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{
"metadata": {
"name": "",
"signature": "sha256:e3ffdae85ed1c10a54629e535e9e044264a512de563ad3fb48c98b93c4a65432"
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 2 - Fundamental Concepts"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1 - Pg 18"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the potential energy\n",
"#Initialization of variables\n",
"z=100 #ft\n",
"m=32.1739 #lbm\n",
"#calculations\n",
"PE=m*z\n",
"#results\n",
"print '%s %.2f %s' %(\"Potential energy =\",PE,\"ft-lbm\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Potential energy = 3217.39 ft-lbm\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2 - Pg 21"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the absolute energy of this mixture and the change in mass\n",
"#Initialization of variables\n",
"m0=18.016 #lbm\n",
"gc=32.1739 #lbm ft/lbf sec^2\n",
"c=186000*5280\n",
"dU=94.4*10**6 #ft-lbf\n",
"#calculations\n",
"U=m0/gc *c**2\n",
"dm= -dU*gc/c**2\n",
"#results\n",
"print '%s %.2e %s' %(\"Absolute energy of this mixture =\",U,\" ft-lbf\")\n",
"print '%s' %(\"\\n In case b, there is no change in mass\")\n",
"print '%s %.2e %s' %(\"\\n Change in mass =\",dm,\" lbm\")\n",
"print '%s' %(\"The answers are a bit different due to rounding off error in textbook.\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Absolute energy of this mixture = 5.40e+17 ft-lbf\n",
"\n",
" In case b, there is no change in mass\n",
"\n",
" Change in mass = -3.15e-09 lbm\n",
"The answers are a bit different due to rounding off error in textbook.\n"
]
}
],
"prompt_number": 2
}
],
"metadata": {}
}
]
}
|
