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{
"metadata": {
"name": "",
"signature": "sha256:56795fefbe7b62ddb8818924d3943a71c60bd075d0e3f1778fec6ffb47c8906e"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"3: Polarization, Laser and Holography"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.1, Page number 103"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#importing modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"x = 5; #distance of 1st minimum(mm)\n",
"D = 2; #distance between lens and screen(m)\n",
"a = 0.2; #width of slit(mm)\n",
"\n",
"#Calculation\n",
"x = x*10**-3; #distance of 1st minimum(m)\n",
"a = a*10**-3; #width of slit(m)\n",
"lamda = a*x/D; #wavelength of light(m)\n",
"\n",
"#Result\n",
"print \"wavelength of light is\",lamda,\"m\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"wavelength of light is 5e-07 m\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.2, Page number 103"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#importing modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"a = 0.2; #width of slit(mm)\n",
"lamda = 5*10**-7; #wavelength(m)\n",
"f = 50; #focal length(cm)\n",
"\n",
"#Calculation\n",
"a = a*10**-3; #width of slit(m)\n",
"f = f*10**-2; #focal length(m)\n",
"theta_1 = lamda/a; #angular diffraction correcponding to 1st minima(radian)\n",
"theta_2 = 2*lamda/a; #angular diffraction correcponding to 2nd minima(radian)\n",
"x = f*(theta_2-theta_1); #separation between 1st and second minima(m)\n",
"x = x*10**2;\n",
"\n",
"#Result\n",
"print \"distance between first two minima on the screen is\",x,\"*10**-3 m\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"distance between first two minima on the screen is 0.125 *10**-3 m\n"
]
}
],
"prompt_number": 8
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.3, Page number 104"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#importing modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"a = 0.16; #1st slit width(mm)\n",
"b = 0.8; #2nd slit width(mm)\n",
"\n",
"#Calculation\n",
"nbym = (a+b)/a; #condition for missing orders\n",
"\n",
"#Result\n",
"print \"n = \",nbym,\"m\"\n",
"print \"n = \",nbym,\",\",2*nbym,\",\",3*nbym,\"etc for m = 1,2,3...\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"n = 6.0 m\n",
"n = 6.0 , 12.0 , 18.0 etc for m = 1,2,3...\n"
]
}
],
"prompt_number": 13
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.4, Page number 104"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#importing modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"n = 2; #second order\n",
"theta = 30; #angle of diffraction(degrees)\n",
"lamda = 5*10**-5; #wavelength(cm)\n",
"\n",
"#Calculation\n",
"theta = theta*math.pi/180; #angle of diffraction(radian)\n",
"aplusb = n*lamda/math.sin(theta);\n",
"N = 1/aplusb; #number of lines(per cm)\n",
"\n",
"#Result\n",
"print \"number of lines on the grating surface is\",N,\"per cm\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"number of lines on the grating surface is 5000.0 per cm\n"
]
}
],
"prompt_number": 14
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.5, Page number 105"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#importing modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"aplusb = 1.5*10**-6; #grating element(m)\n",
"lamda = 550; #wavelength(nm)\n",
"\n",
"#Calculation\n",
"lamda = lamda*10**-9; #wavelength(m)\n",
"n = aplusb/lamda; #maximum possible order\n",
"n = math.ceil(n*10**3)/10**3; #rounding off to 3 decimals\n",
"\n",
"\n",
"#Result\n",
"print \"maximum possible order is\",n,\". third and higher orders are not possible\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"maximum possible order is 2.728 . third and higher orders are not possible\n"
]
}
],
"prompt_number": 19
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.6, Page number 105"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#importing modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"dlamda = 0.6; #difference in wavelength(nm)\n",
"lamda = 589.3; #wavelength(nm)\n",
"n = 1; #first order\n",
"\n",
"#Calculation\n",
"N = lamda/(n*dlamda); #number of lines on grating\n",
"\n",
"#Result\n",
"print \"number of lines on grating is\",int(N)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"number of lines on grating is 982\n"
]
}
],
"prompt_number": 21
}
],
"metadata": {}
}
]
}
|
