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{
"metadata": {
"name": "",
"signature": "sha256:064d55405a5d05f007b28f32cf39a9f99d10f303fc4084e2d14d99aaeb87858c"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Physics of Nano Materials"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 8.1, Page number 320"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" \n",
"#import modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable decleration\n",
"r=5; #radius in m\n",
"pi=3.14;\n",
"\n",
"#Calculation \n",
"SA=4*pi*r**2; #surface area of sphere in m^2\n",
"V=(4/3)*pi*r**3; #volume of sphere in m^3\n",
"R=SA/V; #ratio\n",
"#surface area to volume ratio can also be given by 3/radius\n",
"\n",
"#Result\n",
"print(\"surface area to volume ratio of sphere in m-1 is\",R);"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"('surface area to volume ratio of sphere in m-1 is', 0.6)\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 8.2, Page number 321"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" \n",
"#import modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable decleration\n",
"d=26; #distance in m\n",
"r=d/2; #radius in m\n",
"pi=3.14;\n",
"\n",
"#Calculation\n",
"SA=4*pi*r**2; #surface area of sphere in m^2\n",
"V=(4/3)*pi*r**3; #volume of sphere in m^3\n",
"R=SA/V; #ratio\n",
"R=math.ceil(R*10**3)/10**3; #rounding off to 3 decimals\n",
"#surface area to volume ratio can also be given by 3/radius\n",
"\n",
"#Result\n",
"print(\"surface area to volume ratio of sphere in m-1 is\",R);"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"('surface area to volume ratio of sphere in m-1 is', 0.231)\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 8.3, Page number 321"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" \n",
"#import modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable decleration\n",
"r=1; #radius in m\n",
"h=1; #height in m\n",
"pi=3.14\n",
"\n",
"#Calculation\n",
"V=(1/3)*pi*(r**2)*h;\n",
"V=math.ceil(V*10**2)/10**2; #rounding off to 2 decimals\n",
"\n",
"#Result\n",
"print(\"volume of cone in m^3 is\",V); "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"('volume of cone in m^3 is', 1.05)\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 8.4, Page number 321"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" \n",
"#import modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable decleration\n",
"r=3; # radius in m\n",
"h=4; # height in m\n",
"pi=3.14\n",
"\n",
"#Calculation\n",
"SA=pi*r*math.sqrt((r**2)+(h**2));\n",
"TSA=SA+(pi*r**2);\n",
"\n",
"#Result\n",
"print(\"total surface area of cone in m^2 is\",TSA);\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"('total surface area of cone in m^2 is', 75.36)\n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 8.5, Page number 322"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" \n",
"#import modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable decleration\n",
"V=100; #volume of cone in cubic inches\n",
"r=5; #radius of cone in inches\n",
"pi=3.14;\n",
"\n",
"#Calculation\n",
"r_m=r*0.0254; #radius of cone in m\n",
"#volume V=(1/3)*pi*(r**2)*h\n",
"#therefore h = (3*V)/(pi*r**2)\n",
"h=(3*V)/(pi*r**2); #height in inches\n",
"R=3/r_m;\n",
"h=math.ceil(h*10**3)/10**3; #rounding off to 3 decimals\n",
"\n",
"#Result\n",
"print(\"height of the cone in inches is\",h);\n",
"print(\"surface area to volume ratio in m-1 is\",R);\n",
"\n",
"#answer for the surface area to volume ratio given in the book is wrong"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"('height of the cone in inches is', 3.822)\n",
"('surface area to volume ratio in m-1 is', 23.62204724409449)\n"
]
}
],
"prompt_number": 18
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
