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"metadata": {},
"source": [
"Chapter 30 :\n",
"\n",
"Product-Limiting Microbial \n",
"\n",
"Fermentation"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 30.1 pageno : 651"
]
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"input": [
"import math \n",
"\n",
"# Variables\n",
"k = math.sqrt(3) #hr**-1\n",
"n = 1.\n",
"V = 30. #m3\n",
"CR = 0.12 #kgalc/kgsol\n",
"density = 1000. #kg/m3\n",
"\n",
"# Calculations and Results\n",
"CR = CR*density;\n",
"CR_opt = CR/2;\n",
"alcohol_per = CR_opt*100/density #PErcentage of alcohol\n",
"\n",
"print \" The Percentage of alchol in cocktail is %f\"%(alcohol_per)\n",
"\n",
"kt = 1.\n",
"t = kt/k;\n",
"t_opt = 2*t;\n",
"v_opt = V/t_opt;\n",
"\n",
"print \" The Optimum feed rate is %f\"%(v_opt),\n",
"print \" m3/hr\"\n",
"\n",
"#The production rate of alcohol \n",
"FR = v_opt*CR_opt;\n",
"print \" The production rate of alcohol is %f \"%(FR),\n",
"print \" kgalc/hr\"\n"
],
"language": "python",
"metadata": {},
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{
"output_type": "stream",
"stream": "stdout",
"text": [
" The Percentage of alchol in cocktail is 6.000000\n",
" The Optimum feed rate is 25.980762 m3/hr\n",
" The production rate of alcohol is 1558.845727 kgalc/hr\n"
]
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