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{
"metadata": {
"name": "EE-9"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": "Depreciation"
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 9.1 Page 127"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nP=100000.0;#in Rs\nF=20000.0;#in Rs\nn=8.0;#in years\neoy=[0,1,2,3,4,5,6,7,8]#end of year\nBt=100000;#book vakue\n\n#calcualtion\nDt=(P-F)/n;#in Rs.\n\n#result\nprint \"End of year Depreciation Book value\";\nfor i in range (8):\n B=Bt-i*Dt;\n print eoy[i],\" \",Dt,\" \", B,\" \";\n \n \n ",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "End of year Depreciation Book value\n0 10000.0 100000.0 \n1 10000.0 90000.0 \n2 10000.0 80000.0 \n3 10000.0 70000.0 \n4 10000.0 60000.0 \n5 10000.0 50000.0 \n6 10000.0 40000.0 \n7 10000.0 30000.0 \n"
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 9.2 Page 127"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nP=100000.0;#in Rs\nF=20000.0;#in Rs\nn=8.0;#in years\n\n#calculation\nD5=(P-F)/n;#in Rs.\nt=5;#in years\nBt=P-t*(P-F)/n;#in Rs\n\n#result\nprint \"D5 in Rs. : \",round(D5,3);\nprint \"(This is independent of the time period)\";\nprint \"B5 in Rs. : \",round(Bt,3);",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "D5 in Rs. : 10000.0\n(This is independent of the time period)\nB5 in Rs. : 50000.0\n"
}
],
"prompt_number": 8
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 9.3 Page 129"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nP=100000.0;#in Rs\nF=20000.0;#in Rs\nn=8.0;#in years\nk=0.2\neoy=[0,1,2,3,4,5,6,7,8]#end of year\nBt=[100000.0,0,0,0,0,0,0,0,0];#book vakue\nDt=[0.0,0,0,0,0,0,0,0,0];\n\n#result\nprint \"End of year Depreciation Book value\";\nprint \"0 0 100000\"\nfor i in xrange (1,9):\n Dt[i]=k*Bt[i-1];\n Bt[i]=Bt[i-1]-Dt[i];\n print eoy[i],\" \",Dt[i],\" \", Bt[i],\" \";",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "End of year Depreciation Book value\n0 0 100000\n1 20000.0 80000.0 \n2 16000.0 64000.0 \n3 12800.0 51200.0 \n4 10240.0 40960.0 \n5 8192.0 32768.0 \n6 6553.6 26214.4 \n7 5242.88 20971.52 \n8 4194.304 16777.216 \n"
}
],
"prompt_number": 22
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 9.4 Page 128"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nP=100000.0;#in Rs\nF=20000.0;#in Rs\nn=8.0;#in years\nk=0.2\nt=5.0;#in years\n\n#calculation\nDt=k*(1-k)**(t-1)*P;#in Rs.\nBt=((1-k)**t)*P;#in Rs.\n\n#result\nprint \"D5 in Rs. : \",round(Dt,3);\nprint \"B5 in Rs. : \",round(Bt,3);",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "D5 in Rs. : 8192.0\nB5 in Rs. : 32768.0\n"
}
],
"prompt_number": 23
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 9.5 Page 129"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nP=100000.0;#in Rs\nF=20000.0;#in Rs\nn=8.0;#in years\nSum=n*(n+1)/2;#sum of the years\neoy=[0,1,2,3,4,5,6,7,8]#end of year\nBt=[100000.0,0,0,0,0,0,0,0,0];#book vakue\nDt=[0.0,0,0,0,0,0,0,0,0];\nrate=[0.0,0,0,0,0,0,0,0,0];\n\n#result\nprint \"End of year Depreciation Book value\";\nprint \"0 0 100000\"\nfor i in xrange (1,9):\n rate[i]=(8-i+1)/36.0;\n Dt[i]=rate[i]*(P-F);\n Bt[i]=Bt[i-1]-Dt[i];\n print eoy[i],\" \",Dt[i],\" \", Bt[i],\" \";",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "End of year Depreciation Book value\n0 0 100000\n1 17777.7777778 82222.2222222 \n2 15555.5555556 66666.6666667 \n3 13333.3333333 53333.3333333 \n4 11111.1111111 42222.2222222 \n5 8888.88888889 33333.3333333 \n6 6666.66666667 26666.6666667 \n7 4444.44444444 22222.2222222 \n8 2222.22222222 20000.0 \n"
