summaryrefslogtreecommitdiff
path: root/Electronic_Communication_Systems_by_Roy_Blake/Chapter21.ipynb
blob: 59c9285689b0beda8e01beda651c00d3c7e0f799 (plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
{
 "cells": [
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# Chapter 21 : Cellular Radio"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Example 1 : pg 795"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Handoff time is 720.0 sec\n",
      "Handoff time is 36.0 sec\n"
     ]
    }
   ],
   "source": [
    " \n",
    "# page no 795\n",
    "# prob no 21.1\n",
    "#calculate the hand off time\n",
    "#given\n",
    "v=100.;#in km/hr\n",
    "# first convert speed into m/sec\n",
    "v1=(100.*10**3)/3600;#in km/sec\n",
    "#calculations and results\n",
    "#part a)\n",
    "r=10.**4;#in m\n",
    "t=(2*r)/v1;\n",
    "print 'Handoff time is',t,'sec'\n",
    "#part b)\n",
    "r=500;#in m\n",
    "t=(2*r)/v1;\n",
    "print 'Handoff time is',t,'sec'"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Example 2 : pg 807"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "a) The average traffic is 416.667 E\n",
      "The peak traffic is 3333.333 E\n",
      "b) The average traffic per cell is 3.472 E\n",
      "The peak traffic per cell is 27.778 E\n"
     ]
    }
   ],
   "source": [
    " \n",
    "# page no 807\n",
    "# prob no 21.2\n",
    "#calculate the average and peak traffic\n",
    "#given\n",
    "N = 12\n",
    "m = 120.\n",
    "a = 20000.\n",
    "th = 30.#in min/day this means\n",
    "H = 0.5\n",
    "tp = 10.\n",
    "#calculations and results\n",
    "#part a)Calculation of the average and peak traffic in erlangs for the whole\n",
    "#system\n",
    "# The average traffic is\n",
    "T = a * H / 24\n",
    "print 'a) The average traffic is',round(T,3),'E'\n",
    "# The peak traffic is\n",
    "T1 = (a * tp) / 60\n",
    "print 'The peak traffic is',round(T1,3),'E'\n",
    "#part b)Calculation of the average and peak traffic in erlangs for one cell\n",
    "# The average traffic per cell is\n",
    "t = T / m\n",
    "print 'b) The average traffic per cell is',round(t,3),'E'\n",
    "# The peak traffic per cell is\n",
    "t = T1 / m\n",
    "print 'The peak traffic per cell is',round(t,3),'E'\n",
    "# part c)\n",
    "# For average traffic at 3.47E, the blocking probability is much less than 1%,\n",
    "# since the average no of call is much less than the no of channels. \n",
    "#However, the blocking probability increases to just over 5%"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Example 3 : pg 816"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "The maximum distance between base and mobile is 36900.0 m\n"
     ]
    }
   ],
   "source": [
    " \n",
    "# page no 816\n",
    "# prob no 21.3\n",
    "#calculate the max distance\n",
    "#given\n",
    "tg=123.*10**-6;\n",
    "c=3.*10**8;\n",
    "#calculations\n",
    "#The maximum distance between base and mobile is\n",
    "d=c*tg;\n",
    "#results\n",
    "print 'The maximum distance between base and mobile is',d,'m'"
   ]
  }
 ],
 "metadata": {
  "kernelspec": {
   "display_name": "Python 2",
   "language": "python",
   "name": "python2"
  },
  "language_info": {
   "codemirror_mode": {
    "name": "ipython",
    "version": 2
   },
   "file_extension": ".py",
   "mimetype": "text/x-python",
   "name": "python",
   "nbconvert_exporter": "python",
   "pygments_lexer": "ipython2",
   "version": "2.7.11"
  }
 },
 "nbformat": 4,
 "nbformat_minor": 0
}