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{
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{
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"source": [
"# Chapter 19 - Psychrometry"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 1: pg 625"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Example 19.1\n",
" (a) The mass of water vapor in the humid air is (kg) = 0.0087\n",
" The specific volume of humid air is (m^3/kg) = 0.811\n",
" (b) The mass of water vapor in the humid air is (kg) = 0.029\n",
" The specific volume of humid air is (m^3/kg) = 0.881\n",
" On the warm day the air contains 2.5 times the mass of water vapor as on the cool day \n",
"\n"
]
}
],
"source": [
"#pg 625\n",
"print('Example 19.1');\n",
"\n",
"# aim : To compare the moisture content and the true specific volumes of atmosphere air \n",
"# (a) temperature is 12 C and the air is saturaded\n",
"# (b) temperature is 31 C and air is .75 saturated\n",
"\n",
"# Given values\n",
"P_atm = 101.4;# atmospheric pressure, [kN/m^2]\n",
"R = .287;# [kJ/kg K]\n",
"\n",
"# solution\n",
"# (a)\n",
"T = 273+12;# air temperature, [K]\n",
"# From steam table at 12 C\n",
"p = 1.4;# [kN/m^2]\n",
"vg = 93.9;# [m^3/kg]\n",
"pa = P_atm-p;# partial pressure of the dry air, [kN/m^2]\n",
"va = R*T/pa;# [m^3/kg]\n",
"\n",
"mw = va/vg;# mass of water vapor in the air,[kg]\n",
"v = va/(1+mw);# specific volume of humid air, [m^3/kg]\n",
"\n",
"print ' (a) The mass of water vapor in the humid air is (kg) = ',round(mw,4)\n",
"print ' The specific volume of humid air is (m^3/kg) = ',round(v,3)\n",
"\n",
"# (b)\n",
"x = .75;# dryness fraction\n",
"T = 273.+31;# air temperature, [K]\n",
"# From steam table\n",
"p = 4.5;# [kN/m^2]\n",
"vg = 31.1;# [m^3/kg]\n",
"pa = P_atm-p;# [kN/m^2]\n",
"va = R*T/pa;# [m^3/kg]\n",
"mw1= va/vg;# mass of water vapor in the air, [kg]\n",
"mw_actual = mw1*x;# actual mass of vapor, [kg]\n",
"v = va/(1+mw_actual);# true specific volume of humid air,[m^3/kg] \n",
"\n",
"print ' (b) The mass of water vapor in the humid air is (kg) = ',round(mw1,4)\n",
"print ' The specific volume of humid air is (m^3/kg) = ',round(v,3)\n",
"\n",
"ewv = mw_actual/mw ;\n",
"print ' On the warm day the air contains ',round(ewv,1),' times the mass of water vapor as on the cool day \\n'\n",
"\n",
"# End\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 2: pg 626"
]
},
{
"cell_type": "code",
"execution_count": 4,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Example 19.2\n",
" (a) The partial pressure of vapor is (kN/m^2) = 1.521\n",
" The partial pressure of dry air is (kN/m^2) = 98.479\n",
" (b) The specific humidity of the mixture is (kg/kg dry air) = 0.0096\n",
" (c) The composition of the mixture is = 0.99\n"
]
}
],
"source": [
"#pg 626\n",
"print('Example 19.2');\n",
"\n",
"# aim : To determine\n",
"# (a) the partial pressures of the vapor and the dry air\n",
"# (b) the specific humidity of the mixture\n",
"# (c) the composition of the mixture\n",
"\n",
"# Given values\n",
"phi = .65;# Relative humidity\n",
