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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 2 - Thermodynamics : The first law"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example I1 - Pg 46"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the change in temperature\n",
"#Initialization of variables\n",
"Cpm=75 #J/k mol\n",
"n=5.55 #mol\n",
"q=1 #kJ\n",
"#Calculations\n",
"deltaT=q*1000/(n*Cpm)\n",
"#results\n",
"print '%s %.1f %s' %('Change in temperature =',deltaT,'K')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Change in temperature = 2.4 K\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example I4 - Pg 52"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the change in enthalpy of the sample\n",
"#Initialization of variables\n",
"n=5.55 #mol\n",
"T1=20 #C\n",
"T2=80 #K\n",
"Cpm=75.29 #J/K mol\n",
"#Calculations\n",
"H=n*Cpm*(T2-T1)/1000.\n",
"#results\n",
"print '%s %d %s' %('Enthalpy of the sample changes by',H,'kJ')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Enthalpy of the sample changes by 25 kJ\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example E1 - Pg 45"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the heat supplied, heat capacity and heat output of the calorimeter\n",
"#Initialization of variables\n",
"A=1.23 #A\n",
"V=12 #V\n",
"t=123 #s\n",
"Temp=4.47 #C\n",
"rise=3.22 #C\n",
"#Calculations\n",
"q=A*V*t\n",
"C=q/Temp\n",
"Output= C*rise/1000.\n",
"#Results\n",
"print '%s %.1f %s' %('heat supplied during calibration =',q,'J')\n",
"print '%s %.1f %s' %('\\n Heat capacity of the calorimeter =',C,'J/C')\n",
"print '%s %.2f %s' %('\\n Heat output =',Output,' kJ')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"heat supplied during calibration = 1815.5 J\n",
"\n",
" Heat capacity of the calorimeter = 406.1 J/C\n",
"\n",
" Heat output = 1.31 kJ\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example E2 - Pg 48"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the amount by which the person's internal energy falls\n",
"#Initialization of variables\n",
"work=-622 #kJ\n",
"heat=-82 #kJ\n",
"#Calculations\n",
"U=work+heat\n",
"#results\n",
"print '%s %d %s' %('The persons internal energy falls by',-U,'kJ')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The persons internal energy falls by 704 kJ\n"
]
}
],
"prompt_number": 2
}
],
"metadata": {}
}
]
}
|
