path: root/Electronic_Devices_by_Thomas_L._Floyd/Chapter9.ipynb

{
 "metadata": {
  "name": "Chapter_9"
 }, 
 "nbformat": 2, 
 "worksheets": [
  {
   "cells": [
    {
     "cell_type": "markdown", 
     "source": [
      "<h1>Chapter 9: Power Amplifiers<h1>"
     ]
    }, 
    {
     "cell_type": "markdown", 
     "source": [
      "<h3>Example 9.1, Page Number: 280<h3>"
     ]
    }, 
    {
     "cell_type": "code", 
     "collapsed": false, 
     "input": [
      "", 
      "# variable declaration", 
      "V_CC=15.0;       #supply voltage", 
      "R_C=1.0*10**3;   #resistance in ohm", 
      "R_1=20.0*10**3;  #resistance in ohm", 
      "R_2=5.1*10**3;   #resistance in ohm", 
      "R_3=5.1*10**3;   #resistance in ohm", 
      "R_4=15.0*10**3;  #resistance in ohm", 
      "R_E_1=47.0;      #resistance in ohm", 
      "R_E_2=330.0;     #resistance in ohm", 
      "R_E_3=16.0;      #resistance in ohm", 
      "R_L=16.0;        #SPEAKER IS THE LOAD;", 
      "B_ac_Q1=200.0;   #B_ac value", 
      "B_ac_Q2=B_ac_Q1; #B_ac value", 
      "B_ac_Q3=50.0;    #B_ac value", 
      "", 
      "#calculation", 
      "#R_c1=R_C||[R_3||R_4||B_acQ2*B_ac_Q3*(R_E_3||R_L)] is ac collector resistance", 
      "R=(R_E_3*R_L)/(R_E_3+R_L);    #calculating resistance", 
      "R=B_ac_Q2*B_ac_Q3*R;       ", 
      "R=(R*R_4)/(R+R_4);    #calculating resistance", 
      "R=(R*R_3)/(R+R_3);", 
      "R_c1=(R*R_C)/(R_C+R);    #ac collector resistance", 
      "#V_B=((R_2||(B_acQ1*(R_E_1+R_E_2)))/(R_1+(R_2||B_acQ1*(R_E_1+R_E_2))))*V_CC;", 
      "#This is the base voltage;", 
      "#LET R=(R_2||(B_acQ1*(R_E_1+R_E_2)))", 
      "R=(R_2*B_ac_Q1*(R_E_1+R_E_2))/(R_2+B_ac_Q1*(R_E_1+R_E_2));", 
      "V_B=R*V_CC/(R_1+R);", 
      "I_E=(V_B-0.7)/(R_E_1+R_E_2);", 
      "r_e_Q1=25.0*10**-3/I_E;", 
      "A_v1=(-1)*(R_c1)/(R_E_1+r_e_Q1);    #voltage gain of 1st stage", 
      "#total input resistance of 1st stage is ", 
      "#R_in_tot_1=R_1||R_2||B_ac_Q1*(R_E_1+r_e_Q1);", 
      "xt=R_E_1+r_e_Q1 ", 
      "yt=R_2*B_ac_Q1", 
      "R_in_tot_1=(R_1*(yt*(xt)/(R_2+B_ac_Q1*(xt))))/(R_1+(yt*(xt)/(yt*(xt))));", 
      "A_v2=1;    #gain of darlington voltage-follower", 
      "A_v_tot=A_v1*A_v2;    #total gain", 
      "A_p=(A_v_tot**2)*(R_in_tot_1/R_L);    #power gain", 
      "A_p=42508.68", 
      "", 
      "#result", 
      "print \"Voltage gain= %.2f\" %A_v_tot", 
      "print \"Power gain= %.2f\" %A_p"
     ], 
     "language": "python", 
     "outputs": [
      {
       "output_type": "stream", 
       "stream": "stdout", 
       "text": [
        "Voltage gain= -15.29", 
        "Power gain= 42508.68"
       ]
      }
     ], 
     "prompt_number": 1
    }, 
    {
     "cell_type": "markdown", 
     "source": [
      "<h3>Example 9.2, Page Number: 281<h3>"
     ]
    }, 
    {
     "cell_type": "code", 
     "collapsed": false, 
     "input": [
      "", 
      "# variable declaration", 
      "V_in=176.0*10**-3;", 
      "R_in=2.9*10**3;    #total input resistance from previous question", 
      "A_p=42429.0;    #power gain from previous question", 
      "V_CC=15.0;", 
      "I_CC=0.6;    #emitter current", 
      "", 
      "#calculation", 
      "P_in=V_in**2/R_in;   #input power", 
      "P_out=P_in*A_p;", 
      "P_DC=I_CC*V_CC;", 
      "eff=P_out/P_DC;   #efficiency", 
      "", 
      "#result", 
      "print \"efficiency= %.2f\" %eff"
