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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 8:Molecules"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Exampnle no:8.1,Page no:283"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration \n",
"r= 0.113 #bond length, nm\n",
"Mc= 1.99*(10**(-26)) #mass of C12, kg\n",
"Mo= 2.66*(10**(-26)) #mass of O16, kg\n",
"\n",
"#Calculation\n",
"#Part (a)\n",
"import math\n",
"Mco= (Mc*Mo)/(Mc+Mo) #mass of CO, kg\n",
"I= Mco*((r*(10.0**(-9.0)))**2.0) #moment of inertia, kg.m**2\n",
"J=1.0 #lowest rotational state\n",
"h= 6.63*(10**(-34)) #Planck's constant, J.s\n",
"hbar= h/(2.0*(math.pi)) #reduced Planck's constant, J.s\n",
"E1= (J*(J+1)*(hbar**2))/(2.0*I) #energy corresponding to state J=1, J\n",
"e= 1.6*(10**(-19)) #charge of an electron, C\n",
"E1= E1/e #converting to eV\n",
"#Part(b)\n",
"w= math.sqrt((2.0*7.61*10**-23)/(1.46*10**-46)) #angular velocity, rad/s\n",
"\n",
"#Result\n",
"print\"(a).The energy of CO molecule is:%.2e\"%E1,\"eV(approx)\"\n",
"print\"(b).The angular velocity is:%.3g\"%w,\"rad/sec\\n\"\n",
"\n",
"print\"NOTE:(Calculation mistake):Incorrect answer in book for (b) part\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a).The energy of CO molecule is:4.79e-04 eV(approx)\n",
"(b).The angular velocity is:1.02e+12 rad/sec\n",
"\n",
"NOTE:(Calculation mistake):Incorrect answer in book for (b) part\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Exampnle no:8.2,Page no:285"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"Ji=0 #initial state\n",
"Jf=1 #final state\n",
"f= 1.15*(10**11) #frequency for the absorption, Hz\n",
"h= 6.63*(10**(-34)) #Planck's constant, J.s\n",
"\n",
"#Calculation\n",
"hbar= h/(2*(math.pi)) #reduced Planck's constant, J.s\n",
"Ico= hbar*Jf/(2*(math.pi)*f) #moment of inertia, kg.m**2\n",
"Mco= 1.14*(10**(-26)) #Mass of CO, refer Exa 8.1\n",
"r= math.sqrt(Ico/Mco) #bond length, m\n",
"r= r*(10**9) #converting to nm\n",
"\n",
"#Result\n",
"print\"The bond length of CO molecule is: \",round(r,3),\"nm\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The bond length of CO molecule is: 0.113 nm\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Exampnle no:8.3,Page no:288"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"f= 6.42*(10**13) #frequency of absorbed radiation, Hz\n",
"Mco= 1.14*(10**(-26)) #mass of CO, kg\n",
"h= 6.63*(10**(-34)) #Planck's constant, J.s\n",
"\n",
"#Calculation\n",
"#Part (a)\n",
"k= 4*((math.pi)**2)*(f**2)*Mco #using Eqn 8.15, Page 287\n",
"#Part (b)\n",
"dE= h*f #separation, J\n",
"etoJ=dE*6.24*10**18 \n",
"\n",
"#Result\n",
"print\"(a).The force constant for the bond in CO molecule is: %.3g\"%k,\"N/m\"\n",
"print\"\\nNOTE:Slight error in calculation of book,'k' is written as 1.86*10**3\\n\\n\"\n",
"print\"(b).The separation in its vibrational eergy levels is:%.3g\"%dE,\"J=\",round(etoJ,3),\"eV\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a).The force constant for the bond in CO molecule is: 1.85e+03 N/m\n",
"\n",
"NOTE:Slight error in calculation of book,'k' is written as 1.86*10**3\n",
"\n",
"\n",
"(b).The separation in its vibrational eergy levels is:4.26e-20 J= 0.266 eV\n"
]
}
],
"prompt_number": 4
}
],
"metadata": {}
}
]
}
|
