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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 0 - Introduction"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example E1 - Pg 4"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the final pressure of the gas\n",
"#Initialization of variables\n",
"P=1.115 #bar\n",
"#Calculations\n",
"Conv_fac=1/1.01325\n",
"FinalP=Conv_fac*P #Final pressure\n",
"#Results\n",
"print '%s %.3f' %('Final pressure in atmospheres (atm)= ',FinalP)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Final pressure in atmospheres (atm)= 1.100\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example I1 - Pg 5"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the pressure at the foot of the column\n",
"#Initialization of variables\n",
"h=0.760 #m\n",
"d=1.36*10000 #kg/m^3\n",
"#Calculations\n",
"P=9.81*d*h\n",
"#Results\n",
"print '%s %.3e' %('Pressure at the foot of the column (Pa)= ',P)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Pressure at the foot of the column (Pa)= 1.014e+05\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example I2 - Pg 6"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the hydrostatic pressure and pressure in apparatus\n",
"#Initialization of variables\n",
"h=0.1 #m\n",
"d=1000 #Kg/m^3\n",
"Patm=100021. #Pa\n",
"#Calculations\n",
"P=9.81*h*d\n",
"Papp=(Patm-P)/1000.\n",
"#Results\n",
"print '%s %.3f' %('Hydrostatic pressure(Pa) = ',P )\n",
"print '%s %.3f' %('\\n Pressure in apparatus(kPa) = ',Papp)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Hydrostatic pressure(Pa) = 981.000\n",
"\n",
" Pressure in apparatus(kPa) = 99.040\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example I3 - Pg 8"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the no.of moles of copper required\n",
"import math\n",
"#Initialization of variables\n",
"N=8.8*math.pow(10,22)\n",
"NA=6.023*math.pow(10,23) #mol^-1\n",
"#Calculations\n",
"n=N/NA\n",
"#Results\n",
"print '%s %.2f' %('No. of moles of Cu ( mol Cu)= ',n)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"No. of moles of Cu ( mol Cu)= 0.15\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example I4 - Pg 9"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the amount of Carbon atoms \n",
"#Initialization of variables\n",
"m=21.5 #g\n",
"Mc=12.01 #g/mol\n",
"#Calculations\n",
"nc=m/Mc\n",
"#Results\n",
"print '%s %.2f %s' %(\"Amount of C atoms=\",nc,\"mol C\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Amount of C atoms= 1.79 mol C\n"
]
}
],
"prompt_number": 5
}
],
"metadata": {}
}
]
}
|
