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{
"metadata": {
"name": "EE-12"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": "Inventory Control"
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 12.1 Page 160"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nfrom math import sqrt\nD=24000.0;#in units/year\nCo=150.0;#in Rs./order\nPprice=75.0;#Rs./unit\nCpupy=18.0;#in % of Pprice/unit\n\n#calculation\nCc=Pprice*Cpupy/100;#in Rs.\nEOQ=sqrt((2*Co*D)/Cc);#in units\nn=D/round(EOQ);#no. of orders/year\nT=round(EOQ)/D;# time between successive orders in year\nT=T*12;#in months\nT=T*30;#in Days\n\n#result\nprint \"Economic order quantity in units : \",round(EOQ);\nprint \"No. of orders/year : \",round(n,2);\nprint \"Time between successive orders in days : \",round(T);",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "Economic order quantity in units : 730.0\nNo. of orders/year : 32.88\nTime between successive orders in days : 11.0\n"
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 12.2 Page 162"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nfrom math import sqrt\nr=12000.0;#in units/year\nk=24000.0;#in units/year\nCo=175.0;#in Rs./setup\nCc=15.0;#in Rs./unit/year\n\n#calclation\nEOQ=sqrt((2*Co*r)/(Cc*(1-r/k)));#in units\nQ=round(EOQ);#units\nt1=Q/k;#in year\nt1=t1*12*30;#in days\nt2=(Q/r)*(1-r/k);#in year\nt2=t2*12*30;#in days\n\n#result\nprint \"Economic order quantity in units : \",round(Q,3);\nprint \"Cycle time in days :\",round(t1+t2);\nprint \"No. of setups/year : \",round(r/Q,3)",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "Economic order quantity in units : 748.0\nCycle time in days : 22.0\nNo. of setups/year : 16.043\n"
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 12.3 Page 164"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#iniatiation of variable\nfrom math import sqrt\nD=30000.0;#in units/year\nCc=2.0;#in Rs./unit/year\nCo=100.0;#in Rs./orde\nCs=12.0;#in units/year\n\n#calculation\nEOQ=sqrt(2*Co*D*(Cs+Cc)/(Cc*Cs));#in units\nQ=round(EOQ);#units\nQ1=sqrt(2*Co*D*Cs/(Cc*(Cs+Cc)));#in units\nt=Q/D;#in year\nt=t*365;#in days\nt1=Q1/D;#in year\nt1=t1*365;#in days\nt2=t-t1;#in days\n\n#result\nprint \"Ordering quantity in units : \",round(Q,3);\nprint \"Maximum Inventory in units : \",round(Q1);\nprint \"Maximum shortage quantity in units : \",round(Q-Q1);\nprint \"Cycle time in days: \",round(t);\nprint \"Inventory period(t1) in days : \",round(t1);\nprint \"Shortage period(t2) in days : \",round(t2);\nprint \"No. of Orders/year : \",round(D/Q,3);",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "Ordering quantity in units : 1871.0\nMaximum Inventory in units : 1604.0\nMaximum shortage quantity in units : 267.0\nCycle time in days: 23.0\nInventory period(t1) in days : 20.0\nShortage period(t2) in days : 3.0\nNo. of Orders/year : 16.034\n"
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 12.4 Page 166"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nfrom math import sqrt\nr=12000.0;#in units/year\nk=2000.0*12;#in units/year\nCo=400.0;#in Rs./setup\nCc=0.20*12;#in Rs./year\nCs=15.0;#in Rs./unit/year\n\n#calculation\nEOQ=sqrt((2*Co*k*r*(Cc+Cs)/(Cc*(k-r)*Cs)));#in units\nQ=round(EOQ);#units\nQ1=sqrt(2*Co*Cc*r*(k-r)/(Cs*(Cc+Cs)*k));#in units\nQ2=(Q*(k-r)/k)-Q1;#in Units\nt=Q/r;#in year\nt=t*365.0;#in days\nt1=(Q2/r)*365.0;#in days\nt2=(Q2/(k-r))*365.0;#in days\nt3=(Q1/(k-r))*365.0;#in days\nt4=(Q1/r)*365.0;#in days\n\n#result\nprint \"Ordering quantity in units : \",round(Q,3);\nprint \"Maximum Inventory in units : \",round(Q1);\nprint \"Maximum shortage quantity in units : \",round(Q2);\nprint \"Cycle time in days: \",round(t);\nprint \"Period of shortage in days : \",round(t1);\nprint \"Period of production satisfying back order in days : \",round(t2);\nprint \"Period of production satisfying period requirement in days : \",round(t3);\nprint \"Period of consumption only in days : \",round(t4);\n",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "Ordering quantity in units : 3046.0\nMaximum Inventory in units : 210.0\nMaximum shortage quantity in units : 1313.0\nCycle time in days: 93.0\nPeriod of shortage in days : 40.0\nPeriod of production satisfying back order in days : 40.0\nPeriod of production satisfying period requirement in days : 6.0\nPeriod of consumption only in days : 6.0\n"
}
],
"prompt_number": 8
}
],
"metadata": {}
}
]
}
|