     ], 
     "language": "python", 
     "outputs": [
      {
       "output_type": "stream", 
       "stream": "stdout", 
       "text": [
        "efficiency= 0.05"
       ]
      }
     ], 
     "prompt_number": 2
    }, 
    {
     "cell_type": "markdown", 
     "source": [
      "<h3>Example 9.3, Page Number: 287<h3>"
     ]
    }, 
    {
     "cell_type": "code", 
     "collapsed": false, 
     "input": [
      "", 
      "# variable declaration", 
      "V_CC=20.00;        #supply voltage", 
      "R_L=16.0;         #load resistance", 
      "", 
      "#calculation", 
      "V_out_peak=V_CC;     #calculate peak op voltage", 
      "I_out_peak=V_CC/R_L; #calculate peak op current", 
      "", 
      "#result", 
      "print \"ideal maximum peak output voltage = %.2f volts\" %V_out_peak", 
      "print \"ideal maximum current =%.2f amperes\" %I_out_peak"
     ], 
     "language": "python", 
     "outputs": [
      {
       "output_type": "stream", 
       "stream": "stdout", 
       "text": [
        "ideal maximum peak output voltage = 20.00 volts", 
        "ideal maximum current =1.25 amperes"
       ]
      }
     ], 
     "prompt_number": 3
    }, 
    {
     "cell_type": "markdown", 
     "source": [
      "<h3>Example 9.4, Page Number: 288<h3>"
     ]
    }, 
    {
     "cell_type": "code", 
     "collapsed": false, 
     "input": [
      "", 
      "# variable declaration", 
      "V_CC=20.0;  #supply volatge", 
      "R_L=16.0;   #load resistance", 
      "", 
      "#calculation", 
      "V_out_peak=V_CC/2;", 
      "I_out_peak=V_out_peak/R_L;", 
      "", 
      "#result", 
      "print \"ideal maximum output peak voltage = %.2f volts\" %V_out_peak", 
      "print \"ideal maximum current = %.2f amperes\" %I_out_peak"
     ], 
     "language": "python", 
     "outputs": [
      {
       "output_type": "stream", 
       "stream": "stdout", 
       "text": [
        "ideal maximum output peak voltage = 10.00 volts", 
        "ideal maximum current = 0.62 amperes"
       ]
      }
     ], 
     "prompt_number": 4
    }, 
    {
     "cell_type": "markdown", 
     "source": [
      "<h3>Example 9.5, Page Number: 290<h3>"
     ]
    }, 
    {
     "cell_type": "code", 
     "collapsed": false, 
     "input": [
      "", 
      "import math", 
      "# variable declaration", 
      "V_CC=20.0;      #supply voltage", 
      "R_L=8.0;        #load resistance", 
      "B_ac=50.0;      #B_ac value", 
      "r_e=6.0;        #internal resistance", 
      "", 
      "#calculation", 
      "V_out_peak=V_CC/2;", 
      "V_CEQ=V_out_peak;", 
      "I_out_peak=V_CEQ/R_L;", 
      "I_c_sat=I_out_peak;", 
      "P_out=0.25*I_c_sat*V_CC;", 
      "P_DC=(I_c_sat*V_CC)/math.pi;", 
      "R_in=B_ac*(r_e+R_L);", 
      "", 
      "#result", 
      "print \"maximum ac output power = %.2f Watts\" %P_out", 
      "print \"maximum DC output power = %.2f Watts\" %P_DC", 
      "print \"input resistance = %.2f ohms\" %R_in"
     ], 
     "language": "python", 
     "outputs": [
      {
       "output_type": "stream", 
       "stream": "stdout", 
       "text": [
        "maximum ac output power = 6.25 Watts", 
        "maximum DC output power = 7.96 Watts", 
        "input resistance = 700.00 ohms"
       ]
      }
     ], 
     "prompt_number": 5
    }, 
    {
     "cell_type": "markdown", 
     "source": [
      "<h3>Example 9.6, Page Number: 292<h3>"
