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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 19 : Economic Load Dispatch"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 19.1, Page No 643"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"import numpy as np\n",
"#initialisation of variables\n",
"#dF1/dP1=.4*P1+40 per MWhr\n",
"#dF2/dP2=.5*P1+30 per MWhr\n",
"print(\"Two equations are :\")\n",
"print(\"%.1f P1 %.1f P2 = %.1f\\n\" %(.4,-.5,-10))\n",
"print(\"%.1f P1+ %.1fP2 = %.1f\\n\" %(1,1,180))\n",
"A=[[.4,1],[-.5,1]]\n",
"B=[-10,180]\n",
"P1=88.89\n",
"P2=91.11\n",
"\n",
"#Calculations\n",
"F1=.2*(P1)**2 +40*P1+120\n",
"F2=.25*(P2)**2+30*P2+150\n",
"Total=F1+F2\t\t\t#Total cost\n",
"print(\"(a)Cost of Generation=Rs %.2f /hr\\n\" %Total)\n",
"P1=90\n",
"P2=90\n",
"F1=.2*(P1)**2 +40*P1+120\n",
"F2=.25*(P2)**2+30*P2+150\n",
"Total2=F1+F2\t\t#Total cost\n",
"savings=Total2-Total\n",
"\n",
"#Results\n",
"print(\"(b)Savings=Rs %.2f /hr\\n\" %savings)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Two equations are :\n",
"0.4 P1 -0.5 P2 = -10.0\n",
"\n",
"1.0 P1+ 1.0P2 = 180.0\n",
"\n",
"(a)Cost of Generation=Rs 10214.44 /hr\n",
"\n",
"(b)Savings=Rs 0.56 /hr\n",
"\n"
]
}
],
"prompt_number": 10
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 19.2, Page No 643"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"pf=10.0/8 #penalty factor\n",
"\n",
"#Calculations\n",
"cost=(.1*10+3)*pf\t\t#Cost of recieved power=dF1/dP1\n",
"\n",
"#Results\n",
"print(\"Penalty Factor = %.1f\" %pf)\n",
"print(\"Cost of recieved Power = Rs %.1f /MWhr\" %cost)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Penalty Factor = 1.2\n",
"Cost of recieved Power = Rs 5.0 /MWhr\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 19.4, Page No 645"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"print(\"two equations are :\")\n",
"print(\"%.3f P1 %.2f P2 = %.1f\" %(0.048,-.08,-2))\n",
"print(\"%.1f P1+ %.1fP2 = %.1f\" %(1,1,50))\n",
"\n",
"#Calculations\n",
"A=[[.048,-.08],[1,1]]\n",
"B=[-2,50]\n",
"P1=15.625\n",
"P2=34.38\n",
"F1=(.024*(P1)**2 +8*P1+80)*(10**6)\n",
"F2=(.04*(P2)**2+6*P2+120)*(10**6)\n",
"print(\"when load is 150MW , equations are: :\")\n",
"print(\"%.3f P1 %.2f P2 = %.1f\" %(.048,-.08,-2))\n",
"print(\"%.1f P1+ %.1fP2 = %.1f\" %(1,1,150))\n",
"A=[[.048,-.08],[1,1]]\n",
"B=[-2,150]\n",
"P1=78.125\n",
"P2=71.88\n",
"f1=(.024*(P1)**2 +8*P1+80)*(10**6)\n",
"f2=(.04*(P2)**2+6*P2+120)*(10**6)\n",
"Total=(F1+F2+f1+f2)*12*2/(10**6)\n",
"\n",
"#Results\n",
"print(\"Total cost=Rs. %.2f\" %(Total))\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"two equations are :\n",
"0.048 P1 -0.08 P2 = -2.0\n",
"1.0 P1+ 1.0P2 = 50.0\n",
"when load is 150MW , equations are: :\n",
"0.048 P1 -0.08 P2 = -2.0\n",
"1.0 P1+ 1.0P2 = 150.0\n",
"Total cost=Rs. 52652.46\n"
]
}
],
"prompt_number": 12
}
],
"metadata": {}
}
]
}
|