}
],
"prompt_number": 25
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 9.6 Page 131"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nP=100000.0;#in Rs\nF=20000.0;#in Rs\nn=8.0;#in years\nt=5.0;#in years\n\n#cacualtion\nDt=(n-t+1)*(P-F)/(n*(n+1)/2);#in Rs.\nBt=(P-F)*((n-t)/n)*((n-t+1)/(n+1))+F;#in Rs.\n\n#result\nprint \"D5 in Rs. : \",round(Dt,3);\nprint \"B5 in Rs. : \",round(Bt,3);",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "D5 in Rs. : 8888.889\nB5 in Rs. : 33333.333\n"
}
],
"prompt_number": 26
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 9.7 Page 132"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nP=100000.0;#in Rs\nF=20000.0;#in Rs\nn=8.0;#in years\nk=0.12;\ni=12.0;#in % per annum\neoy=[0,1,2,3,4,5,6,7,8]#end of year\nBt=[100000.0,0,0,0,0,0,0,0,0];#book vakue\nDt=[0.0,0,0,0,0,0,0,0,0];\nrate=[0.0,0,0,0,0,0,0,0,0];\nSUM=0;\n\n#calculation\nA=(P-F)*(i/100)/(((1+i/100)**n)-1);\n\n#result\nprint \"End of year Net Depreciation Book value\";\nprint \"0 0 100000\"\nfor i in xrange (1,9):\n Dt[i]=k*SUM+A;\n SUM=SUM+Dt[i]\n Bt[i]=Bt[i-1]-Dt[i];\n print eoy[i],\" \",round(Dt[i],3),\" \", round(Bt[i],3),\" \";\n \nprint \"fixed deprececiation which is constant in Rs\",round(A,3);",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "End of year Net Depreciation Book value\n0 0 100000\n1 6504.227 93495.773 \n2 7284.735 86211.038 \n3 8158.903 78052.135 \n4 9137.971 68914.164 \n5 10234.528 58679.637 \n6 11462.671 47216.966 \n7 12838.191 34378.774 \n8 14378.774 20000.0 \nfixed deprececiation which is constant in Rs 6504.227\n"
}
],
"prompt_number": 30
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 9.8 Page 133"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nP=100000.0;#in Rs\nF=20000.0;#in Rs\nn=8.0;#in years\ni=12.0;#in % per annum\nt=5.0;#in Years\n\n#calculation\nDt=(P-F)*(i/100)/(((1+i/100)**n)-1)*(1+i/100)**(t-1);#in Rs.\nt=7;#in Years\nBt=P-(P-F)*(i/100)/(((1+i/100)**n)-1)*(((1+i/100)**t)-1)/(i/100);#in Rs.\n\n#result\nprint \"D7 in Rs. : \",round(Dt,3);\nprint \"B7 in Rs. : \",round(Bt,3);",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "D7 in Rs. : 10234.528\nB7 in Rs. : 34378.774\n"
}
],
"prompt_number": 31
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 9.9 Page 134"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nP=8000000.0;#in Rs\nF=50000.0;#in Rs\nX=75000.0;#in Km\nx=2000.0;#in Km\nn=8.0;#in years\ni=12.0;#in % per annum\n\n#calcualtion\nD=(P-F)*x/X;#in Rs.\n\n#result\nprint \"Depreciation for year 3 in Rs. : \",round(D,3);",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "Depreciation for year 3 in Rs. : 212000.0\n"
}
],
"prompt_number": 32
}
],
"metadata": {}
}
]
}
|
