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"# Chapter 13 - Non-linear Analog Systems"
]
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"source": [
"## Example 13_1 Page No. 395"
]
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"text": [
"VT= 0.03 volts\n",
"R1= 5000.00 ohm\n",
" Iso = 1.00e-10 ampere\n",
"part(i)\n",
"vs= 1.00e-03 volts\n",
"vo=-VT*(log(vs/(Iso*R1)))= -0.20 volts\n",
"part(ii)\n",
"vs= 1.00e-02 volts\n",
"vo=-VT*(log(vs/(Iso*R1)))= -0.26 volts\n",
"part(iii)\n",
"vs= 0.10 volts\n",
"vo=-VT*(log(vs/(Iso*R1)))= -0.32 volts\n",
"part(iv)\n",
"vs= 1.00 volts\n",
"vo=-VT*(log(vs/(Iso*R1)))= -0.38 volts\n"
]
}
],
"source": [
"from math import log\n",
"from __future__ import division \n",
"VT=26*10**(-3)\n",
"print \"VT= %0.2f\"%(VT),\" volts\" # Thermal voltage \n",
"R1=5*10**(3)\n",
"print \"R1= %0.2f\"%(R1),\" ohm\" # resistance\n",
"Iso=1*10**(-10)\n",
"print \" Iso = %0.2e\"%(Iso),\" ampere\" # Scale factor (as current)directly proportional to cross-section area of EBJ \n",
"\n",
"print \"part(i)\"\n",
"vs=1*10**(-3)\n",
"print \"vs= %0.2e\"%(vs),\" volts\" # Input voltage1\n",
"vo=-VT*(log(vs/(Iso*R1)))\n",
"print \"vo=-VT*(log(vs/(Iso*R1)))= %0.2f\"%(vo),\" volts\" # Output voltage of Log OP-AMP for input1 i.e vs = 1 mV\n",
"\n",
"print \"part(ii)\"\n",
"vs=10*10**(-3)\n",
"print \"vs= %0.2e\"%(vs),\" volts\" # Input voltage2\n",
"vo=-VT*(log(vs/(Iso*R1)))\n",
"print \"vo=-VT*(log(vs/(Iso*R1)))= %0.2f\"%(vo),\" volts\" # Output voltage of Log OP-AMP for input1 i.e vs = 10 mV\n",
"\n",
"print \"part(iii)\"\n",
"vs=100*10**(-3)\n",
"print \"vs= %0.2f\"%(vs),\" volts\" # Input voltage3\n",
"vo=-VT*(log(vs/(Iso*R1)))\n",
"print \"vo=-VT*(log(vs/(Iso*R1)))= %0.2f\"%(vo),\" volts\" # Output voltage of Log OP-AMP for input1 i.e vs = 100 mV\n",
"\n",
"print \"part(iv)\"\n",
"vs=1\n",
"print \"vs= %0.2f\"%(vs),\" volts\" # Input voltage4\n",
"vo=-VT*(log(vs/(Iso*R1)))\n",
"print \"vo=-VT*(log(vs/(Iso*R1)))= %0.2f\"%(vo),\" volts\" # Output voltage of Log OP-AMP for input1 i.e vs = 1V"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 13_2 Page No. 396"
]
},
{
"cell_type": "code",
"execution_count": 4,
"metadata": {
"collapsed": false
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{
"name": "stdout",
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"text": [
"VT= 0.03 volts\n",
"R1= 100000.00 ohm\n",
" Iso = 5.00e-08 ampere\n",
"vs= 2.50 volts\n",
"vo=-VT*(log(vs/(Iso*R1)))= -0.16 volts\n"
]
}
],
"source": [
"from math import log\n",
"from __future__ import division \n",
"VT=26*10**(-3)\n",
"print \"VT= %0.2f\"%(VT),\" volts\" # Thermal voltage \n",
"R1=100*10**(3)\n",
"print \"R1= %0.2f\"%(R1),\" ohm\" # resistance\n",
"Iso=50*10**(-9)\n",
"print \" Iso = %0.2e\"%(Iso),\" ampere\" # Scale factor (as current)directly proportional to cross-section area of EBJ \n",
"vs=2.5\n",
"print \"vs= %0.2f\"%(vs),\" volts\" # Input voltage\n",
"vo=-VT*(log(vs/(Iso*R1)))\n",
"print \"vo=-VT*(log(vs/(Iso*R1)))= %0.2f\"%(vo),\" volts\" # Output voltage of Log OP-AMP for input1 i.e vs = 2.5 V"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 13_3 Page No. 397"
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"VT= 0.03 volts\n",
"RF= 1.00e+05 ohm\n",
" Iso = 5.00e-08 ampere\n",
"vs= -0.16 volts\n",
"vo=Iso*RF*(exp(-vs/VT))= 2.54 volts\n"
]
}
],
"source": [
"from math import exp\n",
"from __future__ import division \n",
"VT=26*10**(-3)\n",
"print \"VT= %0.2f\"%(VT),\" volts\" # Thermal voltage \n",
"RF=100*10**(3)\n",
"print \"RF= %0.2e\"%(RF),\" ohm\" # resistance\n",
"Iso=50*10**(-9)\n",
"print \" Iso = %0.2e\"%(Iso),\" ampere\" # Scale factor (as current)directly proportional to cross-section area of EBJ \n",
"vs=-0.162\n",
"print \"vs= %0.2f\"%(vs),\" volts\" # Input voltage\n",
"vo=Iso*RF*(exp(-vs/VT))\n",
"print \"vo=Iso*RF*(exp(-vs/VT))= %0.2f\"%(vo),\" volts\" # Output voltage of Antilog OP-AMP for input1 i.e vs = -0.162 V"
]
}
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