"T = 273.+20;# temperature, [K]\n",
"p = 100.;# barometric pressure, [kN/m^2]\n",
"\n",
"# solution\n",
"# (a)\n",
"# From the steam table at 20 C\n",
"pg = 2.34;# [kN/m^2]\n",
"ps = phi*pg;# partial pressure of vapor, [kN/m^2]\n",
"pa = p-ps;# partial pressure of dry air, [kN/m^2]\n",
"print ' (a) The partial pressure of vapor is (kN/m^2) = ',ps\n",
"print ' The partial pressure of dry air is (kN/m^2) = ',pa\n",
"\n",
"# (b)\n",
"# from equation [15]\n",
"omega = .622*ps/(p-ps);# specific humidity of the mixture\n",
"print ' (b) The specific humidity of the mixture is (kg/kg dry air) = ',round(omega,4)\n",
"\n",
"# (c)\n",
"# using eqn [1] from section 19.2\n",
"y = 1/(1+omega);# composition of the mixture\n",
"print ' (c) The composition of the mixture is = ',round(y,2)\n",
"\n",
"# End\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 3: pg 627"
]
},
{
"cell_type": "code",
"execution_count": 5,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Example 19.3\n",
" (a) The specific humidity is (kg/kg air) = 0.0119\n",
" (b) The dew point is (C) = 10.08\n",
" (c) The degree of superheat is (C) = 14.92\n",
" (d) The mass of condensate is (kg/kg dry air) = 0.003\n",
"there is calculation mistake in the book so answer is no matching\n"
]
}
],
"source": [
"#pg 627\n",
"print('Example 19.3');\n",
"\n",
"# aim : To determine\n",
"# (a) the specific humidity\n",
"# (b) the dew point\n",
"# (c) the degree of superheat of the superheated vapor\n",
"# (d) the mass of condensate formed per kg of dry air if the moist air is cooled to 12 C\n",
"\n",
"# Given values\n",
"t = 25.;# C\n",
"T = 273.+25;# moist air temperature, [K]\n",
"phi = .6;# relative humidity\n",
"p = 101.3;# barometric pressure, [kN/m^2]\n",
"R = .287;# [kJ/kg K]\n",
"\n",
"# solution\n",
"# (a)\n",
"# From steam table at 25 C\n",
"pg = 3.17;# [kN/m^2]\n",
"ps = phi*pg;# partial pressure of the vapor, [kN/m^2]\n",
"omega = .622*ps/(p-ps);# the specific humidity of air\n",
"\n",
"print ' (a) The specific humidity is (kg/kg air) = ',round(omega,4)\n",
"\n",
"# (b)\n",
"# Dew point is saturated temperature at ps is,\n",
"t_dew = 16.+2*(1.092-1.817)/(2.062-1.817);# [C]\n",
"print ' (b) The dew point is (C) = ',round(t_dew,2)\n",
"\n",
"# (c)\n",
"Dos = t-t_dew;# degree of superheat, [C]\n",
"print ' (c) The degree of superheat is (C) = ',round(Dos,2)\n",
"\n",
"# (d)\n",
"# at 25 C\n",
"pa = p-ps;# [kN/m^2]\n",
"va = R*T/pa;# [m^3/kg]\n",
"# at 16.69 C\n",
"vg = 73.4-(73.4-65.1)*.69/2;# [m^3/kg]\n",
"ms1= va/vg; \n",
"# at 12 C\n",
"vg = 93.8;# [m^3/kg]\n",
"ms2 = va/vg;\n",
"\n",
"m = ms1-ms2;# mas of condensate\n",
"print ' (d) The mass of condensate is (kg/kg dry air) = ',round(m,4)\n",
"\n",
"print 'there is calculation mistake in the book so answer is no matching'\n",
"\n",
"# End\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 4: pg 630"
]
},
{
"cell_type": "code",
"execution_count": 6,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
" Example 19.4\n",
" (a) The volume of air required is (m^3/h) = 107057.0\n",
