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{
"metadata": {
"name": "",
"signature": "sha256:17452ca2e9b7dcffa8d444e8e6e3bb3b7f47f9f947558729a784ae56a1f45de2"
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Chapter 5 : Pressure"
]
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 5.1 Page no.109\n"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"P = 60 ; #[Gpa]\n",
"\n",
"# Calculation and Results\n",
"#(a)\n",
"p_atm = (P*(10**6))/101.3 ; #[atm]\n",
"print '(a) Pressure in atmospheres is %.2e atm'%p_atm\n",
"\n",
"#(b)\n",
"p_s = (P*(10**6)*14.696)/101.3 ; #[psia]\n",
"print ' (b) Pressure in psia is %.2e psia'%p_s\n",
"\n",
"# (c)\n",
"p_in = (P*(10**6)*29.92)/101.3 ; #[inches of Hg]\n",
"print ' (c) Pressure in inches of Hg is %.2e in. Hg'%p_in\n",
"\n",
"# (d)\n",
"p_mm = (P*(10**6)*760)/101.3 ; #[mm of Hg]\n",
"print ' (d) Pressure in mm of Hg is %.2e mm Hg'%p_mm"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a) Pressure in atmospheres is 5.92e+05 atm\n",
" (b) Pressure in psia is 8.70e+06 psia\n",
" (c) Pressure in inches of Hg is 1.77e+07 in. Hg\n",
" (d) Pressure in mm of Hg is 4.50e+08 mm Hg"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
" Example 5.2 Page no. 110\n"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"# Variable\n",
"b_rd = 28.0 ; #[in. Hg]\n",
"p_rd = 51.0 ; #[psia]\n",
"\n",
"# calculation\n",
"p_atm = b_rd*14.7/29.92 ; # [psia]\n",
"p_tnk = p_atm+p_rd ; #[psia]\n",
"\n",
"# Result\n",
"print ' Pressure in tank in psia is %.1f psia'%p_tnk"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Pressure in tank in psia is 64.8 psia\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
" Example 5.3 Page no. 111\n"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"b_rd = 100.0 ; #[kPa]\n",
"gp = 64.5*101.3/76.0 ; #[kPa]\n",
"\n",
"# Calculations\n",
"p_tnk = b_rd-gp ; #[kPa]\n",
"\n",
"# Results\n",
"print ' Absolute Pressure in tank in is %.1f kPa'%p_tnk\n",
"print ' Since absolute pressure in tank(%.1f kPa) is less than 20 kPa , the \\\n",
" mice probably will not survive. '%p_tnk"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Absolute Pressure in tank in is 14.0 kPa\n",
" Since absolute pressure in tank(14.0 kPa) is less than 20 kPa , the mice probably will not survive. \n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
" Example 5.4 Page no. 115\n"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"# Variables\n",
"df = 1.10*10**3 ; #[kg/m**3]\n",
"d = 1.0*10**3 ; #[kg/m**3]\n",
"g = 9.8 ; #[m/s**2]\n",
"h = 22.0 ; #[mm]\n",
"\n",
"# Calculation\n",
"dP = (df-d)*g*(h*10**(-3)) ; #[Pa]\n",
"\n",
"# Result\n",
"print 'Pressure difference across the orifice plate is %.1f Pa.'%dP"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Pressure difference across the orifice plate is 21.6 Pa.\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
" Example 5.5 Page no. 117\n"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"# Variables\n",
"p_atm=730.0*29.92/760.0 ; #[in. Hg]\n",
"gp= (4.0*29.92)/(2.54*12*33.91) ; #[in. Hg]\n",
"\n",
"# Calculation\n",
"p_air=p_atm-gp ; #[in. Hg]\n",
"\n",
"# Result\n",
"print ' Pressure of the air is %.1f in. Hg.'%p_air"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Pressure of the air is 28.6 in. Hg.\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "code",
"collapsed": true,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
