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"metadata": {},
"source": [
"Chapter 29 :\n",
"\n",
"Substrate-Limiting\n",
"\n",
"Microbial Fermentation"
]
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{
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"level": 2,
"metadata": {},
"source": [
"Example 29.3 pageno : 639"
]
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"input": [
"import math \n",
"\n",
"# Variables\n",
"CAo = 6. # glucose solution\n",
"CM = 0.4 #kg/m3\n",
"V = 1. #m3\n",
"k = 4.\n",
"\n",
"# Calculations and Results\n",
"N = math.sqrt(1+(CAo/CM));\n",
"kt_op = N/(N-1);\n",
"C_by_A = 0.1;\n",
"t_op = kt_op/k;\n",
"v_op = V/t_op;\n",
"\n",
"#The feed rate of glumath.cose\n",
"FAo = v_op*CAo;\n",
"print \" The feed rate of glumath.cose is %.1f\"%(FAo) ,\n",
"print \"kg/hr\"\n",
"\n",
"#Max consumption rate of glumath.cose is\n",
"XA = N/(N+1);\n",
"c_max = FAo*XA;\n",
"print \" Max consumption rate of glumath.cose is %.1f \"%(c_max),\n",
"print \"kg/hr\"\n",
"\n",
"#Max production rate of E.coli is\n",
"Cc_op = (C_by_A)*CAo*N/(N+1);\n",
"Fcmax = v_op*Cc_op;\n",
"print \" Max production rate of E.coli is %.2f\"%(Fcmax),\n",
"print \"kg/hr\"\n"
],
"language": "python",
"metadata": {},
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{
"output_type": "stream",
"stream": "stdout",
"text": [
" The feed rate of glumath.cose is 18.0 kg/hr\n",
" Max consumption rate of glumath.cose is 14.4 kg/hr\n",
" Max production rate of E.coli is 1.44 kg/hr\n"
]
}
],
"prompt_number": 5
},
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"input": [],
"language": "python",
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