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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"APPENDIX A-3: APPLICABLE SECTIONS OF THE NATIONAL ELECTRIC CODE(NEC)"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1, Page number 594"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"hp = 5.0 #Power rating of motor(hp)\n",
"V = 220.0 #Voltage rating of motor(V)\n",
"Va_a = 180.0 #Armature voltage(V)\n",
"Va_b = 240.0 #Armature voltage(V)\n",
"\n",
"#Calculation\n",
"I1 = 27.0 #Current(A). From Appendix A-3 table for 180V\n",
"I_L1 = I1*(Va_a/V) #Full load current(A)\n",
"I2 = 20.0 #Current(A). From Appendix A-3 table for 240V\n",
"I_L2 = I2*(Va_b/V) #Full load current(A)\n",
"\n",
"#Result\n",
"print('Case(a): Full-load current for armature voltage of 180 V , I_L1 = %.f A' %I_L1)\n",
"print('Case(b): Full-load current for armature voltage of 240 V , I_L2 = %.f A' %I_L2)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Case(a): Full-load current for armature voltage of 180 V , I_L1 = 22 A\n",
"Case(b): Full-load current for armature voltage of 240 V , I_L2 = 22 A\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2, Page number 594"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"hp = 10.0 #Power rating of motor(hp)\n",
"V = 600.0 #Voltage rating of motor(V)\n",
"Va = 550.0 #Armature voltage(V)\n",
"\n",
"#Calculation\n",
"I = 16.0 #Current(A). From Appendix A-3 table for 550 V\n",
"I_L = I*(Va/V) #Full load current(A)\n",
"\n",
"#Result\n",
"print('Line current at rated load , I_L = %.1f A' %I_L)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Line current at rated load , I_L = 14.7 A\n"
]
}
],
"prompt_number": 1
}
],
"metadata": {}
}
]
}
|
