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{
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"name": "",
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter-8 Non-Linear Circuits"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8.2 - Page 258"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from numpy import pi\n",
"# Given data \n",
"R1= 5 # in k\u03a9\n",
"R2= 10.0 # in k\u03a9\n",
"V_peak= R1*R2/(R1+R2) # in V\n",
"Vav= V_peak/pi # in V\n",
"print \"Peak value of V1 = %0.2f V\" %V_peak\n",
"print \"Average value of Vo = %0.2f V\" %Vav"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Peak value of V1 = 3.33 V\n",
"Average value of Vo = 1.06 V\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8.7 - Page 268"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"from __future__ import division\n",
"from math import exp\n",
"# Given data \n",
"t= 0 \n",
"Vc= 0 # in volts\n",
"Vo= 5 # in volts\n",
"R= 10 # in 2 \u03a9 (assume)\n",
"RC= 1 # (assume)\n",
"R3= 2*R # in \u03a9\n",
"R2= 3*R # in \u03a9\n",
"# From equation : T= 2*Rf*C*log[1+2*R3/R2]\n",
"T= 2*RC*math.log(1+2*R3/R2) \n",
"Vc_t= 2 # in volts\n",
"t= T/2 \n",
"#Voltage across capacitor,\n",
"# Vc_t= Vco*[1-%e**(-t/ReqC)]= 1/5*(VR+4*Vo)*[1-%e**(-t/4*RC/5)]\n",
"VR= Vc_t*5/(1-exp((-t/(4*RC/5))))-4*Vo \n",
"print \"The value of VR = %0.2f volts\" %VR"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of VR = -4.69 volts\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8.9 - Page 270"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from __future__ import division\n",
"# Given data\n",
"# Part (c)\n",
"R1= 150 # in \u03a9\n",
"R2= 68*10**3 # in \u03a9\n",
"Vin= 50*10**-3 # in V\n",
"Vsat= 14 # in V\n",
"Vpositive= Vsat*(R1/(R1+R2)) # in V\n",
"V_UT= Vpositive # in V\n",
"Vpositive= -Vsat*(R1/(R1+R2)) # in V\n",
"V_LT= Vpositive # in V\n",
"print \"The value of V_UT = %0.4f V\" %V_UT\n",
"print \"The value of V_LT = %0.4f V\" %V_LT"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of V_UT = 0.0308 V\n",
"The value of V_LT = -0.0308 V\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8.10 - Page 271"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Given data \n",
"V_UT= 5 # in V\n",
"V_LT= -5 # in V\n",
"# Hysteresis voltage,\n",
"Vhy= V_UT-V_LT # in V\n",
"print \"The hysteresis voltage = %0.f V\" %Vhy"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The hysteresis voltage = 10 V\n"
]
}
],
"prompt_number": 4
}
],
"metadata": {}
}
]
}
|
