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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 2:Current and Voltage Source"
]
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 2.1 Page no.39"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Vs=2 #V open circuit voltage\n",
"Rs=1 #ohm . internal impedence\n",
"#Current Source or Norton's Representaion (Parallel Current Source & Resistor\n",
"Is=Vs/Rs #Ampere, short circuit current\n",
"#result\n",
"print \"The Short Circuit Current Value is \",Is,\"A\"\n",
"print \"The Source Impedence Value is \",Rs,\"ohm\"\n",
"print \"The Current Source & Source Impedance are connected in Parallel.\""
],
"language": "python",
"metadata": {},
"outputs": []
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 2.2 Page no.40"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Is=0.2 #Amperes\n",
"Zs=100 #Ohms\n",
"#Voltage Source or Thevenin's Representaion (Series Voltage Source & Resistor)\n",
"Vs=Is*Zs #Volts\n",
"# Results \n",
"print \"The Open Circuit Voltage is \",Vs,\"V\"\n",
"print \"The Source Impedence Value is \",Zs,\"ohm\"\n",
"print \"The Voltage Source & Source Impedance are connected in Series.\""
],
"language": "python",
"metadata": {},
"outputs": []
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 2.3 Page no.40"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Is=1.5*10**(-3) #Amperes ,source current\n",
"Zs=2000 #Ohms, resistance connected to the loads\n",
"Z1=10000 #Ohms , load resistance 1\n",
"Z2=40000 #Ohms load resistance 2\n",
"#Calculation for Current Source Representation\n",
"Zl=Z1*Z2/(Z1+Z2)\n",
"I2=Is*Zs/(Zs+Zl)\n",
"I4I=I2*Z1/(Z1+Z2) #Using Current Divider Rule\n",
"\n",
"#Calculation for Current Source Representation\n",
"Vs=Is*Zs #Open Circuit Volatge\n",
"I=Vs/(Zs+Zl)\n",
"I4V=I*Z1/(Z1+Z2) #Using Current Divider Rule\n",
"# Results \n",
"print \"The Load Current using Current Source Representaion is I4I = \",I4I,\"A\"\n",
"print \"The Load Current using Voltage Source Representaion is I4V = \",I4V,\"A\"\n",
"print \"I4I==I4V so\"\n",
"print \" Both Results are same.\"\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": []
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 2.4 Page no.45"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" \n",
"Vs=0.01 #V ,dc voltage\n",
"Rs=1000 # ohm, resistance\n",
"#Output Side resistance\n",
"Ro1=20000 #ohm, 20 kOhms\n",
"Ro2=2000 # Ohms\n",
"\n",
"#Calculation\n",
"i=Vs/Rs #Input Current\n",
"Io=100*i #Output Current\n",
"Il=Io*Ro1/(Ro1+Ro2) #Using Current Divider Rule\n",
"Vo=Il*Ro2 #Output Volatge\n",
"\n",
"# Result\n",
"print \"The Output Voltage Vo = \",round(Vo,3),\"V\""
],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
