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{
"metadata": {
"name": "",
"signature": "sha256:3f2462cfb429298e26fc6bf563d665947cd211731889b95d7dd1a2db3452c286"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Fibre Optics"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.1, Page number 98 "
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#importing modules\n",
"import math\n",
"\n",
"#Variable declaration\n",
"n1=1.6; #refractive index of core\n",
"n2=1.5; #refractive index of cladding\n",
"\n",
"#Calculation\n",
"NA=math.sqrt((n1**2)-(n2**2));\n",
"NA=math.ceil(NA*10**4)/10**4; #rounding off to 4 decimals\n",
"\n",
"#Result\n",
"print(\"the numerical aperture of the fibre is\",NA);\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"('the numerical aperture of the fibre is', 0.5568)\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.2, Page number 98 "
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#importing modules\n",
"import math\n",
"\n",
"#Variable declaration\n",
"n1=1.54; #refractive index of core\n",
"n2=1.5; #refractive index of cladding\n",
"n0=1;\n",
"\n",
"#Calculation\n",
"NA=math.sqrt((n1**2)-(n2**2)); #numerical aperture of fibre\n",
"NA=math.ceil(NA*10**5)/10**5; #rounding off to 5 decimals\n",
"alpha=math.asin(NA/n0); #acceptance angle in radians\n",
"alpha=alpha*57.2957795; #converting radians to degrees\n",
"alpha=math.ceil(alpha*10**5)/10**5; #rounding off to 5 decimals\n",
"deg=int(alpha); #converting to degrees\n",
"t=60*(alpha-deg); \n",
"mi=int(t); #converting to minutes\n",
"sec=60*(t-mi); #converting to seconds\n",
"sec=math.ceil(sec*10**3)/10**3; #rounding off to 3 decimals\n",
"\n",
"#Result\n",
"print(\"the numerical aperture of the fibre is\",NA);\n",
"print(\"the acceptance angle of the fibre in degrees is\",alpha);\n",
"print(\"acceptance angle of the fibre is\",deg,\"degrees\",mi,\"minutes\",sec,\"seconds\");\n",
"\n",
"#answer for the angle given in the book is wrong"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"('the numerical aperture of the fibre is', 0.34872)\n",
"('the acceptance angle of the fibre in degrees is', 20.40905)\n",
"('acceptance angle of the fibre is', 20, 'degrees', 24, 'minutes', 32.581, 'seconds')\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.3, Page number 99"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#importing modules\n",
"import math\n",
"\n",
"#Variable declaration\n",
"n1=1.6; #refractive index of core\n",
"n2=1.49; #refractive index of cladding\n",
"\n",
"#Calculation\n",
"thetac=math.asin(n2/n1); #critical angle in radians\n",
"thetac=thetac*57.2957795; #converting radians to degrees\n",
"theta_c=math.ceil(thetac*10**3)/10**3; #rounding off to 3 decimals\n",
"deg=int(thetac); #converting to degrees\n",
"t=60*(thetac-deg); \n",
"mi=int(t); #converting to minutes\n",
"sec=60*(t-mi); #converting to seconds\n",
"sec=math.ceil(sec*10**2)/10**2; #rounding off to 2 decimals\n",
"\n",
"#Result\n",
"print(\"the critical angle of the fibre in degrees is\",theta_c);\n",
"print(\"critical angle of the fibre is\",deg,\"degrees\",mi,\"minutes\",sec,\"seconds\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"('the critical angle of the fibre in degrees is', 68.631)\n",
"('critical angle of the fibre is', 68, 'degrees', 37, 'minutes', 49.85, 'seconds')\n"
]
}
],
"prompt_number": 10
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.4, Page number 99"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#importing modules\n",
"import math\n",
"\n",
"#Variable declaration\n",
"NA=0.15; #numerical aperture\n",
"n2=1.55; #refractive index of cladding\n",
"n0=1.33; #refractive index of water\n",
"\n",
"#Calculation\n",
"n1=math.sqrt((NA**2)+(n2**2)); #refractive index\n",
"n_1=math.ceil(n1*10**5)/10**5; #rounding off to 5 decimals\n",
"alpha=math.asin(math.sqrt(n1**2-n2**2)/n0); #acceptance angle in radians\n",
"alpha=alpha*57.2957795; #converting radians to degrees\n",
"alphaa=math.ceil(alpha*10**3)/10**3; #rounding off to 3 decimals\n",
"deg=int(alpha); #converting to degrees\n",
"t=60*(alpha-deg); \n",
"mi=int(t); #converting to minutes\n",
"sec=60*(t-mi); #converting to seconds\n",
"sec=math.ceil(sec*10**2)/10**2; #rounding off to 2 decimals\n",
"\n",
"#Result\n",
"print(\"refractive index of the core is\",n_1);\n",
"print(\"the acceptance angle of the fibre in degrees is\",alphaa);\n",
"print(\"acceptance angle of the fibre is\",deg,\"degrees\",mi,\"minutes\",sec,\"seconds\");\n",
"\n",
"#answer for acceptance angle given in the book is wrong"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"('refractive index of the core is', 1.55725)\n",
"('the acceptance angle of the fibre in degrees is', 6.476)\n",
"('acceptance angle of the fibre is', 6, 'degrees', 28, 'minutes', 32.55, 'seconds')\n"
]
}
],
"prompt_number": 13
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.5, Page number 100"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#importing modules\n",
"import math\n",
"\n",
"#Variable declaration\n",
"NA=0.26; #numerical aperture\n",
"n1=1.5; #refractive index of core\n",
"d=100; #core diameter in micro meter\n",
"\n",
"#Calculation\n",
"d=100*(10**-6); #core diameter in metre\n",
"n2=math.sqrt((n1**2)-(NA**2));\n",
"n2=math.ceil(n2*10**5)/10**5; #rounding off to 5 decimals\n",
"\n",
"#Result\n",
"print(\"refractive index of the cladding is\",n2);"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"('refractive index of the cladding is', 1.4773)\n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.6, Page number 100"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#importing modules\n",
"import math\n",
"\n",
"#Variable declaration\n",
"NA=0.26; #numerical aperture\n",
"delta=0.015; #refractive index difference\n",
"\n",
"#Calculation\n",
"#NA=math.sqrt(n1**2-n2**2)\n",
"#let A=n1**2-n2**2\n",
"#therefore A=NA**2\n",
"A=NA**2;\n",
"#delta=(n1**2-n2**2)/2*(n1**2)\n",
"#let 2*(n1**2) be B\n",
"#therefore B=A/delta\n",
"B=A/delta;\n",
"n1=math.sqrt(B/2);\n",
"n1=math.ceil(n1*100)/100; #rounding off to 2 decimals\n",
"n2=math.sqrt(n1**2-NA**2);\n",
"n2=math.ceil(n2*10**3)/10**3; #rounding off to 4 decimals\n",
"\n",
"#Result\n",
"print(\"refractive index of the core is\",n1);\n",
"print(\"refractive index of the cladding is\",n2);\n",
"\n",
"#answer for refractive index of cladding given in the book is wrong"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"('refractive index of the core is', 1.51)\n",
"('refractive index of the cladding is', 1.488)\n"
]
}
],
"prompt_number": 19
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
