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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter18 Fascimile and Television"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 18.2.1,Pg.no.671"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The index of co−operation is 1105.84\n"
]
}
],
"source": [
"import math\n",
"from math import pi\n",
"#given\n",
"D=70.4\n",
"P=0.2 \n",
"#Determination of index of co−operation\n",
"IOC_CCITT=D/P\n",
"IOC_IEEE=IOC_CCITT*(pi)\n",
"IOC_IEEE=round(IOC_IEEE,2)\n",
"print 'The index of co−operation is',IOC_IEEE"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 18.2.2,Pg.no.676"
]
},
{
"cell_type": "code",
"execution_count": 4,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The no . of pixels in scan line is 826.0 pixels/line \n",
"The scan rate is 2 lines/sec \n",
"The pixel rate is 1652.0 pixels/sec\n",
"The document Transmission time is 8 sec\n"
]
}
],
"source": [
"import math\n",
"from math import pi\n",
"D=68.4\n",
"P=0.26\n",
"rpm=120\n",
"n=1075\n",
"#Determination of no . of pixels scan\n",
"Npx=(pi)*(D/P)\n",
"Npx=round(Npx,0)\n",
"print 'The no . of pixels in scan line is',Npx,'pixels/line ' \n",
"#Determination of scan rate\n",
"Rs=rpm/60\n",
"print 'The scan rate is',Rs,'lines/sec '\n",
"#Determination of pixel rate is\n",
"Rpx=Npx*Rs\n",
"Rpx=round(Rpx,0)\n",
"print 'The pixel rate is',Rpx,'pixels/sec'\n",
"f_max=Rpx/2\n",
"#Determination of document Tx time\n",
"td=n/(60*Rs)\n",
"print 'The document Transmission time is',td,'sec'"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 18.3.1,Pg.no.693"
]
},
{
"cell_type": "code",
"execution_count": 5,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The no . of pixel periods in line period is 485 lines\n",
"The picture height is 485 pixels\n",
"The picture length is 580.8 pixels\n"
]
}
],
"source": [
"import math\n",
"a=(4/3) #aspect ratio\n",
"N=525 #no . of line periods per frame\n",
"Ns=40 #no . of suppressed lines\n",
"#Determination of no . of pixel periods in line period\n",
"Nv=N-Ns\n",
"print 'The no . of pixel periods in line period is',Nv,'lines'\n",
"#Determination of picture height and width\n",
"Nh=a*Nv\n",
"print 'The picture height is',Nh,'pixels'\n",
"Nl=(Nh/0.835)\n",
"Nl=round(Nl,1)\n",
"print 'The picture length is',Nl,'pixels'"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 18.3.2,Pg.no.694"
]
},
{
"cell_type": "code",
"execution_count": 6,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The horizontal frequency is 15750.0 Hz\n",
"The vertical frequency is 60.0 Hz\n",
"The time required to scan one line is 6.35e-05 sec\n"
]
}
],
"source": [
"import math\n",
"N=525.0\n",
"P=30.0\n",
"#Determination of horizontal and vertical synchhronization freq .\n",
"fh=N*P\n",
"print 'The horizontal frequency is',fh,'Hz'\n",
"fv=2*P\n",
"print 'The vertical frequency is',fv,'Hz'\n",
"#Determination of time reqd to scan one line\n",
"Th=((fh)**-1)*10**5\n",
"Th=round(Th,2)*10**-5\n",
"print 'The time required to scan one line is',Th,'sec'"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 18.3.3,Pg.no.695"
]
},
{
"cell_type": "code",
"execution_count": 7,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"the band width is 4272187.5 Hz\n"
]
}
],
"source": [
"import math\n",
"fh=15750\n",
"Nl=775\n",
"#Determination of video bandwidth\n",
"Bv=0.35*fh*Nl\n",
"Bv=round(Bv,1)\n",
"print 'the band width is',Bv,'Hz'"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 18.7.1,Pg.no.706"
]
},
{
"cell_type": "code",
"execution_count": 8,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The viewing angle is 10.78 degrees\n",
"The min.viewing dist is -0.14 m\n"
]
}
],
"source": [
"import math\n",
"from math import sqrt\n",
"a=4/3 #aspect ratio\n",
"D=48.26*10**-2 #CRT tube diagonal\n",
"Nh=647.0\n",
"H=sqrt((a**2)*(D**2)/(1+a**2))\n",
"#Determination of viewing angle & minimum distance\n",
"w=H/Nh\n",
"theta=Nh*(1/60.0) #As each pixel subtend 1 minute of arc\n",
"theta=round(theta,2)\n",
"print 'The viewing angle is',theta,'degrees' \n",
"X=H/(2*math.tan(theta/2))\n",
"X=round(X,2)\n",
"print 'The min.viewing dist is',X,'m'"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 18.7.2,Pg.no.707"
]
},
{
"cell_type": "code",
"execution_count": 9,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The viewing angle is 30.67 degrees\n",
"The viewing dist is -1.27 m\n"
]
}
],
"source": [
"import math\n",
"from math import sqrt\n",
"a=16/9\n",
"D=1.40\n",
"Nh=1840.0 #Assuming square pixel\n",
"H=sqrt((a**2)*(D**2)/(1+a**2))\n",
"#Determination of viewing angle\n",
"theta=Nh*(1/60.0)\n",
"theta=round(theta,2)\n",
"print 'The viewing angle is',theta,'degrees'\n",
"#Determination of viewing dist\n",
"X=H/(2*math.tan(theta/2));\n",
"X=round(X,2)\n",
"print 'The viewing dist is',X,'m'"
]
}
],
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"kernelspec": {
"display_name": "Python 2",
"language": "python",
"name": "python2"
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"language_info": {
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"file_extension": ".py",
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|
