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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
" Chapter 1 - The properties of gases"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example E1 - Pg 17"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the pressure in the glass flask\n",
"#Initialzation of variables\n",
"m=1.25 #g\n",
"MN2=28.02 #g/mol\n",
"T=20+273.15 #K\n",
"V=0.25#L\n",
"#Calculations\n",
"P=m*8.31451*T/(MN2*V)\n",
"#Results\n",
"print '%s %.1f %s' %('Pressure in the gas flask = ',P,'kPa')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Pressure in the gas flask = 434.9 kPa\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example I2 - Pg 19"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the partial pressures of Oxygen, Nitrogen and Argon\n",
"#Initialzation of variables\n",
"xN2=0.780\n",
"xO2=0.210\n",
"xAr=0.009\n",
"P=100 #kPa\n",
"#Calculations\n",
"PN2=xN2*P\n",
"PO2=xO2*P\n",
"PAr=xAr*P\n",
"#Results\n",
"print '%s %.1f' %('Partial pressure of Nitrogen(kPa) = ',PN2)\n",
"print '%s %.1f' %('\\n Partial pressure of Oxygen(kPa) = ',PO2)\n",
"print '%s %.1f' %('\\n Partial pressure of Argon(kPa) = ',PAr)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Partial pressure of Nitrogen(kPa) = 78.0\n",
"\n",
" Partial pressure of Oxygen(kPa) = 21.0\n",
"\n",
" Partial pressure of Argon(kPa) = 0.9\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example I3 - Pg 22"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the percentage loss of speed of air molecules\n",
"#Initialzation of variables\n",
"import math\n",
"T1=298. #K\n",
"T2=273. #K\n",
"#Calculations\n",
"factor=math.sqrt(T2/T1)\n",
"percentage=(1-factor)*100\n",
"#Results\n",
"print '%s %.3f' %('Factor by which speed is reduced = ',factor)\n",
"print '%s %d' %('Percentage loss of speed of air molecules = ',percentage)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Factor by which speed is reduced = 0.957\n",
"Percentage loss of speed of air molecules = 4\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example I4 - Pg 24"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the ratio of rates of effusion\n",
"#Initialzation of variables\n",
"import math\n",
"MH2=2.016 #g/mol\n",
"MCO2=44.01 #g/mol\n",
"#calculations\n",
"ratio=math.sqrt(MCO2/MH2)\n",
"#results\n",
"print '%s %.3f' %('ratio of rates of effusion = ',ratio)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"ratio of rates of effusion = 4.672\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example I5 - Pg 25"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the mean free path and collision frequency\n",
"#Initialzation of variables\n",
"import math\n",
"T=25+273. #K\n",
"sigma=0.4*math.pow(10,(-18)) #m^2\n",
"P=math.pow(10,5) #Pa\n",
"c=481.8 #m/sec\n",
"#Calculations\n",
"Lambda=8.31451*T/(math.pow(2,0.5) *6.022*math.pow(10,23) *sigma*P)\n",
"frequency=math.pow(2,0.5) *6.022*math.pow(10,23) *sigma*P*c/(8.31451*T)\n",
"#Results\n",
"print '%s %.1e %s' %('Mean free path =',Lambda,'m')\n",
"print '%s %.1e %s' %('\\n Collision frequency =',frequency,'m')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Mean free path = 7.3e-08 m\n",
"\n",
" Collision frequency = 6.6e+09 m\n"
]
}
],
"prompt_number": 7
}
],
"metadata": {}
}
]
}
|
