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{
"metadata": {
"name": "",
"signature": "sha256:9ece3b9f8730ff4f15d623a124d9415b373cdc935ed6cb089360bef5516a2604"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
" Chapter 11: Cathode Ray Oscilloscope"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 11.2,Page number 532"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"E=120 #electric field(V/m) \n",
"B=5*10**-5 #magnetic field(T) \n",
"q=1.6*10**-19 #charge on electron(C)\n",
"u=10**6 #velocity of electron(m/s)\n",
"m=9.1*10**-31 #mass of electron(Kg) \n",
"a=9.81 #acceleration of gravitation(m/s^2)\n",
"\n",
"#Calculations\n",
"#Part a\n",
"fe=q*E #force on electron due to electric field(N)\n",
"\n",
"#Part\n",
"fm=B*q*u #force on electron due to magnetic field(N)\n",
"\n",
"#Part c\n",
"fg=m*a #force on electron due to gravitational field(N)\n",
"\n",
"#Results\n",
"print\"force on electron due to electric field is\",fe,\"N\"\n",
"print\"force on electron due to magnetic field is\",fm,\"N\"\n",
"print\"force on electron due to gravitational field is\",fg,\"N\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"force on electron due to electric field is 1.92e-17 N\n",
"force on electron due to magnetic field is 8e-18 N\n",
"force on electron due to gravitational field is 8.9271e-30 N\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 11.3,Page number 532"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Variable declaration\n",
"T1=1200. #temperature(k)\n",
"T2=1000. #temperature(k)\n",
"Ww=1.2*10**5 #work function(eV)\n",
"k=8.62\n",
"Ie1=200 #emission current density\n",
"T3=1500. #temperature(k)\n",
"\n",
"#Calculations\n",
"Ie2=Ie1*(T2/T1)**2*math.exp(-(Ww/k)*((1/T2)-(1/T1))) #current density(mA/cm^2) at 1000k\n",
"Ie3=Ie1*(T3/T1)**2*math.exp(-(Ww/k)*((1/T3)-(1/T1))) #current density(mA/cm^2) at 1000k\n",
"\n",
"#Results\n",
"print\"current density at 1000 k is\",round(Ie2,2),\"mA/cm^2\"\n",
"print\"current density at 1500 k is\",round(Ie3,2),\"mA/cm^2\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"current density at 1000 k is 13.65 mA/cm^2\n",
"current density at 1500 k is 3180.49 mA/cm^2\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 11.4,Page number 533"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Variable declaration\n",
"Ls=40 #distance from screen(m)\n",
"d=1.5 #distance between plates(cm)\n",
"Va=1200 #accelerating potential(V) \n",
"L=3 #length of CRT(m)\n",
"e=1.6*10**-19 #charge on electron(C)\n",
"m=9.1*10**-31 #mass of electron(Kg) \n",
"Y=4*10**-2 #vertical deflection(V)\n",
"\n",
"#Calculations\n",
"#Part a\n",
"U=math.sqrt((2*e*Va)/m) #velocity of electron upon striking screen(m/s)\n",
"\n",
"#Part\n",
"Vd=(2*d*Va*Y)/(L*Ls) #deflecting voltage(V)\n",
"\n",
"#Part c\n",
"Vdmax=(m*d**2*U**2)/(e*L**2) #maximum allowable deflection(V)\n",
"\n",
"#Results\n",
"print\"velocity of electron upon stricking the screen is\",round((U/1E+7),3),\"*10^7 m/s\"\n",
"print\"deflecting voltage is\",round(Vd/1E-2),\"V\"\n",
"print\"maximum allowable deflection is\",Vdmax,\"V\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"velocity of electron upon stricking the screen is 2.054 *10^7 m/s\n",
"deflecting voltage is 120.0 V\n",
"maximum allowable deflection is 600.0 V\n"
]
}
],
"prompt_number": 1
}
],
"metadata": {}
}
]
}
|
