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{
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 14 : Real Gases Compressiblity"
]
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
" Example 14.1 Page No. 442\n"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Variables\n",
"T1f = 125. ;\t\t\t# Temperature of NH3 -[degree F] \n",
"T1 = 460. +T1f ;\t\t\t# Temperature NH3 -[degree Rankine] \n",
"Pg = 292. ;\t\t\t# Pressure of NH3 -[psig]\n",
"Pa = Pg+14.7 ;\t\t\t#Pressure of NH3 -[psia]\n",
"R = 10.73 ;\t\t\t#Universal gas constant-[(psia*cubic feet)/(lb mol*R)]\n",
"mw_NH3 = 17. ;\t\t# Molecular wt. 1 lb mol NH3-[lb]\n",
"n = 1/17. ;\t\t\t#[mol]\n",
"V_tank = 120. ;\t\t# Volume of tank-[cubic feet]\n",
"\n",
"# Calculations\n",
"V_id = (n*R*T1)/Pa ;\t# Specific volume of NH3 treating it ideal gas-[cubic feet/lb]\n",
"Tc = 729.9 ;\t\t\t#[degree R]\n",
"Pc = 1636. ;\t\t\t#[psia]\n",
"Tr = T1/Tc;\n",
"Pr = Pa/Pc;\n",
"\n",
"z_real = 0.855;\n",
"z_ideal = 1.;\n",
"V_real = V_id*z_real/z_ideal;\t\t\t# Specific volume of NH3 treating it real gas-[cubic feet/lb]\n",
"NH3 = V_tank/V_real ;\t\t\t # Actual amt. of NH3 in tank-[lb]\n",
"\n",
"# Results\n",
"print 'Actual amt. of NH3 in tank is %.0f lb. Therefore , boss is wrong.'%NH3\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Actual amt. of NH3 in tank is 117 lb. Therefore , boss is wrong.\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
" Example 14.2 Page No. 444\n"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"Tc = 154.4 ;\t\t\t#[K]\n",
"Pc1 = 49.7 ;\t\t\t# [atm]\n",
"Pc = 101.3 * Pc1;\t\t#[kPa]\n",
"\n",
"T_O21 = -25 ;\t\t\t# Temperature-[degree C]\n",
"T_O2 = 273+T_O21;\t\t#Temperature -[K]\n",
"R = 8.134 ;\t\t\t # gas constant-[(cubic metre * kPa)/(kg mol * K)]\n",
"V_tank = 0.0284 ;\t\t# Volume of tank-[cubic metre]\n",
"mol_O2 = 32 ;\t\t\t# Kmol. wt. of O2-[kg]\n",
"m_O2 = 3.5 ;\t\t\t# Mass of liquid O2-[kg]\n",
"\n",
"# Calculations\n",
"V_sp = V_tank * mol_O2/m_O2 ;\t\t\t# Specific molar volume-[m**3/kg]\n",
"Vc = R * Tc/Pc ;\t\t\t # [cubic metre/kg mol]\n",
"Vr = V_sp/Vc;\n",
"Tr = T_O2/Tc;\n",
"\n",
"Pr = 1.43 ;\t\t\t# [kPa]\n",
"P_O2 = Pr * Pc ;\t# The pressure in the tank -[kPa]\n",
"\n",
"# Results\n",
"print 'The pressure in the tank is %.2f kPa.'%P_O2\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The pressure in the tank is 7199.49 kPa.\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
" Example 14.3 Page No. 448\n"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Variables\n",
"Tc = 100. ;\t\t\t# Temperature -[degree C] \n",
"T = 273 +Tc ;\t# Temperature -[K] \n",
"P = 90. ;\t\t# Pressure [atm]\n",
"R = 82.06 ;\t\t\t# gas constant-[(cubic centimetre * atm)/(g mol * K)]\n",
"Y_CH4 = 20./100 ;\t\t\t# [mole fraction]\n",
"Y_C2H4 = 30./100 ;\t\t\t# [mole fraction]\n",
"Y_N2 = 50./100 ;\t\t\t#[mole fraction]\n",
"\n",
"#Additional information from appendix D\n",
"Tc_CH4 = 191. ;\t\t\t#[K]\n",
"Pc_CH4 = 45.8 ;\t\t\t# [atm]\n",
"Tc_C2H4 = 283. ;\t\t#[K]\n",
"Pc_C2H4 = 50.5 ;\t\t# [atm]\n",
"Tc_N2 = 126. ;\t\t\t#[K]\n",
"Pc_N2 = 33.5 ;\t\t\t# [atm]\n",
"\n",
"# Calculations & Results\n",
"#(a)-Ideal gas law\n",
"V_sp1 = R * T/P ;\t\t\t# Molar volume-[cubic centimetre/g mol]\n",
" \n",
"print '(a) The volume per mole of mixture by ideal gas law is %.1f cubic centimetre/g mol.'%V_sp1\n",
"\n",
"\t\t\t#(b)\n",
"Pc_mix = Pc_CH4 * Y_CH4+Pc_C2H4 * Y_C2H4+Pc_N2 * Y_N2;\t\t\t# [atm]\n",
"Tc_mix = Tc_CH4 * Y_CH4+Tc_C2H4 * Y_C2H4+Tc_N2 * Y_N2 ;\t\t\t# [K]\n",
"Pr_mix = P/Pc_mix;\n",
"Tr_mix = T/Tc_mix;\n",
"\t\t\t# With 2 parameters(Pr_mix and Tr_mix) , you can find from figure 14.4b that z * Tr_mix = 1.91\n",
"z = 1.91/Tr_mix;\n",
"V_sp2 = z * R * T/P ;\t\t\t# Molar volume-[cubic centimetre/g mol]\n",
"print '(b) The volume per mole of mixture by treating it to be real gas is %.1f cubic centimetre/g mol.'%V_sp2\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a) The volume per mole of mixture by ideal gas law is 340.1 cubic centimetre/g mol.\n",
"(b) The volume per mole of mixture by treating it to be real gas is 324.1 cubic centimetre/g mol.\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "code",
"collapsed": true,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
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