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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h1>Chapter 39: Dielectrics and dielectric loss</h1>"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h3>Example 1, page no. 717</h3>"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Determine for the capacitor, at a frequency of 8 MHz, \n",
"#(a) the loss angle, (b) the power factor, (c) the Q-factor, and (d) the dissipation factor.\n",
"from __future__ import division\n",
"import math\n",
"#initializing the variables:\n",
"Rs = 1.5;# in ohms\n",
"Cs = 400E-12;# in Farads\n",
"f = 8E6;# in Hz\n",
"\n",
"#calculation: \n",
" #for a series equivalent circuit,\n",
" #tan(del) = Rs*w*Cs\n",
" #loss angle,\n",
"de = math.atan(Rs*Cs*(2*math.pi*f))\n",
" #power factor\n",
"pf = math.cos(de)\n",
" #the Q-factor\n",
"Q = 1/math.tan(de)\n",
" #dissipation factor,\n",
"D = 1/Q\n",
"\n",
"\n",
"#Results\n",
"print \"\\n\\n Result \\n\\n\"\n",
"print \"\\n (a)loss angle \",round(de,2),\" rad.\"\n",
"print \"\\n (b)power factor \",round(de,2),\" rad.\"\n",
"print \"\\n (c)Q-factor is \",round(Q,2)\n",
"print \"\\n (d)dissipation factor \",round(D,2),\" rad.\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"\n",
" Result \n",
"\n",
"\n",
"\n",
" (a)loss angle 0.03 rad.\n",
"\n",
" (b)power factor 0.03 rad.\n",
"\n",
" (c)Q-factor is 33.16\n",
"\n",
" (d)dissipation factor 0.03 rad."
]
}
],
"prompt_number": 1
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h3>Example 2, page no. 718</h3>"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Determine the component values of the equivalent parallel circuit.\n",
"from __future__ import division\n",
"import math\n",
"#initializing the variables:\n",
"de = 0.025;# in rad.\n",
"V = 5000;# in Volts\n",
"PL = 20;# power loss\n",
"f = 50;# in Hz\n",
"\n",
"#calculation: \n",
" #power loss = w*C*V**2*tan(del)\n",
"Cp = PL/(2*math.pi*f*V*V*math.tan(de))\n",
" #for a parallel equivalent circuit,\n",
" #tan(del) = 1/(Rp*w*Cp)\n",
"Rp = 1/(2*math.pi*f*Cp*math.tan(de))\n",
"\n",
"\n",
"#Results\n",
"print \"\\n\\n Result \\n\\n\"\n",
"print \"\\n capacitance C \",round(Cp*1E6,2),\"uF and parallel resistance \",round(Rp,2),\"ohm.\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"\n",
" Result \n",
"\n",
"\n",
"\n",
" capacitance C 0.1 uF and parallel resistance 1250000.0 ohm."
]
}
],
"prompt_number": 2
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h3>Example 3, page no. 718</h3>"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#determine (a) the loss angle, (b) the equivalent series loss resistance, and (c) the equivalent parallel loss resistance.\n",
"from __future__ import division\n",
"import math\n",
"#initializing the variables:\n",
"P = 500E-6;# in Watt\n",
"C = 2000E-12;# in Farads\n",
"V = 20;# in Volts\n",
"f = 10000;# in Hz\n",
"\n",
" #calculation: \n",
" #power loss = w*C*V**2*tan(del)\n",
" #loss angle\n",
"de = math.atan(P/(2*math.pi*f*V*V*C))\n",
" #for an equivalent series circuit,\n",
" #tan(del) = (Rs*w*Cs)\n",
"Cs = C\n",
"Rs = (math.tan(de))/(2*math.pi*f*Cs)\n",
" #for an equivalent parallel circuit\n",
" #tan(del) = 1/(Rp*w*Cp)\n",
"Cp = C\n",
"Rp = 1/(2*math.pi*f*Cp*math.tan(de))\n",
"\n",
"\n",
"#Results\n",
"print \"\\n\\n Result \\n\\n\"\n",
"print \"\\n (a)loss angle \",round(de*180/math.pi,2),\"deg\"\n",
"print \"\\n (b)series resistance \",round(Rs,2),\" ohm.\"\n",
"print \"\\n (c)parallel resistance \",round(Rp/1000,2),\"Kohm.\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"\n",
" Result \n",
"\n",
"\n",
"\n",
" (a)loss angle 0.57 deg\n",
"\n",
" (b)series resistance 79.16 ohm.\n",
"\n",
" (c)parallel resistance 800.0 Kohm."
]
}
],
"prompt_number": 1
}
],
"metadata": {}
}
]
}
|
