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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"CHAPTER 1 INTRODUCTION"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1-1, Page 9"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Rs=50 #source resistance(Ohm)\n",
"\n",
"RL=100*Rs/1000 #Minimum Load resistance(KOhm)\n",
"\n",
"print 'Minimum Load resistance =',RL,'KOhm'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Minimum Load resistance = 5 KOhm\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1-2, Page 12"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Is=0.002 #Current source(A)\n",
"Rs=10000000 #internal resistance(Ohm)\n",
"\n",
"Rl_Max=0.01*Rs/1000 #Maximum load resistance(KOhm)\n",
"\n",
"print 'With 100:1 Rule, Maximum Load resistance =',Rl_Max,'KOhm'\n",
"print 'Stiff range for current source is load resistance from 0 KOhm to',Rl_Max,'KOhm'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"With 100:1 Rule, Maximum Load resistance = 100.0 KOhm\n",
"Stiff range for current source is load resistance from 0 KOhm to 100.0 KOhm\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1-3, Page 13"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Il=0.002 #current source(A)\n",
"Rl=10000 #load resistance(Ohm)\n",
"\n",
"Vl=Il*Rl #load voltage(V)\n",
"\n",
"print 'Load Voltage =',Vl,'V'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Load Voltage = 20.0 V\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1-4, Page 14"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"print 'As per figure 1-9a, Calculate Thevenin resistor by opening load resistor'\n",
"\n",
"Vs=72 #source voltage\n",
"R1=6 #Resistance (KOhm)\n",
"R2=3 #Resistance (KOhm)\n",
"R3=4 #Resistance (KOhm)\n",
"\n",
"Ro=R1+R2 #Resistance (KOhm)\n",
"I=Vs/Ro\n",
"Vab=R2*Vs/(R1+R2) #Thevenin voltage(V)\n",
"Rth=((R1*R2)/(R1+R2))+R3 #Thevenin Resistance(KOhm)\n",
"\n",
"print 'After removing Rl current flowing through 6KOhm is',I,'mA'\n",
"print 'Thevenin Voltage Vth =',Vab,'V'\n",
"print 'Calculating Thevenin Resistance with considering R1 & R2 in parallel'\n",
"print 'Thevenin Resistance =',Rth,'KOhm'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"As per figure 1-9a, Calculate Thevenin resistor by opening load resistor\n",
"After removing Rl current flowing through 6KOhm is 8 mA\n",
"Thevenin Voltage Vth = 24 V\n",
"Calculating Thevenin Resistance with considering R1 & R2 in parallel\n",
"Thevenin Resistance = 6 KOhm\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1-5, Page 15"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Vs=72 #source voltage\n",
"R1=2 #resistance1 (KOhm)\n",
"R2=2 #resistance1 (KOhm)\n",
"R3=1 #resistance1 (KOhm)\n",
"R4=2 #resistance1 (KOhm)\n",
"R5=1 #resistance1 (KOhm)\n",
"R6=2 #resistance1 (KOhm)\n",
"R7=0.5 #resistance1 (KOhm)\n",
"RL=1 #load resistance (KOhm)\n",
"\n",
"Vth=9 #Thevenin voltage(V)\n",
"Rth=1.5 #Thevenin resistance(KOhm)\n",
"\n",
"print 'Thevenin Voltage Vth =',Vth,'V'\n",
"print 'Thevenin Resistance =',Rth,'KOhm'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Thevenin Voltage Vth = 9 V\n",
"Thevenin Resistance = 1.5 KOhm\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1-6, Page 19"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Vs=10 #source voltage\n",
"Rs=2 #series source resistance (KOhm)\n",
"\n",
"IN=Vs/Rs #Norton current(mA)\n",
"Rp=Rs #parallel source resistance(KOhm)\n",
"\n",
"print 'Norton current IN =',IN,'mA'\n",
"print 'Norton Resistance =',Rp,'KOhm'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Norton current IN = 5 mA\n",
"Norton Resistance = 2 KOhm\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
