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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 6 : Thermodynamic potentials"
]
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 6.6 Page No : 218"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"m = 0.1;\t\t\t #mass of superheated steam in the piston cylinder assembly in kg\n",
"P1 = 1.\t \t\t #initial pressure of superheated steam in MPa\n",
"T1 = 300.\t\t\t #initial temperature of superheated steam in degree celsius\n",
"P2 = 0.1\t\t\t #pressure of steam after expansion in MPa\n",
"T2 = 200.\t\t\t #temperature of steam after expansion in degree celsius\n",
"\n",
"# Calculations\n",
"#For steam at P1 and T1:\n",
"h1 = 3052.1\n",
"v1 = 0.2580\n",
"\n",
"#For steam at P2 and T2:\n",
"h2 = 2875.4\n",
"v2 = 2.1720\n",
"\n",
"del_u = (((h1*10**3)-(P1*10**6*v1))-((h2*10**3)-(P2*10**6*v2)))*10**-3\n",
"W = m*(del_u)\n",
"\n",
"# Results\n",
"print \" The work done by steam = %0.2f kJ\"%(W);\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" The work done by steam = 13.59 kJ\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 6.8 Page No : 220"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"P = 3.\t \t\t #pressure of superheated steam in MPa\n",
"Ti = 300.\t\t\t #temperature at which the steam enters the turbine in degree celsius\n",
"m = 1.\t\t \t #mass flow rate of steam in kg/s\n",
"Te = 60.\t\t\t #temperature of dry saturated steam when it leaves the turbine in degree celsius\n",
"\n",
"# Calculations\n",
"#For steam at P and Ti:\n",
"h1 = 2995.1\t\t\t #specific entahlpy of steam in kJ/kg\n",
"\n",
"#For saturated steam at Te:\n",
"h2 = 2609.7\t\t\t #specific enthalpy of saturated vapour in kJ/kg\n",
"\n",
"Ws = m*(h1-h2)\t\t # Calculations of the power Results of the turbine using Eq.(6.83) in kW\n",
"\n",
"# Results\n",
"print \" The power Results of the turbine = %0.1f kW\"%(Ws);\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" The power Results of the turbine = 385.4 kW\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 6.10 Page No : 223"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"m = 0.1 \t\t\t #mass of superheated steam in the piston cylinder assembly in kg\n",
"P1 = 3.\t \t\t #initial pressure of superheated steam in MPa\n",
"T1 = 300.\t\t\t #initial temperature of superheated steam in degree celsius\n",
"T0 = 300.\t\t\t #temperature of the reservoir which is placed in thermal contact with the piston-cylinder assembly in degree celsius\n",
"P2 = 0.1\t\t\t #pressure of steam after expansion in MPa\n",
"\n",
"#For steam at P1 and T1:\n",
"h1 = 2995.1\n",
"v1 = 0.08116\n",
"s1 = 6.5422\n",
"\n",
"#For steam at P2 and T2:\n",
"h2 = 3074.5\n",
"v2 = 2.6390\n",
"s2 = 8.2166\n",
"\n",
"# Calculations\n",
"T0 = T0+273.15\n",
"\n",
"W = m*(h1-h2-(((P1*v1)-(P2*v2))*10**3)-(T0*(s1-s2)))\n",
"\n",
"# Results\n",
"print \" The maximum work obtained from steam = %0.2f kJ\"%(W);\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" The maximum work obtained from steam = 90.07 kJ\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 6.12 Page No : 226"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"import math\n",
"\n",
"# Variables\n",
"P1 = 0.1\t\t\t #pressure at which air enters the compressor in MPa\n",
"T1 = 300.\t\t\t #temperature at which air enters the compressor in K\n",
"P2 = 1. \t\t\t #pressure at which air leaves the compressor in MPa\n",
"T2 = 300.\t\t\t #temperature at which air leaves the compressor in K\n",
"T0 = 300.\t\t\t #ambient temperature in K\n",
"N = 1. \t\t\t #molar flow rate of air in mol/s\n",
"gaamma = 1.4\t\t #ratio of specific heat capacities (no unit)\n",
"R = 8.314\t\t\t #universal gas constant in J/molK\n",
"\n",
"# Calculations\n",
"\n",
"Ws = (-N*T0*(-R*math.log (P2/P1)))*10**-3\n",
"\n",
"# Results\n",
"print \" The minimum power required to compress one mole per second of air = %0.3f kW\"%(Ws);\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" The minimum power required to compress one mole per second of air = 5.743 kW\n"
]
}
],
"prompt_number": 4
}
],
"metadata": {}
}
]
}
|
