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"cells": [
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"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 01 : Fundamentals of power System"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1.1, Page No 11"
]
},
{
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"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"Sb=100.0\t\t# base value of power(MVA)\n",
"Vb=33.0\t\t\t# base value of voltage (Kv)\n",
"\n",
"#Calculations\n",
"Vbl=Vb*110.0/32\n",
"Vbm=Vbl*32.0/110\n",
"Zp_ut=0.08*100*32*32/(110*33*33)\n",
"Zp_u_l=50*100/(Vbl**2)\n",
"Zp_um1=0.2*100*30*30.0/(30*33*33)\n",
"Zp_um2=0.2*100*30*30.0/(20*33*33)\n",
"Zp_um3=0.2*100*30*30.0/(50*33*33)\n",
"\n",
"#Results\n",
"print(\"Base value of voltage in line = %.2f kV\" %Vbl)\n",
"print(\"Base value of voltage in motor circuit=%.0f kV\" %Vbm)\n",
"print(\"p.u value of reactance transformer =%.5f p.u\" %Zp_ut)\n",
"print(\"p.u value of impedence of line=%.4f p.u\" %Zp_u_l)\n",
"print(\"p.u value of reactance of motor 1 =%.4f p.u\" %Zp_um1)\n",
"print(\"p.u value of reactance of motor 2 =%.3f p.u\" %Zp_um2)\n",
"print(\"p.u value of reactance of motor 3 =%.4f p.u\" %Zp_um3)\n",
"\n"
],
"language": "python",
"metadata": {},
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{
"output_type": "stream",
"stream": "stdout",
"text": [
"Base value of voltage in line = 113.44 kV\n",
"Base value of voltage in motor circuit=33 kV\n",
"p.u value of reactance transformer =0.06839 p.u\n",
"p.u value of impedence of line=0.3886 p.u\n",
"p.u value of reactance of motor 1 =0.5510 p.u\n",
"p.u value of reactance of motor 2 =0.826 p.u\n",
"p.u value of reactance of motor 3 =0.3306 p.u\n"
]
}
],
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}
],
"metadata": {}
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|
