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"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 3: Tem"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Exa 3.1"
]
},
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"cell_type": "code",
"execution_count": 1,
"metadata": {
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"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"T (F) = 26.60\n",
" \n",
" T (C) = 87.96\n",
" \n",
" T (K) = 361.11\n",
"press enter key to exit\n"
]
},
{
"data": {
"text/plain": [
"''"
]
},
"execution_count": 1,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"#Make the following conversions : (a) -3 C to F (b) 650 R to C (c) 650 R to K\n",
"#initialisation of variables\n",
"T1= -3 \t\t\t\t\t#degrees\n",
"T2= 650. \t\t\t\t#Rankine\n",
"T3= 650. \t\t\t\t#Rankine\n",
"#CALCULATIONS\n",
"t1= (9./5.)*T1+32 \t\t#In F\n",
"t2= T2-459.67 \t\t\t#In F\n",
"t21= (5./9.)*(t2-32) \t#In C\n",
"t3= t21+273.15 \t\t\t#In K\n",
"#RESULTS\n",
"print '%s %.2f' % ('T (F) = ',t1)\n",
"print '%s %.2f' % (' \\n T (C) = ',t21)\n",
"print '%s %.2f' % (' \\n T (K) = ',t3)\n",
"raw_input('press enter key to exit')"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Exa 3.2"
]
},
{
"cell_type": "code",
"execution_count": 2,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"T (F) = 18.00\n",
" \n",
" T (R) = 18.00\n",
"press enter key to exit\n"
]
},
{
"data": {
"text/plain": [
"''"
]
},
"execution_count": 2,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"#The temperatuer of an object drops from 40 to 30C. Determine the temperature\n",
"#drop in (a) F and (b) R.\n",
"#initialisation of variables\n",
"T1= 40. \t\t\t\t#degrees\n",
"T2= 30. \t\t\t\t#degrees\n",
"#CALCULATIONS\n",
"d1= (T1-T2)*(9./5.) \t#drop in F\n",
"d2= d1 \t\t\t\t\t#drop in R\n",
"#RESULTS\n",
"print '%s %.2f' % ('T (F) = ',d1)\n",
"print '%s %.2f' % (' \\n T (R) = ',d2)\n",
"raw_input('press enter key to exit')"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Exa 3.3"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"L (mm) = 400.54\n",
"press enter key to exit\n"
]
},
{
"data": {
"text/plain": [
"''"
]
},
"execution_count": 3,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"#A brass wire has a length of 400mm at 20C. What is the length of the wire at 90C?\t\n",
"#initialisation of variables\n",
"l= 400 \t\t\t\t\t#mm\n",
"t1= 20 \t\t\t\t\t#degrees\n",
"t2= 90 \t\t\t\t\t#degrees\n",
"alpha= 19.3/1000000. \t#degrees^-1\n",
"#CALCULATIONS\n",
"L= alpha*(t2-t1)*l \t\t#Change in Length\n",
"L1= L+l \t\t\t\t#Final Length\n",
"#RESULTS\n",
"print '%s %.2f' % ('L (mm) = ',L1)\n",
"raw_input('press enter key to exit')"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Exa 3.4"
]
},
{
"cell_type": "code",
"execution_count": 4,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"diameter at -15 (in) = 2.98\n",
"press enter key to exit\n"
]
},
{
"data": {
"text/plain": [
"''"
]
},
"execution_count": 4,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"#An Al 2024-T3 plate has a 2.980-in diameter hole at 69F. What is the \n",
"#diameter if the temperature is lowered to -15F?\n",
"import math\n",
"#initialisation of variables\n",
"d= 2.98 \t\t\t\t\t#in\n",
"T1= 69 \t\t\t\t\t\t#F\n",
"T2= -15 \t\t\t\t\t#F\n",
"alpha= 22.7/1000000. \t\t#C^-1\n",
"#CALCULATIONS\n",
"A0= math.pi*d*d/4. \t\t\t#Initial Area\n",
"alpha1= alpha/1.8 \n",
"A= 2*alpha1*A0*(T1-T2) \t#Change in Area\n",
"A1= A0-A \n",
"d1= math.sqrt(4*A1/math.pi) #diameter at -15F\n",
"#RESULTS\n",
"print '%s %.2f' % ('diameter at -15 (in) = ',d1)\n",
"raw_input('press enter key to exit')"
]
}
],
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