1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
|
{
"metadata": {
"name": "",
"signature": "sha256:e9fb88f63f2c9c2769603c77ea25313f638342259fa02ac4950a18408033aeb6"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter9-Oscillators"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1-pg173"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:9.1\n",
"import math\n",
"C=10.*10**-9;\n",
"R=10000.;\n",
"f=(1./(2.*math.pi*math.sqrt (6.)*C*R));\n",
"print'%s %.2f %s'%(\"The freq of oscillation = \",f,\" Hz\");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The freq of oscillation = 649.75 Hz\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2-pg173"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:9.2\n",
"import math\n",
"r1=1000.;\n",
"r2=1000.;\n",
"c=100.*10**-9;\n",
"f=(1./(2.*math.pi*c*r1));\n",
"print'%s %.2f %s'%(\"The freq of oscillation at 1 kohm= \",f,\" Hz\");\n",
"R1=6000.;\n",
"R2=6000.;\n",
"F=(1/(2.*math.pi*c*R1));\n",
"print'%s %.2f %s'%(\"\\nThe freq of oscillation at 6 kohm= \",F,\" Hz\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The freq of oscillation at 1 kohm= 1591.55 Hz\n",
"\n",
"The freq of oscillation at 6 kohm= 265.26 Hz\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex3-pg176"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:9.3\n",
"import math\n",
"f=1000.;\n",
"t=1./f;\n",
"C=10.*10**-9;\n",
"R=t/(1.4*C);\n",
"print'%s %.2f %s'%(\"R= \",R/1000,\" kohm\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"R= 71.43 kohm\n"
]
}
],
"prompt_number": 3
}
],
"metadata": {}
}
]
}
|
