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{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 19 : Controlled Release and Related Phenomena"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 19.1.1 pg : 554"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\t\n",
"#initialization of variables\n",
"VP = 0.045*10**-3\t# Vapor pressure of permethrin in kg/m-sec**2\n",
"R = 8.31 \t# Gas consmath.tant in kg-m**2/sec**2-gmol-K\n",
"l = 63.*10**-6 \t# membrane thickness in m\n",
"A = 12.*10**-4 \t# area surrounded by the membrane in m**2\n",
"M1 = 19.*10**-3 \t# Permithrin release in gmol\n",
"t = 24.*3600 \t# time taken to release\n",
"T = 298. \t# Kelvin\n",
"MW = 391. \t# Mol wt\n",
"\t\n",
"#Calculations\n",
"c1 = VP/(R*T) \t# C1sat \n",
"P = (M1/(t*MW))*(l/c1)*(1/A)*10**-3 \t#Permeability in cm**2/sec\n",
"\t\n",
"#Results\n",
"print \"The permeability is %.1e m**2/sec\"%(P)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The permeability is 1.6e-06 m**2/sec\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 19.2.1 pg : 557"
]
},
{
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"input": [
"\t\n",
"#initialization of variables\n",
"M= 25*10**-6 \t#gm/hr\n",
"d = 0.006 \t#g/cc\n",
"P = 1.4*10**-4\t# permeance in cm/sec\n",
"Deltac1 = 0.006 \t#Equivalent\t#cc\n",
"\t\n",
"#Calculations\n",
"c1 = 1./3600 \t# unit conversion factor hr/sec\n",
"c2 = 1./18 \t#unit conversion factor mole/cc\n",
"m = M*c1*c2/d \t# moles/sec\n",
"A = m/(P*Deltac1)\t#cm**2\n",
"\t\n",
"#Results\n",
"print \"you will need a membrane area of %.3f cm**2\"%(A)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"you will need a membrane area of 0.077 cm**2\n"
]
}
],
"prompt_number": 2
}
],
"metadata": {}
}
]
}
|