" (b) The mass of water added is (kg/h) = 276.7\n",
" (c) The heat transfer required by dry air is (MJ/h) = 458.226\n",
" (d) The heat transferred required for vapor+supply water is (MJ/h) = 721.688\n",
" there is minor variation in the answer reported in the book due to rounding off error\n"
]
}
],
"source": [
"#pg 630\n",
"print(' Example 19.4');\n",
"\n",
"# aim : To determine\n",
"# (a) the volume of external saturated air\n",
"# (b) the mass of air\n",
"# (c) the heat transfer\n",
"# (d) the heat transfer required by the combind water vapour\n",
"\n",
"# given values\n",
"Vb = 56000.;# volume of building, [m^3]\n",
"T2 = 273.+20;# temperature of air in thebuilding, [K]\n",
"phi = .6;# relative humidity\n",
"T1 = 8+273.;# external air saturated temperature, [K]\n",
"p0 = 101.3;# atmospheric pressure, [kN/m^2]\n",
"cp = 2.093;# heat capacity of saturated steam, [kJ/kg K]\n",
"R = .287;# gas constant, [kJ/kg K]\n",
"\n",
"# solution\n",
"# from steam table at 20 C saturation pressure of steam is,\n",
"pg = 2.34;# [kN/m^2]\n",
"\n",
"# (a)\n",
"pvap = phi*pg;# partial pressure of vapor, [kN/m^2] \n",
"P = p0-pvap;# partial pressure of air, [kN/m^2]\n",
"V = 2*Vb;# air required, [m^3]\n",
"# at 8 C saturation pressure ia\n",
"pvap = 1.072;# [kN/m^2]\n",
"P2 = p0-pvap;# partial pressure of entry at 8 C, [kN/m^2]\n",
"\n",
"# using P1*V1/T1=P2*V2/T2;\n",
"V2 = P*V*T1/(T2*P2);# air required at 8 C, [m^3/h]\n",
"print ' (a) The volume of air required is (m^3/h) = ',round(V2)\n",
"\n",
"# (b)\n",
"# assuming\n",
"pg = 1.401;# pressure, [kN/m^2]\n",
"Tg = 273.+12;# [K]\n",
"vg = 93.8;# [m^3/kg]\n",
"# at constant pressure\n",
"v = vg*T2/Tg;# volume[m^3/kg]\n",
"mv = V/v;# mass of vapor in building at 20 C, [kg/h]\n",
"# from steam table at 8 C\n",
"vg2 = 121.;# [m^3/kg]\n",
"mve = V2/vg2;# mass of vapor supplied with saturated entry air, [kg/h]\n",
"mw = mv-mve;# mass of water added, [kg/h]\n",
"print ' (b) The mass of water added is (kg/h) = ',round(mw,1)\n",
"\n",
"# (c)\n",
"# for perfect gas\n",
"m = P2*V2/(R*T1);# [kg/h]\n",
"Cp = .287;# heat capacity, [kJ/kg K]\n",
"Q = m*Cp*(T2-T1);# heat transfer by dry air,[kJ/h]\n",
"print ' (c) The heat transfer required by dry air is (MJ/h) = ',round(Q*10**-3,3)\n",
"\n",
"# (d)\n",
"# from steam table\n",
"h1 = 2516.2;# specific enthalpy of saturated vapor at 8 C,[kJ/kg]\n",
"hs = 2523.6;# specific enthalpy of saturated vapor at 20 C, [kJ/kg]\n",
"h2 = hs+cp*(T2-T1);# specific enthalpy of vapor at 20 c, [kJ/kg]\n",
"Q1 = mve*(h2-h1);# heat transfer required for vapor, [kJ]\n",
"\n",
"# again from steam table\n",
"hf1 = 33.6;# [kJ/kg]\n",
"hg3 = 2538.2;# [kJ/kg]\n",
"Q2 = mw*(hg3-hf1);# heat transfer required for water, [kJ/h]\n",
"Qt = Q1+Q2;# total heat transfer, [kJ/h]\n",
"print ' (d) The heat transferred required for vapor+supply water is (MJ/h) = ',round(Qt*10**-3,3)\n",
"\n",
"print ' there is minor variation in the answer reported in the book due to rounding off error'\n",
"\n",
"# End\n"
]
}
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