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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 26 :\n",
"\n",
"Fluid-Particle Reactors: Design"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 26.1 pageno : 592"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Lets say F(Ri)/F = F_ri\n",
"\n",
"# Variables\n",
"F_50 = 0.3\n",
"F_100 = 0.4\n",
"F_200 = 0.3;\n",
"t_50 = 5.\n",
"t_100 = 10.\n",
"t_200 = 20.\n",
"tp = 8.\n",
"\n",
"# Calculations\n",
"a = ((1-(tp/t_50))**3)*F_50\n",
"b = ((1-(tp/t_100))**3)*F_100\n",
"c = ((1-(tp/t_200))**3)*F_200;\n",
"g = [a,b,c];\n",
"sum1 = 0;\n",
"for p in range(3):\n",
" if g[p]>0:\n",
" sum1 = sum1+g[p];\n",
"f_converted = 1-sum1;\n",
"\n",
"# Results\n",
"print \" The fraction of solid converted equals %.1f %%\"%(f_converted*100)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" The fraction of solid converted equals 93.2 %\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 26.2 pageno : 597"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"t_avg = 60. # min\n",
"t = 20. #min\n",
"\n",
"# Calculations\n",
"unconverted = ((1./4)*(t/t_avg))-((1./20)*(t/t_avg)**2)+((1./120)*(t/t_avg)**3);\n",
"unconverted1 = ((1./5)*(t/t_avg))-((19./420)*(t/t_avg)**2)+((41./4620)*(t/t_avg)**3);\n",
"c_avg = (unconverted+unconverted1)/2;\n",
"\n",
"# Results\n",
"print \"Fraction of original sulfide ore remain unconverted is %.2f\"%(c_avg)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Fraction of original sulfide ore remain unconverted is 0.07\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 26.3 page no : 600"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"F = 1000. #gm/min\n",
"W = 10000. #gm\n",
"\n",
"# Calculations\n",
"t_avg = W/F;\n",
"F_50 = 300.\n",
"F_100 = 400.\n",
"F_200 = 300. #gm/min\n",
"t_50 = 5.\n",
"t_100 = 10.\n",
"t_200 = 20. #min\n",
"\n",
"unconverted = ((((1./4)*(t_50/t_avg))-((1./20)*(t_50/t_avg)**2)+ ((1./120)*(t_50/t_avg)**3))*(F_50/F))+((((1./4)*(t_100/t_avg))-((1./20)*(t_100/t_avg)**2)+((1./120)*(t_50/t_avg)**3))*(F_100/F))+((((1./4)*(t_200/t_avg))-((1./20)*(t_200/t_avg)**2)+((1./120) *(t_50/t_avg)**3))*(F_200/F))\n",
"converted = 1-unconverted;\n",
"\n",
"# Results\n",
"print \"The mean conversion of soild is %f\"%(converted)\n",
"print \" The answer slightly differs from those given in book as we have considered \\\n",
"only significant terms in infinite series\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The mean conversion of soild is 0.795208\n",
" The answer slightly differs from those given in book as we have considered only significant terms in infinite series\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 26.4 pageno : 601"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"t1 = 1. #hr\n",
"t2 = t1/0.1 \n",
"a = 0.\n",
"r = 1 #ton/hr\n",
"# Calculations\n",
"while a<=1:\n",
" x = (1./4)*(a)-((1./20)*(a)**2)+((1./120)*(a)**3);\n",
" if x >0.099 and x<0.1005:\n",
" r = a;\n",
" a += .0001\n",
"\n",
"FBo = 1. #tons/hr\n",
"t_avg = t2/r;\n",
"W = t_avg*FBo;\n",
"\n",
"# Results\n",
"print \" The needed weight of bed is %.f\"%(W),\n",
"print \"tons\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" The needed weight of bed is 23 tons\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