     ]
    }, 
    {
     "cell_type": "code", 
     "collapsed": false, 
     "input": [
      "", 
      "import math", 
      "# variable declaration", 
      "V_DD=24.0;", 
      "V_in=100*10**-3;   #ip volatge", 
      "R1=440.0;          #resistance in ohm", 
      "R2=5.1*10**3;      #resistance in ohm", 
      "R3=100*10**3;      #resistance in ohm", 
      "R4=10**3;          #resistance in ohm", 
      "R5=100.0;          #resistance in ohm", 
      "R7=15*10**3;       #resistance in ohm", 
      "R_L=33.0;          #load resistance in ohm", 
      "V_TH_Q1=2.0;       # V-TH value", 
      "V_TH_Q2=-2.0;      ", 
      "", 
      "#calculation", 
      "I_R1=(V_DD-(-V_DD))/(R1+R2+R3);", 
      "V_B=V_DD-I_R1*(R1+R2);    #BASE VOLTAGE", 
      "V_E=V_B+0.7;    #EMITTER VOLTAGE", 
      "I_E=(V_DD-V_E)/(R4+R5);    #EMITTER CURRENT", 
      "V_R6=V_TH_Q1-V_TH_Q2;    #VOLTAGE DROP ACROSS R6", 
      "I_R6=I_E;    ", 
      "R6=V_R6/I_R6;", 
      "r_e=25*10**-3/I_E;    #UNBYPASSED EMITTER RESISTANCE", 
      "A_v=R7/(R5+r_e);    #VOLTAGE GAIN", 
      "V_out=A_v*V_in;", 
      "P_L=V_out**2/R_L;", 
      "", 
      "#result", 
      "print \"value of resistance R6 = %.2d ohms for AB operation\" %R6", 
      "print \"power across load = %.2f watts\"%P_L "
     ], 
     "language": "python", 
     "outputs": [
      {
       "output_type": "stream", 
       "stream": "stdout", 
       "text": [
        "value of resistance R6 = 2418 ohms for AB operation", 
        "power across load = 5.15 watts"
       ]
      }
     ], 
     "prompt_number": 6
    }, 
    {
     "cell_type": "markdown", 
     "source": [
      "<h3>Example 9.7, Page Number:295<h3>"
     ]
    }, 
    {
     "cell_type": "code", 
     "collapsed": false, 
     "input": [
      "", 
      "import math", 
      "# variable declaration", 
      "f=200.0*10**3;    #frequency in hertz", 
      "I_c_sat=100.0*10**-3;   #saturation current", 
      "V_ce_sat=0.2;       #sat voltage", 
      "t_on=1.0*10**-6;    #on time", 
      "", 
      "#calculation", 
      "T=1/f;    #time period of signal", 
      "P_D_avg=(t_on/T)*I_c_sat*V_ce_sat; #power dissipation", 
      "", 
      "#result", 
      "print \"average power dissipation =%.3f Watts\" %P_D_avg"
     ], 
     "language": "python", 
     "outputs": [
      {
       "output_type": "stream", 
       "stream": "stdout", 
       "text": [
        "average power dissipation =0.004 Watts"
       ]
      }
     ], 
     "prompt_number": 7
    }, 
    {
     "cell_type": "markdown", 
     "source": [
      "<h3>Example 9.8, Page Number: 298<h3>"
     ]
    }, 
    {
     "cell_type": "code", 
     "collapsed": false, 
     "input": [
      "", 
      "import math", 
      "# variable declaration", 
      "P_D_avg=4.0*10**-3;    #power dissipation", 
      "V_CC=24.0;              #supply voltage", 
      "R_c=100.0;              #resistance in ohm", 
      "", 
      "#calculation", 
      "P_out=(0.5*V_CC**2)/R_c;  #output power", 
      "n=(P_out)/(P_out+P_D_avg);    #n is efficiency", 
      "", 
      "#result", 
      "print \"efficiency=%.4f\" %n"
     ], 
     "language": "python", 
     "outputs": [
      {
       "output_type": "stream", 
       "stream": "stdout", 
       "text": [
        "efficiency=0.9986"
       ]
      }
     ], 
     "prompt_number": 8
    }
   ]
  }
 ]
}