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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 1 : Introduction"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1.1 Page No : 1"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Given\n",
"m = 10.; # Acceleration is 2.0m/s**2\n",
"a = 2.; # mass\n",
"\n",
"# Calculation and Results\n",
"#a)\")\n",
"F = m*a\n",
"print \"Force is %dN\"%(F)\n",
"#b)\")\n",
"t = 4; # time\n",
"x = (a*t*t)/2\n",
"KE = (F*x)\n",
"P = KE/t\n",
"print \"Position is %dm\"%(x)\n",
"print \"Kinetic energy = %3.1fJ\"%(KE)\n",
"print \"Power = %3.1fW\"%(P)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Force is 20N\n",
"Position is 16m\n",
"Kinetic energy = 320.0J\n",
"Power = 80.0W\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1.2 Page No : 3"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Given\n",
"i = 5.; # current flow\n",
"\n",
"# Calculation\n",
"#As electroms/min is asked so we need to convert A(C/s) to C/min\n",
"i1 = 5*60;\n",
"#Let e be electronic charge\n",
"e = 1.602*10**-19\n",
"n = (i1/e)\n",
"\n",
"# Results\n",
"print \"Number of electrons = %3.2f electrons/min\"%(n)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Number of electrons = 1872659176029962633216.00 electrons/min\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1.3 Page No : 8"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Given\n",
"E = 9.25*10**-6 ##Energy is 9.25uJ\")\n",
"q = 0.5*10**-6; # #Charge to be transferred is 0.5uC\")\n",
"\n",
"# Calculation\n",
"#1 volt is 1 joule per coulomb\n",
"V = E/q;\n",
"\n",
"# Results\n",
"print \"Potential difference between two points a and b is %3.1fV\"%(V)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Potential difference between two points a and b is 18.5V\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1.4 Page No : 10"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Given\n",
"#Potential difference is 50V\")\n",
"#Charge per minute is 120C/min\")\n",
"V = 50.\n",
"x = 120;\n",
"\n",
"# Calculation\n",
"#As Electrical energy is to be calculated charge per minute is to be converted in charge per second\n",
"#Charge per second is nothing but the current\n",
"i = x/60;\n",
"P = i*V;\n",
"#Since is 1W = 1J/s\n",
"\n",
"# Results\n",
"print \"Rate of energy conversion is %dJ/s\"%(P)\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Rate of energy conversion is 100J/s\n"
]
}
],
"prompt_number": 4
}
],
"metadata": {}
}
]
}
|
