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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"CHAPTER 8 TRANSISTOR BIASING"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8-1, Page 263"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Example 8.1.py\n",
"#What is the collector-emitter voltage in Figure 8-2? \n",
"\n",
"#Variable declaration\n",
"VCC=10 #collector voltage(V)\n",
"RC=3.6 #Collector resistance (KOhm)\n",
"RE=1 #Emitter resistance (KOhm)\n",
"R1=10 #Base resistance1 (KOhm)\n",
"R2=2.2 #Base resistance2 (KOhm)\n",
"VBE=0.7 #Base-emitter voltage drop(V)\n",
"\n",
"#Calculation\n",
"VBB=(R2/(R1+R2))*VCC #Base voltage(V)\n",
"VE=VBB-VBE #Emitter voltage(V)\n",
"IE=VE/RE #Emitter current(mA)\n",
"IC=IE #Collector current(mA)\n",
"VC=VCC-(IC*RC) #collector to ground voltage(V)\n",
"VCE=VC-VE #Collector-emitter voltage(V)\n",
"\n",
"#Result\n",
"print 'Collector current IC = ',round(IC,2),'mA'\n",
"print 'Collector-emitter voltage VCE = ',round(VCE,2),'V'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Collector current IC = 1.1 mA\n",
"Collector-emitter voltage VCE = 4.92 V\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8-3, Page 267"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Example 8.3.py\n",
"#Is the voltage divider of figure 8-5 stiff? Calculate emitter current.\n",
"\n",
"#Variable declaration\n",
"VCC=10 #collector voltage(V)\n",
"RC=3.6 #Collector resistance (KOhm)\n",
"RE=1 #Emitter resistance (KOhm)\n",
"R1=10 #Base resistance1 (KOhm)\n",
"R2=2.2 #Base resistance2 (KOhm)\n",
"VBE=0.7 #Base-emitter voltage drop(V)\n",
"Bdc=200 #current gain\n",
"\n",
"#Calculation\n",
"R=(R1*R2)/(R1+R2) #Thevenin resistance(KOhm)\n",
"Ri=Bdc*RE #Base input resistance(KOhm)\n",
"R100=0.01*Ri #100th of Ri(KOhm)\n",
"VBB=(R2/(R1+R2))*VCC #Base voltage(V)\n",
"VE=VBB-VBE #Emitter voltage(V)\n",
"IE=VE/(RE+(R/Ri)) #Emitter current(mA)\n",
"\n",
"#Result\n",
"print 'As per stiff voltage divider rule, R1||R2 < 0.01 Bdc*RE, So, Voltage divider is stiff.'\n",
"print 'Emitter current IE = ',round(IE,2),'mA'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"As per stiff voltage divider rule, R1||R2 < 0.01 Bdc*RE, So, Voltage divider is stiff.\n",
"Emitter current IE = 1.09 mA\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8-4, Page 269"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Example 8.4.py\n",
"#For the circuit shown in figure 8-7, design resistor values.\n",
"#VCC=10 V, VCE @ mid point, IC=10mA, 2N3904's Bdc=100-300.\n",
"\n",
"#Variable declaration\n",
"VCC=10 #collector voltage(V)\n",
"IC=10 #Collector current(mA)\n",
"VBE=0.7 #Base-emitter voltage drop(V)\n",
"Bdc=100 #current gain\n",
"\n",
"#Calculation\n",
"IE=IC #Emitter current(mA)\n",
"VE=0.1*VCC #Emitter voltage(V)\n",
"RE=(VE/IE)*1000 #Emitter resistance (Ohm)\n",
"RC=4*RE #Collector resistance(Ohm)\n",
"R2=0.01*Bdc*RE #Base input resistance2(Ohm)\n",
"V2=VE+VBE #voltage across R1(V)\n",
"V1=VCC-V2 #voltage across R2(V)\n",
"R1=(V1/V2)*R2 #Base input resistance1(Ohm)\n",
"\n",
"#Result\n",
"print 'Emitter resistance RE = ',RE,'Ohm'\n",
"print 'Collector resistance RC = ',RC,'Ohm'\n",
"print 'Base resistance R1 = ',round(R1,2),'Ohm'\n",
