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{
"metadata": {
"name": "",
"signature": "sha256:1c6a10e6b876d2730bb167805af2fccb3104db62a9988f5aa3ef9c4c86e9b481"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 2: Zeroth Law of Thermodynamics"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1, page no. 46"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" \n",
"#Variable Declaration: \n",
"Tf = 98.6 #Temperature of human body in degree Fahrenheit:\n",
"\n",
"#Calculation:\n",
"Tc = (Tf-32)/1.8 #Temperature of the body in degree Celcius:\n",
"\n",
"#Results:\n",
"print \"Temperature of the human body \",Tc,\"\u00b0C\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Temperature of the human body 37.0 \u00b0C\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2, page no. 47"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" \n",
"import math as m\n",
"import numpy as n\n",
"\n",
"#Variable Declaration: \n",
"p0 = 3.0 #Thermodynamic property at T = 0:\n",
"p100 = 8.0 #Thermodynamic property at T = 100:\n",
"p = 6.5 #Thermodynamic property at which t is to be found\n",
"\n",
"#Calculation:\n",
"#Solving two linear equation by linear Algebra using matrices AX = B\n",
"A = n.matrix([[m.log(p0),0.5],[m.log(p100),0.5]])\n",
"B = n.matrix([[0],[100]])\n",
"X = n.matrix.getI(A)*B\n",
"a = round(X[0],2) #Thermodynamic constant a from matrix solution\n",
"b = round(X[1]) #Thermodynamic constant b from matrix solution\n",
"t = a*m.log(p)-b/2 #At thermodynamic property p = 6.5:\n",
"\n",
"#Results:\n",
"print \"Temperature at the value of thermodynamic property (p = 6.5)\" ,round(t,2),\"\u00b0C\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Temperature at the value of thermodynamic property (p = 6.5) 302.83 \u00b0C\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3, page no. 47"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" \n",
"#Variable Declaration:\n",
"T0 = 0 #Ice point (\u00b0C)\n",
"T100 = 100 #Steam Poiont (\u00b0C)\n",
"def E(t): #Function definition for above expression of EMF\n",
" return 0.003*t - 5*10**-7*t**2 + 0.5 *10**-3\n",
"\n",
"#Calculation:\n",
"t = (E(30)-E(0))/(E(100)-E(0))*(T100-T0) #Temperature shown by the thermometer at T = 30:\n",
"\n",
"#Results:\n",
"print \"!--Please check that there are calculation mistake done in the book \\nhence there is heavy difference in answer of book and the code--!\\n\"\n",
"print \"The temperature shown by thermometer: \",round(t,2),\"\u00b0C\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"!--Please check that there are calculation mistake done in the book \n",
"hence there is heavy difference in answer of book and the code--!\n",
"\n",
"The temperature shown by thermometer: 30.36 \u00b0C\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 4, page no. 48"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" \n",
"#Variable Declaration: \n",
"t1 = 50 #Temperature of gas using gas thermometer:\n",
"def E(t): #Function Definition as per question:\n",
" return 0.18*t - 5.2*10**-4*t**2\n",
" \n",
"#Calculation:\n",
"t = (100-0)*E(t1)/(E(100)-E(0))\t#Temperature at EMF = E50:\n",
"p = (t-t1)/t1*100\n",
"\n",
"#Results:\n",
"print \"Percentage variation: \",round(p,2),\"%\"\n",
" "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Percentage variation: 20.31 %\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5, page no. 48"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" \n",
"import numpy as n\n",
"\n",
"#Variable Declaration: \n",
"#Solving the conversion relation X = aC + b using matrices and finding a and b\n",
"B = n.matrix([[0],[1000]])\n",
"A = n.matrix([[0,1],[100,1]])\n",
"\n",
"#Calculations:\n",
"X = n.matrix.getI(A)*B\n",
"a = round(X[0]) #Value of a of equation X = aC + B\n",
"b = round(X[1]) #Value of b of equation X = aC + B\n",
"X = a*-273.15+b #Absolute temperature in new temperature scale:\n",
"\n",
"#Results:\n",
"print \"Absolute temperature in new scale: \",X,\"\u00b0X\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Absolute temperature in new scale: -2731.5 \u00b0X\n"
]
}
],
"prompt_number": 5
}
],
"metadata": {}
}
]
}
|
