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{
"metadata": {
"name": "",
"signature": "sha256:3303f44cdb2f2123a36f676f7675540bf34779306594f12942900e5506f78518"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter11:Tuned Volatge AMplifiers"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example E1 - Pg 401"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate frequency and impedance and current and voltage across each element at resonance\n",
"#given\n",
"import math\n",
"R=12.;#ohm\n",
"L=200.*10.**-6.;#H\n",
"C=300.*10.**-12.;#F\n",
"Vs=9.;#V\n",
"fo=1./(2.*math.pi*math.sqrt(L*C));\n",
"Z=R;#impedance\n",
"print '%s %.1f %s' %(\"The Resonant frequency =\",fo/1000,\"kHz\\n\");\n",
"print '%s %.f %s' %(\"The impedance Z =\",Z,\"ohm\\n\");\n",
"\n",
"Io=Vs/R;\n",
"print '%s %.2f %s' %(\"The Source current =\",Io,\"A\\n\");\n",
"\n",
"Vl=Io*(2.*math.pi*fo*L);\n",
"Vc=Io/(2.*math.pi*fo*C);\n",
"Vr=Io*R;\n",
"print '%s %.1f %s' %(\"The voltage across the inductor =\",Vl,\"V\\n\");\n",
"print '%s %.1f %s' %(\"The voltage across the capacitor =\",Vc,\"V\\n\");\n",
"print '%s %.f %s' %(\"The voltage across the resistor =\",Vr,\"V\\n\");\n",
"#There is a slight variation in voltage across capacitor due to the approaximation\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The Resonant frequency = 649.7 kHz\n",
"\n",
"The impedance Z = 12 ohm\n",
"\n",
"The Source current = 0.75 A\n",
"\n",
"The voltage across the inductor = 612.4 V\n",
"\n",
"The voltage across the capacitor = 612.4 V\n",
"\n",
"The voltage across the resistor = 9 V\n",
"\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example E2 - Pg 401"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate frequency and impedance and current at resonance and current in coil and capacitor\n",
"#given\n",
"import math\n",
"R=10.;#ohm\n",
"L=100.*10.**-6.;#H\n",
"C=100.*10.**-12.;#F\n",
"Vs=10.;#V\n",
"fo=1./(2.*math.pi*math.sqrt(L*C));\n",
"Zp=L/(C*R); #impedance\n",
"print '%s %.3f %s' %(\"The Resonant frequency =\",fo/10**6,\"MHz\\n\");\n",
"print '%s %.f %s' %(\"The impedance Z =\",Zp/1000,\"kohm\\n\");\n",
"\n",
"Io=Vs/Zp;\n",
"print '%s %.f %s' %(\"The Source current =\",Io*10**6,\"uA\\n\");\n",
"\n",
"Xl=(2.*math.pi*fo*L);\n",
"Xc=1./(2.*math.pi*fo*C);\n",
"Z1=math.sqrt(Xl**2.+R**2.);\n",
"Z2=Xc;\n",
"Ic=Vs/Z2;\n",
"Il=Ic;\n",
"print '%s %.f %s' %(\"The current in the coil =\",1000,\"ohm\\n\");\n",
"print '%s %.f %s' %(\"The current in the capacitor =\",Ic*1000,\"mA\\n\");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The Resonant frequency = 1.592 MHz\n",
"\n",
"The impedance Z = 100 kohm\n",
"\n",
"The Source current = 100 uA\n",
"\n",
"The current in the coil = 1000 ohm\n",
"\n",
"The current in the capacitor = 10 mA\n",
"\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example E3 - Pg 402"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate impedance and quality factor and bandwidth\n",
"#given\n",
"import math\n",
"R=10.;#ohm\n",
"L=150.*10.**-6.;#H\n",
"C=100.*10.**-12.;#F\n",
"fo=1/(2.*math.pi*math.sqrt(L*C));\n",
"Zp=L/(C*R); #impedance\n",
"print '%s %.f %s' %(\"The impedance Z =\",Zp/1000,\"kohm\\n\");\n",
"\n",
"Xl=(2.*math.pi*fo*L);\n",
"Q=Xl/R;\n",
"BW=fo/Q;\n",
"print '%s %.1f %s' %(\"The Quality factor of the circuit =\",Q,\"\\n\");\n",
"print '%s %.1f %s' %(\"The Band width of the circuit =\",BW/1000,\"kHz\\n\");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The impedance Z = 150 kohm\n",
"\n",
"The Quality factor of the circuit = 122.5 \n",
"\n",
"The Band width of the circuit = 10.6 kHz\n",
"\n"
]
}
],
"prompt_number": 3
}
],
"metadata": {}
}
]
}
|