"print 'Base resistance R2 = ',R2,'Ohm'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Emitter resistance RE = 100.0 Ohm\n",
"Collector resistance RC = 400.0 Ohm\n",
"Base resistance R1 = 488.24 Ohm\n",
"Base resistance R2 = 100.0 Ohm\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8-5, Page 271"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Example 8.5.py\n",
"#What is the collector voltage in Figure 8-10 if emitter resistor is increased to 1.8 KOhm? \n",
"\n",
"#Variable declaration\n",
"VCC=10 #collector voltage(V)\n",
"RC=3.6 #Collector resistance (KOhm)\n",
"RE=1.8 #Emitter resistance (KOhm)\n",
"RB=2.7 #Base resistance (KOhm)\n",
"VBE=0.7 #Base-emitter voltage drop(V)\n",
"VEE=2 #emitter voltage(V)\n",
"\n",
"#Calculation\n",
"VBB=0 #Base voltage(V)\n",
"VE=VEE-VBE #Emitter to ground voltage(V)\n",
"IE=VE/RE #Emitter current(mA)\n",
"IC=IE #Collector current(mA)\n",
"VC=VCC-(IC*RC) #collector to ground voltage(V)\n",
"\n",
"#Result\n",
"print 'Emitter current IE = ',round(IE,2),'mA'\n",
"print 'Collector voltage VC = ',VC,'V'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Emitter current IE = 0.72 mA\n",
"Collector voltage VC = 7.4 V\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8-6, Page 271"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Example 8.6.py\n",
"#Figure 8-11 shows 3 stage circuit using TSEB. Find VC.\n",
"\n",
"#Variable declaration\n",
"VCC=15 #collector voltage(V)\n",
"RC=10 #Collector resistance (KOhm)\n",
"RE=20 #Emitter resistance (KOhm)\n",
"VBE=0.7 #Base-emitter voltage drop(V)\n",
"VEE=15 #emitter voltage(V)\n",
"\n",
"#Calculation\n",
"VBB=0 #Base voltage(V)\n",
"VE=VEE-VBE #Emitter to ground voltage(V)\n",
"IE=VE/RE #Emitter current(mA)\n",
"IC=IE #Collector current(mA)\n",
"VC=VCC-(IC*RC) #collector to ground voltage(V)\n",
"\n",
"#Result\n",
"print 'Emitter current IE = ',IE,'mA'\n",
"print 'Collector voltage VC = ',VC,'V'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Emitter current IE = 0.715 mA\n",
"Collector voltage VC = 7.85 V\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8-7, Page 278"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Example 8.7.py\n",
"#Calculate the three transistor voltages for the PNP circuit of figure 8-19b?\n",
"\n",
"#Variable declaration\n",
"VCC=-10 #collector supply voltage(V)\n",
"VEE=-VCC #Emitter supply voltage(V)\n",
"RC=3.6 #Collector resistance (KOhm)\n",
"RE=1 #Emitter resistance (KOhm)\n",
"R1=10 #Base resistance1 (KOhm)\n",
"R2=2.2 #Base resistance2 (KOhm)\n",
"VBE=0.7 #Base-emitter voltage drop(V)\n",
"\n",
"#Calculation\n",
"V2=(R2/(R1+R2))*VEE #Base voltage(V)\n",
"IE=(V2-VBE)/RE #Emitter current(mA)\n",
"VC=IE*RC #collector to ground voltage(V)\n",
"VB=VEE-V2 #Base to ground voltage(V)\n",
"VE=VEE-(V2-VBE) #Emitter to ground voltage(V)\n",
"\n",
"#Result\n",
"print 'Emitter current IE = ',round(IE,2),'mA'\n",
"print 'Collector to ground voltage VC = ',round(VC,2),'V'\n",
"print 'Base to ground voltage VB = ',round(VB,2),'V'\n",
"print 'Emitter to ground voltage VE = ',round(VE,2),'V'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Emitter current IE = 1.1 mA\n",
"Collector to ground voltage VC = 3.97 V\n",
"Base to ground voltage VB = 8.2 V\n",
"Emitter to ground voltage VE = 8.9 V\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
