mA\n",
      "ibias=18;           #in mA\n",
      "vbias=-2;           #in v\n",
      "vout=2;             #in v\n",
      "tj=30;              #degree cel\n",
      "icc=140;            #in mA\n",
      "Pt=(-vcc*icc*10**-3)+(-vcc-vout)*imod*10**-3+(-vcc+vbias)*ibias*10**-3;\n",
      "print\"Pt=\",Pt*1000,\"mW\";\n",
      "Tj=30;              #in degree\n",
      "Tj_a=Tj*Pt;\n",
      "Tcase=125-Tj_a;     #in degree\n",
      "print\"Tcase(max)=\",Tcase,\"degree Cel\";"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Pt= 859.0 mW\n",
        "Tcase(max)= 99.23 degree Cel\n"
       ]
      }
     ],
     "prompt_number": 8
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.11,Page number 174"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "z11=49.95;          #in ohm\n",
      "z12=0.15;           #in ohm\n",
      "z21=0.15;           #in ohm\n",
      "z22=49.95;          #in ohm\n",
      "zdiff=2*(z11-z12);\n",
      "print\"Zdiff=\",zdiff,\"ohm\";        #answer misprinted\n",
      "zcm=z11+z12;\n",
      "print\"Zcm=\",zcm,\"ohm\";\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Zdiff= 99.6 ohm\n",
        "Zcm= 50.1 ohm\n"
       ]
      }
     ],
     "prompt_number": 11
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.12,Page number 174"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "z11=65.4;     #in ohm\n",
      "z12=8.2;      #in ohm\n",
      "z21=8.2;      #in ohm\n",
      "z22=65.4;     #in ohm\n",
      "zdiff=2*(z11-z12);\n",
      "print\" Zdiff=\",zdiff,\"ohm\";  \n",
      "zcm=z11+z12;\n",
      "print\" Zcm=\",zcm,\"ohm\";\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " Zdiff= 114.4 ohm\n",
        " Zcm= 73.6 ohm\n"
       ]
      }
     ],
     "prompt_number": 12
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.13,Page number 181"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "dV=50;              #in mV\n",
      "di=3;               #in Amp\n",
      "Lcable=15;          #in nH\n",
      "fL=dV*10**-3/di/2/math.pi/Lcable/10**-9;\n",
      "print\"fLcable =\",round(fL/1000,4),\"kHz\";\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "fLcable = 176.8388 kHz\n"
       ]
      }
     ],
     "prompt_number": 14
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.14,Page number 181"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "dV=50;          #in mV\n",
      "di=4;           #in Amp\n",
      "fL=120;         #in kHz\n",
      "Lcable=dV*10**-3/di/2/math.pi/fL/10**3;\n",
      "print\"The maximum allowed parasitic cable inductance (Lcable) must not exceed\",round(Lcable*10**9,4),\"nH\";\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "The maximum allowed parasitic cable inductance (Lcable) must not exceed 16.5786 nH\n"
       ]
      }
     ],
     "prompt_number": 17
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.15,Page number 182"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "dV=40;              #in mV\n",
      "di=2.5;             #in Amp\n",
      "Lbypas=0.5;         #in nH\n",
      "fL=dV*10**-3/di/2/math.pi/Lbypas/10**-9;\n",
      "print\"fHnoise =\",round(fL/10**6,4),\"MHz\";\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "fHnoise = 5.093 MHz\n"
       ]
      }
     ],
     "prompt_number": 19
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.16,Page number 182"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "dV=50;              #in mV\n",
      "di=2.5;             #in Amp\n",
      "Cbypas=220;         #in microF\n",
      "fL=di/(dV*10**-3*2*math.pi*Cbypas*10**-6);\n",
      "print\"fLnoise =\",round(fL/1000,4),\"kHz\";          #Result\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "fLnoise = 36.1716 kHz\n"
       ]
      }
     ],
     "prompt_number": 21
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.17,Page number 182"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "dV=50;              #in mV\n",
      "di=4;               #in Amp\n",
      "Cbypas=200;         #in microF\n",
      "Lbypas=0.2;         #in nH\n",
      "fL=di/(dV*10**-3*2*math.pi*Cbypas*10**-6);\n",
      "print\"fLnoise =\",round(fL/1000,4),\"kHz\";          #Result misprinted\n",
      "fH=dV*10**-3/di/2/math.pi/Lbypas/10**-9;\n",
      "print\"fHnoise =\",round(fH/10**6,4),\"MHz \";         \n",
      "Bw=fH-fL;\n",
      "print\"Bwnoise =\",round(Bw/10**6,4),\"MHZ\";         #Result miscalculated\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "fLnoise = 63.662 kHz\n",
        "fHnoise = 9.9472 MHz \n",
        "Bwnoise = 9.8835 MHZ\n"
       ]
      }
     ],
     "prompt_number": 23
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.18,Page number 184"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "dV=40;          #in mV\n",
      "di=3;           #in Amp\n",
      "LT=0.05;        #in nH\n",
      "fH=dV*10**-3/di/2/math.pi/LT/10**-9;\n",
      "print\"fCdecoupling(high) =\",round(fH/10**6,4),\"MHz\";         #Result"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "fCdecoupling(high) = 42.4413 MHz\n"
       ]
      }
     ],
     "prompt_number": 25
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6.19,Page number 184"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#given\n",
      "\n",
      "dV=45;            #in mV\n",
      "di=2.5;           #in Amp\n",
      "CT=2.2;           #in microF\n",
      "LT=0.05;          #in nH\n",
      "fCL=di/(dV*10**-3*2*math.pi*CT*10**-6);\n",
      "print\"fLnoise =\",round(fCL/10**6,4),\"MHz\";          #Result     \n",
      "fCH=42.3;           #in MHz taken from last question i.e. 6.18      \n",
      "print\"\",round(fCL/10**6,4),\"MHz <=B.W.noise <=\",round(fCH,4),\"MHZ\";         #Result\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "fLnoise = 4.0191 MHz\n",
        " 4.0191 MHz <=B.W.noise <= 42.3 MHZ\n"
       ]
      }
     ],
     "prompt_number": 29
    }
   ],
   "metadata": {}
  }
 ]
}