1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
|
{
"metadata": {
"name": "EE-1"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": "Introduction"
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 1.1 Page 10"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initialisation of Variable\nFC=2000000.0;#in Rs\nv=100.0;#in Rs\ns=200.0;#in Rs\nQ=60000.0;#in units\n\n#Part a \n# calculation\nBEQ=FC/(s-v);#in units\n\n#result\nprint \"Break even quantity in units : \",round(BEQ,3)\n\n#Part b \n#calculation\nBES=FC*s/(s-v);#in Rs\n\nprint \"Break even sales in Rs. : \",round(BES,3)\n\n#Part c \n#calculation\nCon=s*Q-v*Q;#in Rs\nMos=Q*s-BES;#in Rs\n\n#result\nprint \"Contribution in units : \",round(Con,3)\nprint \"Margin of safety in Rs. : \",round(Mos,3)",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "Break even quantity in units : 20000.0\nBreak even sales in Rs. : 4000000.0\nContribution in units : 6000000.0\nMargin of safety in Rs. : 8000000.0\n"
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 1.2,Page 12"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initialisation of variable\nFC=25000.0;#in Rs\nv=45000.0;#in Rs\ns=120000.0;#in Rs\n\n#Part a \n#calculation\nCon=s-v;#in Rs\n\n#result\nprint \"Contribution in Rs \",round(Con,3)\n\n#Part b \n#calculation\nProf=Con-FC;#in Rs\n\n#result\nprint \"Profit in Rs \",round(Prof,3);\n\n#Part c \n#calculation\nPVratio=Con*100.0/s;#in %\nBEP=FC*100.0/PVratio;#in Rs\n\n#result\nprint \"BEP in Rs \", round(BEP,3)\n\n#Part d \n#calculoation\nMS=Prof*100/PVratio;#in Rs\n\n#result\nprint\"M.S. in Rs \", round(MS,3)",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "Contribution in Rs 75000.0\nProfit in Rs 50000.0\nBEP in Rs 40000.0\nM.S. in Rs 80000.0\n"
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 1.3 Page 13"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initialisation of variable\nFC=15000.0;#in Rs\nv=35000.0;#in Rs\ns=80000.0;#in Rs\n\n#Part a \n#calculation\nCon=s-v;#in Rs\n\n#result\nprint \"Contribution in Rs\", round(Con,3);\n\n#Part b \n#calcualtion\nProf=Con-FC;#in Rs\n\n#result\nprint \"Profit in Rs \", round(Prof,3)\n\n#Part c \n#calculation\nPVratio=Con*100/s;\nBEP=FC*100/PVratio;#in Rs\n\n#result\nprint \"BEP in Rs \",round(BEP,3)\n\n#Part d \n#calculation\nMS=Prof*100/PVratio;#in Rs\n\nprint \"M.S. in Rs\",round(MS,3);",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "Contribution in Rs 45000.0\nProfit in Rs 30000.0\nBEP in Rs 26666.667\nM.S. in Rs 53333.333\n"
}
],
"prompt_number": 7
}
],
"metadata": {}
}
]
}
|