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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 7:Many electron Atoms"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 7.1,Page no:230"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration \n",
"r= 5*(10**(-17)) #radius of spherical electron, m\n",
"Me= 9.1*(10**(-31)) #mass of electron, kg\n",
"h= 6.63*(10**(-34)) #Planck's constant, J.s\n",
"\n",
"#Calculation\n",
"import math\n",
"hbar= h/(2*(math.pi)) #reduced Planck's constant, J.s\n",
"v= (5*math.sqrt(3)/4)*(hbar/(Me*r)) #using Eqn 7.1, Page 230\n",
"c= 3*(10**8) #velocity of light, m/s\n",
"v= v/c #converting in terms of c, m/s\n",
"\n",
"#Result\n",
"print\"The velocity of electron in times of c is:%.3g\"%v,\"c\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The velocity of electron in times of c is:1.67e+04 c\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 7.2,Page no:241"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration \n",
"n= 2 #outer (2s) orbit of lithium\n",
"E2= -5.39 #Ionisation energy of lithium, for n=2 eV\n",
"E1= -13.6 #for n=1, eV\n",
"\n",
"#Calculation\n",
"Z= n*(math.sqrt(E2/E1)) #modification factor for effective charge\n",
"e= 1.6*(10**(-19)) #charge of an electron, C\n",
"Ceffective = Z*e \n",
" \n",
"#Result \n",
"print\"The effective charge is: \",round(Ceffective/e,2),\"e or%.3g\"%Ceffective,\"C\"\n",
" \n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The effective charge is: 1.26 e or2.01e-19 C\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 7.3,Page no:248"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration \n",
"n= 2 #for 2p state\n",
"Ao= 5.29*(10**(-11)) #Bohr's orbit for n=1, m\n",
"r= (n**2)*Ao #orbital radius, m\n",
"f= 8.4*(10**14) #frequency of revolution, Hz ,using Eqn 4.4\n",
"\n",
"#Calculation\n",
"Mo= 4*(math.pi)*(10**(-7)) #Magnetic constant, T.m/A\n",
"e= 1.6*(10**(-19)) #charge of an electron, C\n",
"B= (Mo*f*e)/(2*r) #Magnetic field, T\n",
"Mb= 9.27*(10**(-24)) #Bohr Magneton, J/T\n",
"Um= Mb*B #Magnetic energy, J\n",
"Um= Um/e #converting to eV\n",
"\n",
"#Result\n",
"print\"The magnetic energy for electron is:%.2g\"%Um,\"eV\"\n",
"print\"\\nThe energy difference is twice this,which is:%.2g\"%(2*Um),\"eV\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The magnetic energy for electron is:2.3e-05 eV\n",
"\n",
"The energy difference is twice this,which is:4.6e-05 eV\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 7.8,Page no:257"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration \n",
"l= 0.180 #wavelength, nm\n",
"l= l* 10**(-9) #converting to m\n",
"c= 3*(10**8) #velocity of light, m/s\n",
"\n",
"#Calculation\n",
"f= c/l #frequency, Hz\n",
"R= 1.097*(10**7) #Rydberg's constant, per m\n",
"Z= 1+(math.sqrt((4*f)/(3*c*R))) #using Eqn 7.21\n",
"\n",
"#Result\n",
"print\"The element has atomic number: \",round(Z)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The element has atomic number: 27.0\n"
]
}
],
"prompt_number": 5
}
],
"metadata": {}
}
]
}
|
